ELECTRICITY FOR TRADES
3rd Edition
ISBN: 9780078118630
Author: Petruzella
Publisher: RENT MCG
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Textbook Question
Chapter 7.2, Problem 17RQ
The cold resistance of a tungsten lamp filament is measured using an ohmmeter and found to be much lower than the hot resistance calculated using Ohm’s law and the measured voltage and current values. How can this be possible?
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Consider the following transformer circuit assuming an ideal transformer. In this circuit
the signal generator will provide a 10-Volt peak-to-peak sinusoidal signal at a frequency
of 1.0 kHz. Assume that L₁ = 0.65 H, L2 = 0.00492 H (=4.92 mH) and that the coupling
constant = 0.99925.
+
VG1(
R1 1k
N1:N2
11.5:1
12
V1 N1
N2
V2
R2 8.2
1) Find the following using the theory presented in the prelab reading:
a) Start with Equations (2) of the prelab reading and show that the input impedance
to an ideal transformer is given by the equation for Z1 (=V1/11) in Equations (4) of
the prelab reading.
Equations (2) are: V₁ = joLI₁ + jœMI₂ and V₂ = j@MI₁ +j@L₂I₂
The equation for the input impedance is: Z₁ = 1½ = jwL₁ +
(WM)²
jwL₂+ZL
b) Assuming that Z is a real impedance, find the equations for the real and
imaginary parts of Z1.
c) Use your equations from part (b) to calculate the value of the input impedance
(Z) at an operating frequency of 200 Hz. Assume that the load impedance is 8.2
Ohms…
Use: R1 = 1.5K, R2 = 5K, R3 = 1K, R4 = 2K, R5 = 2K, R6 = 1K.
40%: Find the value for Vs (in V) such as IR2 = 1mA.
40%: Find the voltage VD.
20%: simulate the circuit in Falstad (attach the link).
A
1,5k
B
R1
Vs
L
5k
P2
R2
R6
E
C
R3
С
IR2= 1mA
D
H4
R4
2k
2k
R5
Chapter 7 Solutions
ELECTRICITY FOR TRADES
Ch. 7.1 - What is the base unit and symbol used for...Ch. 7.1 - Write the metric prefix and symbol used to...Ch. 7.1 - Convert each of the following: a. 2,500 to...Ch. 7.2 - State Ohms law.Ch. 7.2 - List the three formulas associated with Ohms law.Ch. 7.2 - Calculate the unknown value for each circuit (a)...Ch. 7.2 - A pilot lamp with 12 volts applied to it draws a...Ch. 7.2 - A resistor has a resistance of 220 . The current...Ch. 7.2 - An electric soldering iron with a 40- heating...Ch. 7.2 - A baseboard heater draws a current of 8 A when...
Ch. 7.2 - A sensor module has an internal resistance of...Ch. 7.2 - The current through and the voltage drop across a...Ch. 7.2 - The heating element for an electric floor heating...Ch. 7.2 - How much power is lost in the form of heat when 25...Ch. 7.2 - The voltage drop across a 330- resistor is...Ch. 7.2 - A digital multimeter display indicates a reading...Ch. 7.2 - Calculate the unknown value for each circuit (a)...Ch. 7.2 - Assume that applying 120 volts to a resistive load...Ch. 7.2 - The voltage drop across a 10-W, 330- resistor is...Ch. 7.2 - The cold resistance of a tungsten lamp filament is...Ch. 7.2 - An electric baseboard heater is rated for 1200 W...Ch. 7.2 - A lamp dimmer switch is rated for 5 A at 120 V....Ch. 7.2 - A 400-W 4- public address speaker is to be fused...
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- Consider the following transformer circuit assuming an ideal transformer. In this circuit the signal generator will provide a 10-Volt peak-to-peak sinusoidal signal at a frequency of 1.0 kHz. Assume that L₁ = 0.65 H, L2 = 0.00492 H (=4.92 mH) and that the coupling constant = 0.99925. + VG1( R1 1k N1:N2 11.5:1 12 V1 N1 N2 V2 R2 8.2 1) Find the following using the theory presented in the prelab reading: a) Start with Equations (2) of the prelab reading and show that the input impedance to an ideal transformer is given by the equation for Z1 (=V1/11) in Equations (4) of the prelab reading. Equations (2) are: V₁ = joLI₁ + jœMI₂ and V₂ = j@MI₁ +j@L₂I₂ The equation for the input impedance is: Z₁ = 1½ = jwL₁ + (WM)² jwL₂+ZL b) Assuming that Z is a real impedance, find the equations for the real and imaginary parts of Z1. c) Use your equations from part (b) to calculate the value of the input impedance (Z) at an operating frequency of 200 Hz. Assume that the load impedance is 8.2 Ohms…arrow_forwardHANDWRITTEN SOLUTION PLEASE NOT USING AIarrow_forwardFor the network of Fig. 7.93, determine: a. ID, and VGS₂- 18 V b. Vps and Vs. Shockley's equation, VGS ID= Vp) ID Vos V 1- VIDSS VGSQ VG = R₂VDD R₁ + R2 VGS VG-IDRS VDS VDD-ID(RD + Rs) (a) ID = 9 mA, VGS₁ = 0.5 V (b) VDs = 7.69 V, Vs = -0.5 V • 2.2 ΚΩ Dss = 8 mA Vp=-8V • 0.39 ΚΩ 8-4 V FIG. 7.93arrow_forward
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