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Simpson’s Rule Apply Simpson’s Rule to the following
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- Show all steps. Correct answer is 37.6991118arrow_forwardFind the flux F(x, y, z) = xi + 2yj +4zk, S is the cube with vertices (1, 1, 1), (-1, -1, -1)arrow_forwardB-Solve the D.E of the following: 1- y+3y+2fy dt = f(t) for y(0)-1 if f(t) is the function whose graph is shown below 2- y" +4y = u(t) for y(0)-y'(0)-0 3- y"+4y+13y=e-2t sin3t 1 2 for y(0)-1 and y'(0)=-2arrow_forward
- 25 Given the following graph of the function y = f(x) and n = 6, answer the following questions about the area under the curve from z = 0 to z = 6. (Click on a graph to enlarge it.) your final (Round your answer to within two decimal places if necessary, but do not round until your computation.) a. Use the Trapezoidal Rule to estimate the area. Estimate: T6= b. Use Simpson's Rule to estimate the area. Estimate: S6 Submit answer Next item urself for a radically different driving experience with the 2024 Acura Integra. Offering a range of trims, each with its que characteristics, this sporty car caters to diverse preferences. Explore our comprehensive review to understand how E 0 T The Weather Channel UP F3 = F4 F5 DELL Parrow_forwardex 2. Diketahui ſ¹ e* dx ·00 x a. Kenapa integral diatas merupakan imroper integral? Jelaskan b. Selesaikan integral tersebutarrow_forwardInverse laplace transform Lect: Huda I H.w 1- F(S)= A- Find - F(s) of the following S (s+1)5 1 2- F(s) s² (s-a) 5+5 3- F(s)= s2+4s+3 1 4- F(s)= (s+2)2(s-2) 3s2-7s+5 5- F(s)= (s-1)(s2-5s+6)arrow_forward
- Inverse laplace transform Lect :Huda I H.w A- Find L-1 F(s) of the following 1- F(S)= 2- F(s)- S (+1)5 s² (s-a) 5+5 s2+4s+3 3- F(s)- 1 4- F(s)- (s+2)2(s-2) 3s2-7s+5 5- F(s)- (s-1)(s2-55+6) B-Solve the D.E of the following: 1- y'+3y+2fy dt = f(t) for y(0)-1 if f(t) is the function whose graph is shown below 2 1 2 2-y+4y-u(t) for y(0)=y'(0)=0 3- y"+4y'+13y= e−2t sin3t for y(0)-1 and y'(0)=-2 17arrow_forwardshow step by step answerarrow_forwardWrite the given third order linear equation as an equivalent system of first order equations with initial values. Use Y1 = Y, Y2 = y', and y3 = y". - - √ (3t¹ + 3 − t³)y" — y" + (3t² + 3)y' + (3t — 3t¹) y = 1 − 3t² \y(3) = 1, y′(3) = −2, y″(3) = −3 (8) - (888) - with initial values Y = If you don't get this in 3 tries, you can get a hint.arrow_forward
- Question 2 1 pts Let A be the value of the triple integral SSS. (x³ y² z) dV where D is the region D bounded by the planes 3z + 5y = 15, 4z — 5y = 20, x = 0, x = 1, and z = 0. Then the value of sin(3A) is -0.003 0.496 -0.408 -0.420 0.384 -0.162 0.367 0.364arrow_forwardQuestion 1 Let A be the value of the triple integral SSS₂ (x + 22) = 1 pts dV where D is the region in 0, y = 2, y = 2x, z = 0, and the first octant bounded by the planes x z = 1 + 2x + y. Then the value of cos(A/4) is -0.411 0.709 0.067 -0.841 0.578 -0.913 -0.908 -0.120arrow_forwardIn the xy-plane, the graphs of the linear function and the exponential function E both pass through the points (0,2) and (1,6) The function f is given by f(x) = L(x) - E(x). What is the maximum value of f? A 0.007 B 0.172 C 0.540 D 1.002arrow_forward
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