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Answer to Problem 73QAP
Explanation of Solution
Given:
Initial
Final angular velocity of roulette wheel
Time
Formula used:
Equation for constant angular acceleration,
(
Calculation:
Consider the rotational motion of roulette wheel,
Applying the
Let's substitute the values,
Conclusion:
Average angular acceleration of the merry-go-round.
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Answer to Problem 73QAP
Angular displacement
Explanation of Solution
Given:
Initial angular velocity of roulette wheel
Final angular velocity of roulette wheel
Time
Angular acceleration of roulette wheel
Formula used:
Equation for constant angular acceleration,
(
Calculation:
Consider the rotational motion of roulette wheel,
Applying the
Let's substitute the values,
It means merry-go-round goes 1 round and 27 radians in distance.
Accordingly, angular displacement is
Conclusion:
Angular displacement of the merry-go-round during this time interval.
Maximum tangential speed of the child if she rides on the edge of platform
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Answer to Problem 73QAP
Maximum tangential speed =
Explanation of Solution
Given:
Initial angular velocity of roulette wheel
Final angular velocity of roulette wheel
Time
Angular acceleration of roulette wheel
Radius of the merry-go-round =
Formula used:
Equation for maximum tangential speed of an object if it on the edge of disk platform,
(
Calculation:
Consider the rotational motion of child,
Applying the
Let's substitute the values,
Conclusion:
Maximum tangential speed of the child if she rides on the edge of platform
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COLLEGE PHYSICS
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