Concept explainers
a) -CH3, -Br, -H, -I.
Interpretation:
To rank -CH3, -Br, -H, -I according to Cahn-Ingold-Prelog sequence rules.
Concept introduction:
According to Cahn-Ingold-Prelog sequence rules the member that ranks higher can be determined by considering the
To rank:
The substituents, -CH3, -Br, -H, -I, according to Cahn-Ingold-Prelog sequence rules.
Answer to Problem 45AP
According to Cahn-Ingold-Prelog sequence rules the substituents can be ranked in the order -I, -Br, -CH3, -H.
Explanation of Solution
The first atoms in the substituents given are I, Br, C and CH. Their atomic numbers are 53, 35, 12, 1 respectively. Based on these atomic numbers, the substituents can be ranked in the order -I, -Br, -CH3, -H.
According to the sequence rules the substituents can be ranked in the order -I, -Br, -CH3, -H.
b) -OH, -OCH3, -H, -CO2H.
Interpretation:
To rank -OH, -OCH3, -H, -CO2H according to Cahn-Ingold-Prelog sequence rules.
Concept introduction:
According to Cahn-Ingold-Prelog sequence rules the member that ranks higher can be determined by considering the atomic number of the first atom in each substituent. The atom with highest atomic number gets a higher rank. If a decision cannot be made by considering the atomic number of the first atom in each substituent then the second, third, fourth atoms can be considered until the first difference is found. Multiple bonded atoms are equivalent to the same number of single bonded atoms.
To rank:
The substituents, -OH, -OCH3, -H, -CO2H according to Cahn-Ingold-Prelog sequence rules.
Answer to Problem 45AP
According to Cahn-Ingold-Prelog sequence rules the substituents can be ranked in the order -OCH3, -OH, -CO2H, -H.
Explanation of Solution
Two groups have oxygen as first atom, third one has carbon as the first atom and the fourth one is H. Their atomic numbers are 8, 1, 12 respectively. Both -OH, -OCH3 have O as the first atom. Hence the second, third and fourth atoms to which they are bonded are to be considered. Oxygen in -OH is bonded to H, while the oxygen in -OCH3 is bonded to carbon. Hence -OCH3 ranks higher than -OH. The substituent -CO2H ranks third and -H the fourth.
According to the sequence rules the substituents can be ranked in the order -OCH3, -OH, -CO2H,-H.
c) -CO2H, -CO2CH3, -CH2OH, -CH3.
Interpretation:
To rank -CO2H, -CO2CH3, -CH2OH, -CH3 according to Cahn-Ingold-Prelog sequence rules.
Concept introduction:
The member that ranks higher can be determined by considering the atomic number of the first atom in each substituent. The atom with highest atomic number gets a higher rank. If a decision cannot be made by considering the atomic number of the first atom in each substituent then the second, third, fourth atoms can be considered until the first difference is found. Multiple bonded atoms are equivalent to the same number of single bonded atoms.
To rank:
The substituents -CO2H, -CO2CH3, -CH2OH, -CH3 according to Cahn-Ingold-Prelog sequence rules.
Answer to Problem 45AP
According to Cahn-Ingold-Prelog sequence rules the substituents can be ranked in the order -CO2CH3, -CO2H, -CH2OH, -CH3.
Explanation of Solution
The first atom in all the substituents given is C. Hence the second, third and fourth atoms to which they are bonded are to be considered. Carbon in -CO2CH3 is bonded to three oxygens(double bond) out of which one is attached to a carbon. Carbon in COOH is also bonded to three oxygen atom (double bond) out of which one is attached to a hydrogen. Carbon in –CH2OH is bonded to H, H, O. Carbon in methyl is bonded to H, H, H. Based on the atomic numbers of the differentiating atoms, the substituents can be ranked in the order -CO2CH3, -CO2H, -CH2OH,-CH3.
According to Cahn-Ingold-Prelog sequence rules the substituents can be ranked in the order -CO2CH3, -CO2H, -CH2OH,-CH3.
d) -CH3, -CH2CH3, -CH2CH2OH, -COCH3.
Interpretation:
To rank -CH3, -CH2CH3, -CH2CH2OH, -COCH3 according to Cahn-Ingold-Prelog sequence rules.
