Biochemistry (Looseleaf)
Biochemistry (Looseleaf)
9th Edition
ISBN: 9781319114800
Author: BERG
Publisher: MAC HIGHER
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Chapter 8, Problem 46P
Interpretation Introduction

(a)

Interpretation:

V0 versus pH curve when the substrate concentration is much greater than the enzyme KM should be drawn.

Concept introduction:

KM is the Michaelis constant which is the substrate concentration when the reaction rate is half of the maximum rate achieved by a system. Michaelis constant is a measure of its binding affinity to a substrate. The higher the Michaelis constant, the lower affinity for its substrate. That means an enzyme with lower KM needs a higher concentration of substrate to achieve Vmax.

Interpretation Introduction

(b)

Interpretation:

V0 versus pH curve when the substrate concentration is much less than the enzyme KM should be drawn.

Concept introduction:

KM is the Michaelis constant which is the substrate concentration when the reaction rate is half of the maximum rate achieved by a system. Michaelis constant is a measure of its binding affinity to a substrate. The higher the Michaelis constant, lower affinity for its substrate. That means an enzyme with lower KM needs a higher concentration of substrate to achieve Vmax.

Interpretation Introduction

(c)

Interpretation:

The pH at which the velocity will equal half of the maximal velocity attainable under these conditions should be determined.

Concept introduction:

KM is the Michaelis constant which is the substrate concentration when the reaction rate is half of the maximum rate achieved by a system. Michaelis constant is a measure of its binding affinity to a substrate. The higher the Michaelis constant, lower affinity for its substrate. That means for an enzyme with lower KM needs a higher concentration of substrate to achieve Vmax.

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Students have asked these similar questions
The beta-lactamase hydrolyzes the lactam-ring in penicillin. Describe the mechanism  of hydrolysis, insuring to include the involvement of S, D, & K in the reaction sequence. Please help
To map the active site of beta-lactamase, the enzyme was hydrolyzed with trypsin to yield a hexapeptide (P1) with the following amino acids. Glu, Lys, Leu, Phe, Met, and Ser. Treatment of P1 with phenyl isothiocyanate yielded a PTH derivative of phenylalanine and a peptide (P2). Treatment of P1 with cyanogenbromide gave an acidic tetrapeptide (P3) and a dipeptide (P4).Treatment of P2 with 1-fluoro-2,4-dinitrobenzene, followed by complete hydrolysis, yields N-2,4-dinitrophenyl-Glu. P1, P2, and P3 contain the active site serine. Why doesn't D in this hexapeptide not participate in the hydrolysis of the beta-lactam ring even though S, K, and D are involved in the catalyst?
To map the active site of -lactamase, the enzyme was hydrolyzed with trypsin to yield a hexapeptide (P1) with the following amino acids. Glu, Lys, Leu, Phe, Met, and Ser. Treatment of P1 with phenyl isothiocyanate yielded a PTH derivative of phenylalanine and a peptide (P2). Treatment of P1 with cyanogenbromide gave an acidic tetrapeptide (P3) and a dipeptide (P4).Treatment of P2 with 1-fluoro-2,4-dinitrobenzene, followed by complete hydrolysis, yields N-2,4-dinitrophenyl-Glu. P1, P2, and P3 contain the active site serine.  Using the experimental results described above derive the primary sequence of the active site hexapeptide. Please help!
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