Concept explainers
(a)
Interpretation:
If the 4-methylphenol will dissolve easily in aqueous NaOH solution than the pure water should be determined.
Concept Introduction:
The acid is a substance that gives
(b)
Interpretation:
If the 4-methylphenol will dissolve easily in aqueous NaHCO3 solution than the pure water should be determined.
Concept Introduction:
The acid is a substance that gives
(c)
Interpretation:
If the 4-methylphenol will dissolve easily in aqueous NH3 solution than the pure water should be determined.
Concept Introduction:
The acid is a substance that gives
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Introduction to General, Organic and Biochemistry
- The disinfectant phenol, C₆H₅OH, has a pKₐ of 10.0 in wa-ter, but 14.4 in methanol. (a) Why are the values different? (b) Is methanol is a stronger or weaker base than water? (c) Write the dissociation reaction of phenol in methanol. (d) Write an expres-sion for the autoionization constant of methanol.arrow_forwardCalculate the equilibrium constant for the acid–base reaction between the reactants in each of the following pairs: (a) HCl + H2O (b) CH3COOH + H2O (c) CH3NH2 + H2O (d) CH3N+H3 + H2Oarrow_forwarddentify the acid-base conjugate pairs in each of the following reactions: (a) CH3COO HCN CH3COOH CN (b) HCO HCO H2CO3 CO (c) H2PO NH3 HPO NH (d) HClO CH3NH2 CH3NH ClO (e) CO H2O HCO OHarrow_forward
- Ammonia can react as an acid or a base. a) What is the conjugate acid of ammonia? b) What is the conjugate base of ammonia? c) arist dit ons servbed as Complete the following acid-base reaction in which NH3(e) acts as both an acid and a base: OcH 6 HOONH3() + NH3() = OOH (d FOZH (s *АНИ (1 sqz ions to biosqu adtaviðarrow_forwardPhenol, C6H5OH, has a Ka = 1.3x 10 -10 (a) Write out the Ka reaction for phenol (b) Calculate Kb for phenols conjugate base (c) Is phenol a stronger or weaker acid than water?arrow_forwardConsider two acids: HCO2H (formic acid, pKa = 3.8) and pivalic acid [(CH3)3CCO,H, pK = 5.0]. (a) Which acid has the larger K? (b) Which acid is the stronger acid? (c) Which acid forms the stronger conjugate base? (d) When each acid is dissolved in water, for which acid does the equilibrium lie further to the right? %3D The pKa values in Table 2.1 span a large range (-7 to 50). The pK, scale is logarithmic. small difference in pK, translates into a large numerical difference, For example, the diffe between the pK, of NH3 (38) and CH2=CH, (44) is six pKa units. This means that NH, is one million times more acidic than CH,=CH,.arrow_forward
- Calculate the pOH of a solution of methylamine and lye. Initially, [CH3NH2] = 1M and [NaOH] = 0.02M. CH3NH2(aq) + H2O(l) ↔ CH3NH3+(aq) + OH-(aq) Kb = 4.38x10-4 NaOH(aq) → Na+(aq) + OH-(aq) Strong base a. 1.70 b. 1.39 c. 1.68 d. 4.12 e. 2.33arrow_forwardCalculate the pH and the pOH of these solutions: (c) 0.957 M HC2H3O2 (Ka = 1.8 x 10-5) pH = pOH =arrow_forwardConsider the dissociation of hydrocyanic acid in aqueous solution HCN - CN + H* for which K, is 4.9 x 101°. (i) Find the pH of a solution initially 102 M in HCN, and the degree of dissociation of the HCN, a. (ii) To this solution is added more CN' until [CN'] = (0.1 M. What is the new pH of the solution? (ii) Without making a new numerical cakculation, explain qualitatively how the degree of dissociation would change if the solution is diluted.arrow_forward
- Pyridinium bromide (C5H5NHBr) is a strong electrolyte thatdissociates completely into C5H5NH+ and Br-. An aqueoussolution of pyridinium bromide has a pH of 2.95.(a) Write out the reaction that leads to this acidic pH.(b) Calculate the Ka for pyridiniumbromide.(c) A solution of pyridinium bromide has a pH of 2.95.What is the concentration of the pyridinium cation atequilibrium, in units of molarity?arrow_forwardWrite equilibrium-constant expressions for each of the following: A) the base dissociation of ethyl-amine, CH3CH2NH2. B) the acid dissociation of hydrogen cyanide, HCN. C) the dissociation of H3AsO4 to H3O^+ and AsO4^3-. D) the reaction of CO3^2- with H2O to give H2CO3 and OH^-.arrow_forwardDoes the equilibrium lie to the left or to the right in the following reaction: H3CO: + H-Br: 2 H;CO-H + H,CO-H + Br:arrow_forward
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