Mechanics of Materials (10th Edition)
Mechanics of Materials (10th Edition)
10th Edition
ISBN: 9780134319650
Author: Russell C. Hibbeler
Publisher: PEARSON
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Chapter 7.3, Problem 7.6FP

The two identical boards are bolted together to form the beam. Determine the maximum spacing s of the bolts to the nearest mm if each bolt has a shear strength of 15 kN. The beam is subjected to a shear force of V = 50 kN.

Chapter 7.3, Problem 7.6FP, The two identical boards are bolted together to form the beam. Determine the maximum spacing s of

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CORRECT ANSWER ONLY WITH COMPLETE FBD. PREFERABLY HANDWRITTEN. I WILL UPVOTE  1. The beam shown carries the following loads:Total dead load, wDL = 36 kN/mConcentrated live load, PLL = 240 kNThe beam section is HSS16X12X3/8 with properties:Span, L = 6 mArea, A = 12,100 mm2Moment of inertia about x-axis, Ix = 292 x 106 mm4Fy = 345 MPa  1. Calculate the location of the live load, from the left support, for maximum moment to occur at the fixed support.Answer: 2.536 m2. Calculate the maximum moment. Answer: 439.128 kN-m
CORRECT ANSWER AND COMPLETE FBD ONLY. I PREFER HANDWRITTEN BUT ITS OKAY IF NOT. I WILL UPVOTE 2. The space truss shown is supported by ball-and-socket joints at A, B and C. Factored loads P1 and P2 areacting on joints D and E, respectively, towards the negative y-direction. 1. Calculate the stress of member CE, indicate tension or compression. Answer: 23.61 MPa Tension2. Calculate the stress of member AD, indicate tension or compression. Answer: 21.01 MPa Compression3. Calculate the stress of member CD, indicate tension or compression. Answer: 11.03 MPa Tension
CORRECT ANSWER AND COMPLETE FBD ONLY. I PREFER HANDWRITTEN BUT ITS OKAY IF NOT. I WILL UPVOTE 3. The frame has pin supports at A and E, subject to a wind load. Treat joint C to be an internal hinge. Given:Dimensions, H1 = 3.0 m; H2 = 4.5 m; L = 10.0 mWind loads, wWL (AB) = 4.8 kN/m; wWL (BC) = 3.9 kN/m; wWL (CD) = 1.5 kN/m; wWL (DE) = 1.2 kN/mMembers are made of A36 steel Wide Flange Section with the following properties:Area, A = 64000 mm2Depth, d = 762 mmFlange width, bf = 371 mmThickness of web, tw = 32 mmThickness of flange, tf = 57.9 mmMoment of inertia about x-axis, Ix = 6080 x 106 mm4The wide flange is oriented so that the bending is about the x-axis1. Calculate the stress in member AB, due to the axial load it carries, indicate if tension or compression.Answer: 0.0476 MPa Tension2. Calculate the stress in member DE, due to the axial load it carries, indicate if tension or compression.Answer: 0.2351 MPa Compression3. Calculate the maximum bending stress at B. Answer: 4.282 MPa

Chapter 7 Solutions

Mechanics of Materials (10th Edition)

