(a)
Interpretation:
The most stable E1 product for each of the given reactions is needed to be drawn.
Concept introduction:
In an elimination reaction,
E1 reaction is a unimolecular elimination reaction in which carbocation is formed as an intermediate and it has stepwise mechanism.
The product of the E1 elimination reaction is depends upon the two β-positions of alkyl halide. If the β-positions are identical and the products formed are also identical. If the β-positions are different and the products formed are also different. This means the double bond can form in two different regions so this type of reaction is called regioselective.
The bulkiness of the base controls the regioselectivity in an elimination reaction. The sterically hindered bases form less substituted alkene and non-sterically hindered bases form more substituted alkenes.
To draw: the major E1 product for the given reactions.
(b)
Interpretation:
The most stable E1 product for each of the given reactions is needed to be drawn.
Concept introduction:
In an elimination reaction, alkenes are formed when alkyl halides are treated with bases via eliminating one proton and one halo group of the alkyl halide.
E1 reaction is a unimolecular elimination reaction in which carbocation is formed as an intermediate and it has stepwise mechanism.
The product of the E1 elimination reaction is depends upon the two β-positions of alkyl halide. If the β-positions are identical and the products formed are also identical. If the β-positions are different and the products formed are also different. This means the double bond can form in two different regions so this type of reaction is called regioselective.
The bulkiness of the base controls the regioselectivity in an elimination reaction. The sterically hindered bases form less substituted alkene and non-sterically hindered bases form more substituted alkenes.
To draw: the major E1 product for the given reactions.
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Chapter 8 Solutions
ORGANIC CHEMISTRY GGC>CUSTOM<-TEXT
- true or false The equilibrium constant for this reaction is 0.20. N2O4(g) ⇔ 2NO2(g) Based on the above, the equilibrium constant for the following reaction is 5. 4NO2(g) ⇔ 2N2O4(g)arrow_forwardtrue or false The equilibrium constant for this reaction is 0.20. N2O4(g) ⇔ 2NO2(g) Based on the above, the equilibrium constant for the following reaction is 0.4. 2N2O4(g) ⇔ 4NO2(g)arrow_forwardtrue or false Using the following equilibrium, if heat is added the equilibrium will shift toward the reactants. N2(g) + 3H2(g) ⇔ 2NH3(g) + heatarrow_forward
- True or False Using the following equilibrium, if heat is added the equilibrium will shift toward the products. N2O4(g) + heat ⇔ 2NO2(g)arrow_forwardtrue or false Using the following equilibrium, if solid carbon is added the equilibrium will shift toward the products. C(s) + CO2(g) ⇔ 2CO(g)arrow_forwardProvide the complete mechanism for the reaction below. You must include appropriate arrows,intermediates, and formal charges. Please also provide a reason to explain why the 1,4-adduct is preferred over the 1,3-adduct.arrow_forward
- Which of the following pairs are resonance structures of one another? I. III. || III IV + II. :0: n P !༠ IV. EN: Narrow_forwardPredict the major organic product(s) and byproducts (either organic or inorganic) for thefollowing reactions.arrow_forwardA 8.25 g sample of aluminum at 55°C released 2500 J of heat. The specific heat of aluminum is 0.900 J/g°C. The density of aluminum is 2.70 g/mL. Calculate the final temperature of the aluminum sample in °C.arrow_forward
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