Let [1,2] R2 be the curve defined by y(t) = (t, 3(t − 1)²) for t = [1,2], and let f R2 R be defined by : (x-1)² - y f(x, y) = 1 +12|y| Then the integral y fds equals (A) 2/13 (B) -2/3 (C) 0 (D) -2
Let [1,2] R2 be the curve defined by y(t) = (t, 3(t − 1)²) for t = [1,2], and let f R2 R be defined by : (x-1)² - y f(x, y) = 1 +12|y| Then the integral y fds equals (A) 2/13 (B) -2/3 (C) 0 (D) -2
Trigonometry (MindTap Course List)
10th Edition
ISBN:9781337278461
Author:Ron Larson
Publisher:Ron Larson
Chapter6: Topics In Analytic Geometry
Section6.2: Introduction To Conics: parabolas
Problem 4ECP: Find an equation of the tangent line to the parabola y=3x2 at the point 1,3.
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correct answer is B
could you please explain
![Let
[1,2]
R2 be the curve defined by y(t) = (t, 3(t − 1)²) for t = [1,2], and
let f R2 R be defined by
:
(x-1)² - y
f(x, y) =
1 +12|y|
Then the integral y fds equals
(A) 2/13
(B) -2/3
(C) 0
(D) -2](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6099d21a-e15a-47f8-adbb-0c871c33581f%2F7525ea83-a0e4-4340-8321-084cf6a0c85d%2Futwzhoq_processed.png&w=3840&q=75)
Transcribed Image Text:Let
[1,2]
R2 be the curve defined by y(t) = (t, 3(t − 1)²) for t = [1,2], and
let f R2 R be defined by
:
(x-1)² - y
f(x, y) =
1 +12|y|
Then the integral y fds equals
(A) 2/13
(B) -2/3
(C) 0
(D) -2
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