Ch. 7.2 - If the wide-flange beam is subjected to a shear of...Ch. 7.2 - The wood beam has an allowable shear stress of...Ch. 7.2 - The shaft is supported by a thrust bearing at A...Ch. 7.2 - The shaft is supported by a thrust bearing at A...Ch. 7.2 - Determine the largest shear force V that the...Ch. 7.2 - If the applied shear force V = 18 kip, determine...Ch. 7.2 - The overhang beam is subjected to the uniform...Ch. 7.2 - The beam is made from a polymer and is subjected...Ch. 7.2 - Determine the maximum shear stress in the strut if...Ch. 7.2 - Determine the maximum shear force V that the strut...Ch. 7.2 - Sketch the intensity of the shear-stress...Ch. 7.2 - Plot the shear-stress distribution over the cross...Ch. 7.2 - If the beam is subjected to a shear of V=15 kN,...Ch. 7.2 - If the wide-flange beam is subjected to a shear of...Ch. 7.2 - If the wide-flange beam is subjected to a shear of...Ch. 7.2 - Determine the length of the cantilevered beam so...Ch. 7.2 - If the beam is made from wood having an allowable...Ch. 7.2 - Determine the largest intensity w of the...Ch. 7.2 - If w=800 lb/ft, determine the absolute maximum...Ch. 7.2 - Determine the shear stress at point B on the web...Ch. 7.2 - Determine the maximum shear stress acting at...Ch. 7.2 - Railroad ties must be designed to resist large...Ch. 7.2 - The beam is slit longitudinally along both sides....Ch. 7.2 - The beam is to be cut longitudinally along both...Ch. 7.2 - The composite beam is constructed from wood and...Ch. 7.2 - The beam has a rectangular cross section and is...Ch. 7.2 - The beam in Fig.6-48f is subjected to a fully...Ch. 7.3 - The two identical boards are bolted together to...Ch. 7.3 - Two identical 20-mm-thick plates are bolted to the...Ch. 7.3 - The boards are bolted together to form the...Ch. 7.3 - The boards are bolted together to form the...Ch. 7.3 - The beam is constructed from two boards fastened...Ch. 7.3 - The beam is constructed from two boards fastened...Ch. 7.3 - The beam is constructed from three boards. If it...Ch. 7.3 - The beam is constructed from three boards....Ch. 7.3 - The double T-beam is fabricated by welding the...Ch. 7.3 - The double T-beam is fabricated by welding the...Ch. 7.3 - The beam is constructed from three boards....Ch. 7.3 - A beam is constructed from three boards bolted...Ch. 7.3 - The simply supported beam is built up from three...Ch. 7.3 - The simply supported beam is built up from three...Ch. 7.3 - The T-beam is constructed as shown. If each nail...Ch. 7.3 - The box beam is constructed from four boards that...Ch. 7.3 - The box beam is constructed from four boards that...Ch. 7.3 - The member consists of two plastic channel strips...Ch. 7.3 - The member consists of two plastic channel strips...Ch. 7.3 - The beam is made from four boards nailed together...Ch. 7.3 - The beam is made from three polystyrene strips...Ch. 7.5 - A shear force of V=300 kN is applied to the box...Ch. 7.5 - A shear force of V=450 kN is applied to the box...Ch. 7.5 - A shear force of V = 18 kN is applied to the box...Ch. 7.5 - A shear force of V = 18 kN is applied to the box...Ch. 7.5 - The aluminum strut is 10 mm thick and has the...Ch. 7.5 - The aluminum strut is 10 mm thick and has the...Ch. 7.5 - The beam is subjected to a shear force of V=50...Ch. 7.5 - The beam is subjected to a shear force of V=50...Ch. 7.5 - The H-beam is subjected to a shear of V=80 kN...Ch. 7.5 - The H-beam is subjected to a shear of V=80 kN...Ch. 7.5 - The built-up beam is formed by welding together...Ch. 7.5 - The assembly is subjected to a vertical shear of V...Ch. 7.5 - The box girder is subjected to a shear of V=15 kN....Ch. 7.5 - Determine the location e of the shear center,...Ch. 7.5 - Determine the location e of the shear center,...Ch. 7.5 - The beam supports a vertical shear of V=7 kip....Ch. 7.5 - The stiffened beam is constructed from plates...Ch. 7.5 - The pipe is subjected to a shear force of V=8 kip....Ch. 7.5 - Determine the location e of the shear center,...Ch. 7.5 - A thin plate of thickness t is bent to form the...Ch. 7.5 - Determine the location e of the shear center,...Ch. 7 - The beam is fabricated from four boards nailed...Ch. 7 - The T-beam is subjected to a shear of V = 150 kN....Ch. 7 - The member is subject to a shear force of V = 2...Ch. 7 - Determine the shear stress at points B and C on...Ch. 7 - Determine the maximum shear stress acting at...

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