Chapter 7.2, Problem 49PPS

To determine

To simplify the given expression.

Answer to Problem 49PPS

  $\frac{20q{r}^{-2}{t}^{-5}}{4q^0{r}^4{t}^{-2}}=\frac{5q}{r^6{t}^3}$

Explanation of Solution

Given:

  $\frac{20q{r}^{-2}{t}^{-5}}{4q^0{r}^4{t}^{-2}}$

Calculation:

  $\begin{array}{l}\frac{20q{r}^{-2}{t}^{-5}}{4q^0{r}^4{t}^{-2}}=\frac{4\times 5\times q}{4\times r^4\times r^2\times t^{-2}\times t^5}\\ =\frac{5q}{r^{4+2}\times t^{-2+5}}\\ =\frac{5q}{r^6{t}^3}\end{array}$