Chapter 7.4, Problem 3AGP

To determine

To simplify the given expression $\sqrt{32r^2{k}^4{t}^5}$ .

Answer to Problem 3AGP

  $4r{k}^2{t}^2\sqrt{2t}$

Explanation of Solution

Given$\sqrt{32r^2{k}^4{t}^5}$ .

Calculation:

  $=\sqrt{32r^2{k}^4{t}^5}$

  $=\sqrt{2\times 2\times 2\times 2\times 2\times r^2\times {\left(k^2\right)}^2\times t^2\times t^2\times t}$

  $=2\times 2\times r\times k^2\times t\times t\times \sqrt{2\times t}$

  $=4r{k}^2{t}^2\sqrt{2t}$

Thus, obtained form is the simplified form of the given expression.