Brock Biology of Microorganisms (15th Edition)
15th Edition
ISBN: 9780134261928
Author: Michael T. Madigan, Kelly S. Bender, Daniel H. Buckley, W. Matthew Sattley, David A. Stahl
Publisher: PEARSON
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Textbook Question
Chapter 7.8, Problem 2MQ
- What is the major transcriptional regulator that controls heterocyst formation?
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What is the role of PopZ in segregating theCaulobacter daughter chromosomes?
The figure below shows the life cycle of the fungus Neurospora. The adult stage of the Neurospora is a multicellular haploid.
b) Neurospora has an arginine amino acid synthesis pathway shown below. Suppose I take the strain above that only grows with arginine supplements and cross it to a different mutant Neurospora strain that grows with arginine and citrulline supplements but not with ornithine supplements. Assuming gens A, B, and C are unlinked and there is only one mutation per stain:
What percentage of the progeny will grow on ornithine?
What percentage on citrulline?
What percentage on arginine?
For a haploid fungus, the starting point in the biosynthesis of the amino acid
arginine is Compound X, which is always present in and absorbed from the
environment. The arginine biosynthetic pathway is:
Enzyme A
Enzyme B
Enzyme Ç
Compound X
It is know that genes encoding enzymes A and C are on two different
chromosomes.
Compound Y
Compound Z-
Arginine
A mutant strain of genotype a (lacking only enzyme A) is crossed to a mutant strain
of genotype c (lacking only enzyme C) to generate a diploid strain. Sporulation (i.e.
meiosis) is subsequently induced in the resulting diploid strain. What proportion of
the spores (haploids formed by sporulation) is expected to grow on medium without
arginine but supplemented with Compound Y?
O 100%
50%
0%
25%
Chapter 7 Solutions
Brock Biology of Microorganisms (15th Edition)
Ch. 7.1 - What is the utility of a reporter gene?Ch. 7.1 - Prob. 2MQCh. 7.1 - Prob. 1CRCh. 7.2 - Prob. 1MQCh. 7.2 - Prob. 2MQCh. 7.2 - Prob. 1CRCh. 7.3 - What is the divisome?Ch. 7.3 - How does FtsZ find the cell midpoint of a...Ch. 7.3 - What is the role of the penicillin-binding protein...Ch. 7.4 - How does MreB control the shape of a rod-shaped...
Ch. 7.4 - What protein is thought to control the shape of...Ch. 7.4 - What relationships exist between cytoskeletal...Ch. 7.4 - What morphology do cells have that lack MreB or...Ch. 7.5 - Prob. 1MQCh. 7.5 - What is transpeptidation and why is it important...Ch. 7.5 - Prob. 1CRCh. 7.6 - How are different sets of genes expressed in the...Ch. 7.6 - Prob. 2MQCh. 7.6 - Prob. 1CRCh. 7.7 - Why are the levels of DnaA protein controlled...Ch. 7.7 - Prob. 2MQCh. 7.7 - Prob. 1CRCh. 7.8 - Prob. 1MQCh. 7.8 - What is the major transcriptional regulator that...Ch. 7.8 - What is meant by "patterning" during heterocyst...Ch. 7.9 - What are the four basic stages of biofilm...Ch. 7.9 - Besides autoinducer synthesis, what intracellular...Ch. 7.9 - What type of genes does c-di-GMP activate during...Ch. 7.10 - Describe two targets of antibiotics and discuss...Ch. 7.10 - Prob. 2MQCh. 7.10 - Prob. 3MQCh. 7.10 - Prob. 1CRCh. 7.11 - Is persistence a heritable trait?Ch. 7.11 - What prevents the toxin component of TA modules...Ch. 7.11 - Prob. 3MQCh. 7.11 - Prob. 1CRCh. 7 - If DnaA was not regulated in Escherichia coli and...Ch. 7 - Explain how cells exhibiting different phenotypes...Ch. 7 - Describe how you would genetically design a...
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- The oncogenic protein BETA promotes entry into the S phase of the cell cycle. Phosphorylation of BETA at the amino acid Tyr98 causes BETA to be degraded by the proteasome, thus limiting its abundance. A mutation in the codon encoding Tyr98 changes this residue to Cys, which cannot be phosphorylated. What is the best description of this mutant allele?a) antimorphb) hypermorphc) hypomorphd) amorphe) neomorpharrow_forwardWhy does nucleation rate cause the number of microtubules to be proportional to nucleation rate but the length of microtubules to be inversely proportional to nucleation rate?arrow_forwardDuring X inactivation, all but one gene get silenced on one X chromosome. Why does one gene escape the inactivation? A) That is the gene responsible for inactivating the others B) Two copies of that gene are needed in females, so both are active C) X inactivation is rarely complete, so occasionally one or two genes get activated by mistake D) That is the gene that encodes the methyltransferase needed to methylate the genome.arrow_forward
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