Concept introduction:
The member that ranks higher can be determined by considering the atomic number of the first atom in each substituent. The atom with highest atomic number gets a higher rank. If a decision cannot be made by considering the atomic number of the first atom in each substituent then the second, third, fourth atoms can be considered until the first difference is found. Multiple bonded atoms are equivalent to the same number of single bonded atoms.
To rank:
The substituents -CH3, -CH2CH3, -CH2CH2OH, -COCH3 according to Cahn-Ingold-Prelog sequence rules.
Answer to Problem 45AP
According to Cahn-Ingold-Prelog sequence rules the substituents can be ranked in the order -COCH3, -CH2CH2OH, -CH2CH3, -CH3.
Explanation of Solution
The first atom in all the substituents given is C. Hence the second, third and fourth atoms to which they are bonded are to be considered.
Carbon in -COCH3 is bonded to O, O(double bond), C.
Carbon in -CH2CH2OH is bonded to H, H & C attached to H, H, O.
Carbon in –CH2CH3 is bonded to H, H & C attached to three hydrogens.
Carbon in methyl is bonded to H, H, H.
Based on the atomic numbers of the differentiating atoms, the substituents can be ranked in the order -COCH3, -CH2CH2OH, -CH2CH3, -CH3.
According to Cahn-Ingold-Prelog sequence rules the substituents can be ranked in the order -COCH3, -CH2CH2OH, -CH2CH3, -CH3.
e) -CH=CH2, -CN, -CH2NH2, -CH2Br.
Interpretation:
To rank -CH=CH2, -CN, -CH2NH2, -CH2Br according to Cahn-Ingold-Prelog sequence rules.
Concept introduction:
The member that ranks higher can be determined by considering the atomic number of the first atom in each substituent. The atom with highest atomic number gets a higher rank. If a decision cannot be made by considering the atomic number of the first atom in each substituent then the second, third, fourth atoms can be considered until the first difference is found. Multiple bonded atoms are equivalent to the same number of single bonded atoms.
To rank:
The substituents -CH=CH2, -CN, -CH2NH2, -CH2Br according to Cahn-Ingold-Prelog sequence rules.
Answer to Problem 45AP
According to Cahn-Ingold-Prelog sequence rules the substituents can be ranked in the order -CH2Br, -CN, -CH2NH2, -CH=CH2.
Explanation of Solution
The first atom in all the substituents given is C. Hence the second, third and fourth atoms to which they are bonded are to be considered.
Carbon in -CH=CH2, is bonded to C, C(double bond), H.
Carbon in -CN, is bonded to three nitrogens.
Carbon in -CH2NH2 is bonded to N, H, H.
Carbon in -CH2Br is bonded to Br, H, H.
Based on the atomic numbers of the differentiating atoms, the substituents can be ranked in the order -CH2Br, -CN, -CH2NH2, -CH=CH2.
According to Cahn-Ingold-Prelog sequence rules the substituents can be ranked in the order -CH2Br, -CN, -CH2NH2, -CH=CH2.
f) -CH=CH2, -CH2CH3, -CH2OCH3, -CH2OH.
Interpretation:
To rank -CH=CH2, -CH2CH3, -CH2OCH3, -CH2OH according to Cahn-Ingold-Prelog sequence rules.
Concept introduction:
The member that ranks higher can be determined by considering the atomic number of the first atom in each substituent. The atom with highest atomic number gets a higher rank. If a decision cannot be made by considering the atomic number of the first atom in each substituent then the second, third, fourth atoms can be considered until the first difference is found. Multiple bonded atoms are equivalent to the same number of single bonded atoms.
To rank:
The substituents -CH=CH2, -CH2CH3, -CH2OCH3, -CH2OH according to Cahn-Ingold-Prelog sequence rules.
Answer to Problem 45AP
According to Cahn-Ingold-Prelog sequence rules the substituents can be ranked in the order -CH2OCH3, -CH2OH, -CH=CH2, CH2CH3.
Explanation of Solution
The first atom in all the substituents given is C. Hence the second, third and fourth atoms to which they are bonded are to be considered.
Carbon in -CH=CH2, is bonded to C, C(Double bond), H.
Carbon in -CH2CH3 is bonded to C, H, H.
Carbon in -CH2OCH3 is bonded to H, H, O attached to a carbon.
Carbon in -CH2OH is bonded to H, H, O attached to a hydrogen.
Based on the atomic numbers of the differentiating atoms, the substituents can be ranked in the order -CH2OCH3, -CH2OH, -CH=CH2, CH2CH3.
