• • Let > be a potential for the vector field F = (−2 y³, −6 xy² − 4 z³, −12 yz² + 4 2). Then the value of sin((-1.63, 2.06, 0.57) – (0,0,0)) is - 0.336 -0.931 -0.587 0.440 0.902 0.607 -0.609 0.146
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- 2. Let r = √x² + y² + z². (a) For n ≥ 1 and r > 0, express V(r-n) in terms of r and the radial vector field er. (b) For r> 0, express Vlnr in terms of r and the radial vector field er. (c) Taking A as in question 1, show that for r> 0 we have A(-¹) = 0.Let be a potential for the vector field F = (−24 x³ z + 6 xyz², 3 x² z² + 15 y¹, −6 x¹ + 6 x²yz – 10 %). Then the value of sin((-1.63, 2.06, 0.57) - (0,0, 0)) isLet F1 = (x + y) & + (-x+y)ŷ-2z2 and F2 = 2yx+ (2x + 3z) ŷ +3yî. Calculate the curl and divergence of F1 and F2. Which one can be written as the gradient of a scalar field? Find a suitable potential that does the job.
- Match each of the functions (a)-(c) with the corresponding gradient vector field from those in (I)-(VI). Enter your answer as upper case roman numerals: I, II, III, etc. (a) f(x, y) = x cos(y) (b) f(x, y) = (x - 2)²(y-2)/5 (c) f(x, y) = sin(x) · cos(y) (click on an image to enlarge it) IV II V II VILet (4xy-3x²z²)₁ + (2x²)Ĵ − 2x³ zk = (i) Find a scalar potential for F. (x, y, z) = - note: Answer should have "+C" in it, where C is some constant (ii) Find the work done in moving from (1,1,0) to (2, −1, 1) by the above force field. W= (iii) Solve the differential equation (4xy - 3x²²)dx + 2x²dy - 2x³zdz = 0 ☐ = K, where K is a constantCompute the flux of the vector field F = 5yi +37-5xzk through the surface S, which is the surface y = x² + 2², with x² + 2² ≤ 1, oriented in the positive y-direction. flux = You can get a hint after 2 incorrect answers.
- Find a potential function of the vector field. F(x,y) = (3x²y + 1, x³+2y) Do not guess, show all steps.1- Prove that the force field F known as : Prove that the force field defined by F = (y*z' -6xz² )i + (2xyz³)j +(3xy²z² - 6x°z)k is field. Then fined the Potential function (Potential energy).2. For the vector field F (x, y, z) = (x²y, xyz, −x²y²) F(x, y, z)=(x2y,xyz,-x2 y 2 ), find: (a) div (F)div (F) (b) curl (F)curl(F) (c) div (curl (F))