Pearson eText for Modern Database Management -- Instant Access (Pearson+)
13th Edition
ISBN: 9780137305940
Author: Jeffrey Hoffer, Ramesh Venkataraman
Publisher: PEARSON+
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Chapter 8, Problem 8.36RQ
Program Plan Intro
Four DBMS facilities that are required for
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#include
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1. [20 pts] What is the output of the program? Please explain why.
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Please run and debug the following program and answer the questions.
(OnlineGDB)
#include <stdio.h>int main(void) {int a;char *s;int v0 = 4, v1 = 5, v2 = 6, v3 = 1, v4 = 2;printf("Exercise 1:\n====================\n");switch(v0) {case 0: printf("Hello October\n"); break;case 1: printf("Go Kean!\n"); break;case 2: printf("Academic Building Center \n"); break;case 3: printf("UNION \n"); break;case 4: printf("Go ");case 5: printf("Kean! \n");default: printf("Have a great semester! \n"); break;}for(a=5; a<v1; a++) {printf("Kean");}printf("\n");if (v2 == 6) {s = "Go";}else {s = "Hello";}if(v3 != v4) {printf("%s Kean!\n",s);} else {printf("%s Computer Science!\n",s);}return 0;}
Assume the following codes are added between line 36 (}) and line 38 (return 0;) v0>0 ? ++v1, ++v2 : --v3; Please give the values of v0, v1, v2, v3, and v4 after this line and explain the reason. You can test the program to verify your answer if you like.
Chapter 8 Solutions
Pearson eText for Modern Database Management -- Instant Access (Pearson+)
Ch. 8 - Prob. 8.1RQCh. 8 - Prob. 8.2RQCh. 8 - Prob. 8.3RQCh. 8 - Prob. 8.4RQCh. 8 - Prob. 8.5RQCh. 8 - Prob. 8.6RQCh. 8 - Prob. 8.7RQCh. 8 - Prob. 8.8RQCh. 8 - Explain why you sometimes have to reserve much...Ch. 8 - Why are field values sometimes coded?
Ch. 8 - Prob. 8.11RQCh. 8 - Prob. 8.12RQCh. 8 - Explain why normalized relations may not comprise...Ch. 8 - Prob. 8.14RQCh. 8 - List three common situations that suggest that...Ch. 8 - Explain the reasons why some experts are against...Ch. 8 - Prob. 8.17RQCh. 8 - Prob. 8.18RQCh. 8 - Prob. 8.19RQCh. 8 - Prob. 8.20RQCh. 8 - Prob. 8.21RQCh. 8 - Prob. 8.22RQCh. 8 - One of the strongest recommendations regarding...Ch. 8 - Explain why an index is useful only if there is...Ch. 8 - Indexing can clearly be very beneficial. Why...Ch. 8 - Prob. 8.26RQCh. 8 - Prob. 8.27RQCh. 8 - Describe the role of data dictionary in the...Ch. 8 - Prob. 8.29RQCh. 8 - Prob. 8.30RQCh. 8 - Explain how creating a view may increase data...Ch. 8 - Prob. 8.32RQCh. 8 - Prob. 8.33RQCh. 8 - Prob. 8.34RQCh. 8 - Prob. 8.35RQCh. 8 - Prob. 8.36RQCh. 8 - Prob. 8.37RQCh. 8 - Prob. 8.38RQCh. 8 - Prob. 8.39RQCh. 8 - How can views be used as part of data security?...Ch. 8 - Prob. 8.41RQCh. 8 - Prob. 8.42RQCh. 8 - Consider the following two relations for...Ch. 8 - Prob. 8.44PAECh. 8 - Prob. 8.45PAECh. 8 - Prob. 8.46PAECh. 8 - Prob. 8.47PAECh. 8 - Suppose you are designing a default value for the...Ch. 8 - When a student has not chosen a major at a...Ch. 8 - Prob. 8.50PAECh. 8 - Prob. 8.51PAECh. 8 - Consider the relations in Problem and Exercise...Ch. 8 - Prob. 8.53PAECh. 8 - Prob. 8.54PAECh. 8 - Prob. 8.55PAECh. 8 - Prob. 8.56PAECh. 8 - Prob. 8.57PAECh. 8 - Consider the relations specified in Problem and...Ch. 8 - Prob. 8.59PAECh. 8 - Prob. 8.60PAECh. 8 - Prob. 8.61PAECh. 8 - Prob. 8.62PAECh. 8 - Prob. 8.63PAECh. 8 - Prob. 8.64PAECh. 8 - Problems and Exercises 8-65 through 8-68 refer to...Ch. 8 - Prob. 8.66PAECh. 8 - Problems and Exercises 8-65i5 through 8-68 refer...Ch. 8 - Refer to Figure 4-5 0. For each of the following...Ch. 8 - Prob. 8.69PAECh. 8 - Prob. 8.70PAECh. 8 - Prob. 8.71PAECh. 8 - Prob. 8.72PAECh. 8 - Prob. 8.73PAECh. 8 - Prob. 8.74PAECh. 8 - Prob. 8.75PAECh. 8 - Prob. 8.76PAECh. 8 - Prob. 8.77PAE
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- #include <stdio.h>int main(void) {int a;char *s;int v0 = 4, v1 = 5, v2 = 6, v3 = 1, v4 = 2;printf("Exercise 1:\n====================\n");switch(v0) {case 0: printf("Hello October\n"); break;case 1: printf("Go Kean!\n"); break;case 2: printf("Academic Building Center \n"); break;case 3: printf("UNION \n"); break;case 4: printf("Go ");case 5: printf("Kean! \n");default: printf("Have a great semester! \n"); break;}for(a=5; a<v1; a++) {printf("Kean");}printf("\n");if (v2 == 6) {s = "Go";}else {s = "Hello";}if(v3 != v4) {printf("%s Kean!\n",s);} else {printf("%s Computer Science!\n",s);}return 0;} Output: Exercise 1:====================Go Kean! Have a great semester! Go Kean! Please only modify the initial value of v0, v1, v2, v3 and v4 to get the following output. Youneed to show your program output (in the screenshot) and submit the code that youmodified.Exercise 1:====================Hello OctoberKeanHello Computer Science!arrow_forward(OnlineGDB) 1. Please read and run the following code and answer the questions.#include <stdio.h>int main(void) {int a;char *s;int v0 = 4, v1 = 5, v2 = 6, v3 = 1, v4 = 2;printf("Exercise 1:\n====================\n");switch(v0) {case 0: printf("Hello October\n"); break;case 1: printf("Go Kean!\n"); break;case 2: printf("Academic Building Center \n"); break;case 3: printf("UNION \n"); break;case 4: printf("Go ");case 5: printf("Kean! \n");default: printf("Have a great semester! \n"); break;}for(a=5; a<v1; a++) {printf("Kean");}printf("\n");if (v2 == 6) {s = "Go";}else {s = "Hello";}if(v3 != v4) {printf("%s Kean!\n",s);} else {printf("%s Computer Science!\n",s);}return 0;} What is the output of the program? Please explain why.arrow_forward1.[30 pts] Answer the following questions: a. [10 pts] Write a Boolean equation in sum-of-products canonical form for the truth table shown below: A B C Y 0 0 0 1 0 0 1 0 0 1 0 0 0 1 1 0 1 0 0 1 1 0 1 0 1 1 0 1 1 1 1 0 a. [10 pts] Minimize the Boolean equation you obtained in (a). b. [10 pts] Implement, using Logisim, the simplified logic circuit. Include an image of the circuitarrow_forward
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