Review. As shown in Figure P8.26, a light string that does not stretch changes from horizontal to vertical as it passes over the edge of a table. The string connects m1, a 3.50-kg block originally at rest on the horizontal table at a height h = 1.20 m above the floor, to m2, a hanging 1.90-kg block originally a distance d = 0.900 m above the floor. Neither the surface of the table nor its edge exerts a
Figure P8.26
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Chapter 8 Solutions
Physics for Scientists and Engineers with Modern, Revised Hybrid (with Enhanced WebAssign Printed Access Card for Physics, Multi-Term Courses)
- A chandelier of mass 18kg hangs from a cable that is attached to a ceiling. The chandelier is at rest and initially the cable hangs vertically.Alice climbs up the stairs to a height level that is close to the chandelier's height. She then pulls the chandelier to one side using a hook, to bring the chandelier closer to her so she can replace a light bulb. The force that Alice exerts on the chandelier is in the horizontal direction and has magnitude 42 N.arrow_forwardA horizontal meter stick has a mass of 235 g.235 g. Three weights ride on the meter stick: 265 g265 g at 41.7 cm,41.7 cm, 183 g183 g at 82.7 cm,82.7 cm, and 205 g205 g at 98.3 cm.98.3 cm. At what location on the meter stick would the system be in balance if it were suspended there?arrow_forwardYou have been hired as an expert witness in the case of a factory owner suing a demolition company. The particular case involves a smokestack at a factory being demolished. In order to save money, the factory owner wanted to move the smokestack to a nearby factory that was being built. The demolition company guaranteed to deliver the undamaged smokestack to the new factory by toppling the smokestack freely onto a huge cushioned platform lying on the ground. The then-horizontal smokestack would have been loaded onto a long truck rig for transport to the new factory. However, as the smokestack toppled, it broke apart at a point along its length. The factory owner is blaming the demolition company for the destruction of his smokestack. The demolition company is claiming that there was a defect in the smokestack and that is the reason for its destruction. What advice do you give the attorney who is handling the case on the side of the factory owner?arrow_forward
- You are working in an ice skating rink and have been asked to hang a new banner on the wall. Your friend is helping you so that the ladder does not collapse by exerting a force FAL at an angle ϕ relative to the horizontal. The ladder has a length L and makes an angle of θ with respect to the vertical wall. You have a mass, mY, and are a horizontal distance x from the wall. The ladder has a mass of mL. Because the wall is slick, and the ice on the floor is slick, the frictional forces acting on the ladder are negligible. Find a formula for the magnitude of the force that your friend must exert to keep the ladder from falling, in terms of the following variables: x,L,mY,mL,θ,ϕ. Then use the following values to get a number for the magnitude of FAL θ = 34.4 degreesϕ = 26.144 degreesx = 1.612 metersL = 6.2 metersmY = 98.0 kgmL = 32.34 kgarrow_forwardAfrican elephants are the largest land animals. They consume approximately 10% of their body weight in food each day, which for an adult male, can be 1000 lb. of vegetation! Their diet consists mostly of grasses, bamboo, tree bark, and fruit. They also like to dine on tree leaves. To reach them, they often stand up on their hind legs and extend their trunks (see the figure). The elephant in the figure is in equilibrium. The location of the elephant's center of mass is shown, and the axis of rotation has been chosen to correspond to the hip joint. The forces in the elephant's free-body diagram are shown, and there is a static friction force between the elephant's back feet and the ground. Use the following information and calculate the magnitude of the tension in the elephant's trunk T (m = 4540 kg, FN = rfs = 133 cm, rcg = 76.0 cm, r = 229 cm). Number +x Axis of rotation Units 60 165 30 W TTFN cg 10° Michael Poliza/Caters News Agencyarrow_forwardA 10.0-kg monkey climbs auniform ladder with weight w =1.20 x 102 N and length L =3.00 mas shown in Figure P8.94. The ladderrests against the wall at an angleof θ = 60.0°. The upper and lowerends of the ladder rest on frictionlesssurfaces, with the lower endfastened to the wall by a horizontalrope that is frayed and that can support a maximum tension of only 80.0 N. (a) Draw aforce diagram for the ladder. (b) Find the normal forceexerted by the bottom of the ladder. (c) Find the tensionin the rope when the monkey is two-thirds of the way up theladder. (d) Find the maximum distance d that the monkeycan climb up the ladder before the rope breaks. (e) If thehorizontal surface were rough and the rope were removed,how would your analysis of the problem be changed andwhat other information would you need to answer parts (c)and (d)?arrow_forward
- An airplane of mass 3.60 × 105 kg experienced a problem with all its tires when it was about to touch down at a runway of an airport. The tires were deadlocked and not able to roll. The airplane began to skid once it touched down and left behind a 728 m long skid mark on the runway before it came to a stop. Even though everyone on the airplane was safe, the pilot was accused of failing to land the airplane within the allowable speed limit of 80.0 m/s and his pilot license was suspended. Given that the coefficient of kinetic friction between the tires and runway was 0.496. (i) Determine the work done by friction on the tires.(ii) Use the Work-Energy Theorem to evaluate if the suspension of the pilot’s license should be revoked. #This is an exercise question, please help. Thank You.arrow_forwardB9arrow_forwardProblem. An object with mass m₁ = 7 kg moves on a level, frictionless table in a physics lab. It is then connected to a hanging weight with m₂ = 12 kg by a string passing over a small frictionless pulley. The string is light and flexible, and it doesn't stretch. What would be the resulting value of the Tension in the given system? O 74.4 N 43.3 N 56.9 N 23.4 Narrow_forward
- Hazel stands on the edge of a lookout admiring the view of a waterfall. The lookout is supported by a horizontal cantilever beam of length 4.5 m. Hazel's mass is 60 kg 4.5 m What is the upward force on the beam? Use g = 9.81 m/s2 for the acceleration due to gravity.arrow_forwardA 1.0 kg pendulum block at the end of a 1.0 m long rope(assume rope has no mass). When the 1.0 kg mass hangs vertically undisturbed it is in contact with a second block that sits on a flat horizontal surface. The coefficient of friction between the second block and the horizontal surface is 0.15 for kinetic friction and 0.40 for static friction. The 1.0 kg mass is pulled back to an angle of 60. degrees with respect to the vertical and let go. At the lowest point in its swing, it hits the block. After the collision (which takes 0.070 seconds) the 1.0 kg block bounces off the second block and swings back up to an angle of 12 degrees. What is the maximum mass that the second block can have if it moves after the collision?arrow_forwardYou are a bully. You pin a 48 kg dweeb to a wall so that his feet aren't touching the ground. Your arm is extended so that it makes an angle 28 degrees with the horizontal. The dweeb's back is so sweaty with fear that there is no friction between his back and the wall. What is the magnitude of the force , in N, you must apply to keep the dweeb in equilibrium? (Use g = 10 m/s2) This scenario is represented schematically below. Unfortunately for you, years later the dweeb is your boss and he makes your life miserable. (Please answer to the fourth decimal place - i.e 12.3445)arrow_forward
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