According to Cahn-Ingold-Prelog sequence rules the substituents can be ranked in the order -CH2OCH3, -CH2OH, -CH=CH2, CH2CH3.
Want to see more full solutions like this?
Chapter 7 Solutions
EP ORGANIC CHEMISTRY,24 MONTH-OWLV2
- What is the mechanism by which the 1,4 product is created? Please draw it by hand with arrows and stuff.arrow_forwardWhat is the relationship between A and B? H3C A Br Cl H3C B Br relationship (check all that apply) O same molecule O enantiomer O diastereomer structural isomer O stereoisomer isomer O need more information to decide O same molecule ☐ enantiomer Br Br Br CH3 Br CI CH3 O diastereomer ☐ structural isomer ☐ stereoisomer isomer O need more information to decide O same molecule O enantiomer Odiastereomer structural isomer O stereoisomer ☐ isomer O need more information to decidearrow_forwardb. Please complete the zig-zag conformation of the compound (3R,4S)-3,4-dichloro-2,5-dimethylhexane by writing the respective atoms in the boxes. 4arrow_forward
- c. Serricornin, the female-produced sex pheromone of the cigarette beetle, has the following structure. OH What is the maximum number of possible stereoisomers? Is this structure a meso compound? d. Please consider the natural product alkaloids shown below. Are these two structures enantiomers, diastereomers or conformers? H HO H H HN HO HN R R с R=H cinchonidine R=ET cinchonine Harrow_forwardNail polish remover containing acetone was spilled in a room 5.23 m × 3.28 m × 2.76 m. Measurements indicated that 2,250 mg of acetone evaporated. Calculate the acetone concentration in micrograms per cubic meter.arrow_forwardPlease help me answer number 1. 1. If your graphs revealed a mathematical relationship between specific heat and atomic mass, write down an equation for the relationship. I also don't understand, is the equation from the line regression the one that I'm suppose use to show the relationship? If so could you work it all the way out?arrow_forward
- Describe the principle of resonance and give a set of Lewis Structures to illustrate your explanation.arrow_forwardDon't used hand raitingarrow_forwardIt is not unexpected that the methoxyl substituent on a cyclohexane ring prefers to adopt the equatorial conformation. OMe H A G₂ = +0.6 kcal/mol OMe What is unexpected is that the closely related 2-methoxytetrahydropyran prefers the axial conformation: H H OMe OMe A Gp=-0.6 kcal/mol Methoxy: CH3O group Please be specific and clearly write the reason why this is observed. This effect that provides stabilization of the axial OCH 3 group in this molecule is called the anomeric effect. [Recall in the way of example, the staggered conformer of ethane is more stable than eclipsed owing to bonding MO interacting with anti-bonding MO...]arrow_forward
- 206 Pb 82 Express your answers as integers. Enter your answers separated by a comma. ▸ View Available Hint(s) VAΣ ΜΕ ΑΣΦ Np, N₁ = 82,126 Submit Previous Answers ? protons, neutronsarrow_forwardPlease draw the inverted chair forms of the products for the two equilibrium reactions shown below. Circle the equilibrium reaction that would have a AG = 0, i.e., the relative energy of the reactant (to the left of the equilibrium arrows) equals the relative energy of the product? [No requirement to show or do calculations.] CH3 CH3 HH CH3 1 -CH3arrow_forward5. Please consider the Newman projection of tartaric acid drawn below as an eclipsed conformer (1). Please draw the most stable conformer and two intermediate energy conformers noting that staggered conformers are lower in energy than eclipsed forms even if the staggered conformers have gauche relationships between groups. [Draw the substituents H and OH on the front carbons and H, OH and CO₂H on the back carbons based on staggered forms. -CO₂H is larger than -OH.] OH COH ICOOH COOH COOH 1 2 COOH COOH 3 4 Staggered Staggered Staggered (most stable) Indicate the number of each conformer above (1, 2, 3 and 4) that corresponds to the relative energies below. Ref=0 Rotation 6. (60 points) a. Are compounds 1 and 2 below enantiomers, diastereomers or identical? OH OH HO HO LOH HO HO OH 2 OH OH b. Please complete the zig-zag conformation of the compound (3R,4S)-3,4-dichloro-2,5-dimethylhexane by writing the respective atoms in the boxes. 3.arrow_forward