Chapter 7.2, Problem 50PPS

To determine

To simplify the given expression.

Answer to Problem 50PPS

  $\frac{-12c^3{d}^0{f}^{-2}}{6c^5{d}^{-3}{f}^4}=-\frac{2d^3}{c^2{f}^6}$

Explanation of Solution

Given:

  $\frac{-12c^3{d}^0{f}^{-2}}{6c^5{d}^{-3}{f}^4}$

Calculation:

  $\begin{array}{l}\frac{-12c^3{d}^0{f}^{-2}}{6c^5{d}^{-3}{f}^4}=\frac{6\times \left(-2\right)\times d^3}{6\times c^5\times c^{-3}\times f^4\times f^2}\\ =\frac{-2d^3}{c^{5-3}\times f^{4+2}}\\ =-\frac{2d^3}{c^2{f}^6}\end{array}$