(a)
Interpretation:
Bond-line structure of the molecules should be drawn for the given IUPAC names.
Concept introduction:
Any organic molecule can be named by using certain rules given by IUPAC (International Union for Pure and applied chemistry). IUPAC name consists of three parts in major namely Prefix suffix and root word.
Prefix represents the substituent present in the molecule and its position in the parent chain.
Suffix denotes the presence of
Root word represents the longest continuous carbon skeleton of the organic molecule.
The structure of a molecule can be drawn by analyzing the presence of prefix, suffix and root word in the given IUPAC name.
In bond-line structure the carbon atoms and the hydrogen atoms which are attached to that carbon atom are not to show, they are drawn as line segments. For acyclic carbon chains it draws as in a zig-zag fashion and for cyclic chains of carbon it draws as a cyclic polygon. For representing a heteroatom attached to the carbon, use a labelled line segment.
(b)
Interpretation:
Bond-line structure of the molecules should be drawn for the given IUPAC names.
Concept introduction:
Any organic molecule can be named by using certain rules given by IUPAC (International Union for Pure and applied chemistry). IUPAC name consists of three parts in major namely Prefix suffix and root word.
Prefix represents the substituent present in the molecule and its position in the parent chain.
Suffix denotes the presence of functional group if any in the molecule. It can be an alkene, alkyne, alcohol, carboxylic acid, alcohol etc. The position of this fictional group is represented just before the root name.
Root word represents the longest continuous carbon skeleton of the organic molecule.
The structure of a molecule can be drawn by analyzing the presence of prefix, suffix and root word in the given IUPAC name.
In bond-line structure the carbon atoms and the hydrogen atoms which are attached to that carbon atom are not to show, they are drawn as line segments. For acyclic carbon chains it draws as in a zig-zag fashion and for cyclic chains of carbon it draws as a cyclic polygon. For representing a heteroatom attached to the carbon, use a labelled line segment.
(c)
Interpretation:
Bond-line structure of the molecules should be drawn for the given IUPAC names.
Concept introduction:
Any organic molecule can be named by using certain rules given by IUPAC (International Union for Pure and applied chemistry). IUPAC name consists of three parts in major namely Prefix suffix and root word.
Prefix represents the substituent present in the molecule and its position in the parent chain.
Suffix denotes the presence of functional group if any in the molecule. It can be an alkene, alkyne, alcohol, carboxylic acid, alcohol etc. The position of this fictional group is represented just before the root name.
Root word represents the longest continuous carbon skeleton of the organic molecule.
The structure of a molecule can be drawn by analyzing the presence of prefix, suffix and root word in the given IUPAC name.
In bond-line structure the carbon atoms and the hydrogen atoms which are attached to that carbon atom are not to show, they are drawn as line segments. For acyclic carbon chains it draws as in a zig-zag fashion and for cyclic chains of carbon it draws as a cyclic polygon. For representing a heteroatom attached to the carbon, use a labelled line segment.
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Chapter 8 Solutions
ORGANIC CHEMISTRY GGC>CUSTOM<-TEXT
- OA. For the structure shown, rank the bond lengths (labeled a, b and c) from shortest to longest. Place your answer in the box. Only the answer in the box will be graded. (2 points) H -CH3 THe b Нarrow_forwardDon't used hand raitingarrow_forwardQuizzes - Gen Organic & Biological Che... ☆ myd21.lcc.edu + O G screenshot on mac - Google Search savings hulu youtube google disney+ HBO zlib Homework Hel...s | bartleby cell bio book Yuzu Reader: Chemistry G periodic table - Google Search b Home | bartleby 0:33:26 remaining CHEM 120 Chapter 5_Quiz 3 Page 1: 1 > 2 > 3 > 6 ¦ 5 > 4 > 7 ¦ 1 1 10 8 ¦ 9 a ¦ -- Quiz Information silicon-27 A doctor gives a patient 0.01 mC i of beta radiation. How many beta particles would the patient receive in I minute? (1 Ci = 3.7 x 10 10 d/s) Question 5 (1 point) Saved Listen 2.22 x 107 222 x 108 3.7 x 108 2.22 x 108 none of the above Question 6 (1 point) Listen The recommended dosage of 1-131 for a test is 4.2 μCi per kg of body mass. How many millicuries should be given to a 55 kg patient? (1 mCi = 1000 μСi)? 230 mCiarrow_forward
- Q4: Rank the relative nucleophilicity of halide ions in water solution and DMF solution, respectively. F CI Br | Q5: Determine which of the substrates will and will not react with NaSCH3 in an SN2 reaction to have a reasonable yield of product. NH2 Br Br Br .OH Brarrow_forwardClassify each molecule as optically active or inactive. Determine the configuration at each H соон Chirality center OH 애 He OH H3C Ноос H H COOH A K B.arrow_forwardQ1: Rank the relative nucleophilicity of the following species in ethanol. CH3O¯, CH3OH, CH3COO, CH3COOH, CH3S Q2: Group these solvents into either protic solvents or aprotic solvents. Acetonitrile (CH3CN), H₂O, Acetic acid (CH3COOH), Acetone (CH3COCH3), CH3CH2OH, DMSO (CH3SOCH3), DMF (HCON(CH3)2), CH3OHarrow_forward
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- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY
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