EBK EXPERIMENTAL ORGANIC CHEMISTRY: A M
6th Edition
ISBN: 9781305687875
Author: Gilbert
Publisher: CENGAGE LEARNING - CONSIGNMENT
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Question
Chapter 7.4, Problem 2E
Interpretation Introduction
Interpretation:
All the possible stereoisomeric forms of the tetrabromo products needs to be drawn due to the addition of bromine to (R)-(-)-carvone.
Concept Introduction :
The stereoisomers having different configurations at all stereocenters are known as enantiomers of each other and if there is different configuration at only one stereocenter but same at other and both isomers are a non-mirror image of each other, they will be diastereomers.
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(a) How will you carry out the following conversions?(i) Acetylene to Acetic acid (ii) Toluene to m-nitrobenzoic acid(iii) Ethanol to Acetone(b) Give reasons :(i) Chloroacetic acid is stronger than acetic acid.(ii) pH of reaction should be carefully controlled while preparing ammonia derivatives of carbonyl compounds.
Explain why
(i) the dipole moment in chlorobenzene is lower than that of cyclohexyl chloride.
(ii) haloalkanes are only slightly soluble in water but dissolve easily in organic solvents.
(a) Cyclohexa-1,3-diene can be converted into a tetrasubstituted haloalkane when reacted with bromine in ether. Write a balanced chemical equation for the reaction that occurs and state the expected observation.
(b) Compound A and B are alkenes with the same molecular formula C5H10. Compound A is a branched-chain alkene while compound B is a straight-chain alkene. The reaction between compound A with hydrogen bromide produces major product C which is optically active.
(i) Draw TWO (2) possible structures for compound B.
(ii) Outline the mechanism for the reaction between compound A with hydrogen bromide to form major product C.
(iii) Name the product formed when compound A undergoes bromination reaction.
Chapter 7 Solutions
EBK EXPERIMENTAL ORGANIC CHEMISTRY: A M
Ch. 7.2 - Prob. 1ECh. 7.2 - Prob. 2ECh. 7.2 - Prob. 3ECh. 7.2 - Prob. 4ECh. 7.2 - Prob. 5ECh. 7.2 - Prob. 6ECh. 7.2 - Prob. 7ECh. 7.2 - Prob. 8ECh. 7.2 - Prob. 9ECh. 7.2 - Prob. 10E
Ch. 7.3 - Prob. 1ECh. 7.3 - Prob. 2ECh. 7.3 - Prob. 3ECh. 7.3 - Prob. 4ECh. 7.3 - Prob. 5ECh. 7.3 - Prob. 6ECh. 7.3 - Prob. 7ECh. 7.3 - Prob. 8ECh. 7.4 - Prob. 1ECh. 7.4 - Prob. 2ECh. 7.4 - Prob. 3ECh. 7.4 - Prob. 4ECh. 7.4 - Prob. 5ECh. 7.4 - Prob. 6ECh. 7.4 - Prob. 7ECh. 7.4 - Prob. 8ECh. 7.4 - Prob. 9ECh. 7.4 - Prob. 10ECh. 7.4 - Prob. 11ECh. 7.4 - Prob. 12ECh. 7.4 - Prob. 13ECh. 7.6 - Prob. 1ECh. 7.6 - Prob. 2ECh. 7.6 - Prob. 3ECh. 7.6 - Prob. 4ECh. 7.6 - Prob. 5ECh. 7.6 - Prob. 6ECh. 7.6 - Prob. 7ECh. 7.6 - Prob. 8ECh. 7.6 - Prob. 9ECh. 7.6 - Prob. 10E
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