Concept explainers
To examine the given cases
Explanation of Solution
Given:
Parent Function:
Let, a be positive for the analysis.
Calculation:
Case1:
Let
Hence,
Calculation for graph:
Consider
Values of x | Values of f (x) |
0 | 2 |
1 | 6 |
2 | 18 |
-1 | 0.67 |
3 | 54 |
From the above table the graph can be potted.
Calculation for graph:
Consider
Values of x | Values of f (x) |
0 | -2 |
1 | -6 |
2 | -18 |
-1 | -0.67 |
3 | -54 |
From the above table the graph can be potted.
Plotting both the graph on the same plane:
Interpretation:
From the above graph it is clear that
Case2:
Let
Hence,
Calculation for graph:
Consider
Values of x | Values of f (x) |
0 | 2 |
-1 | 6 |
-2 | 18 |
1 | 0.67 |
-3 | 54 |
From the above table the graph can be potted.
Calculation for graph:
Consider
Values of x | Values of f (x) |
0 | -2 |
-1 | -6 |
-2 | -18 |
1 | -0.67 |
-3 | -54 |
From the above table the graph can be potted.
Plotting both the graph on the same plane:
Interpretation:
From the above graph it is clear that
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Algebra 1, Homework Practice Workbook (MERRILL ALGEBRA 1)
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