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(a)
Interpretation:
The major product of a Fridel-Crafts alkylation with the given alkyl chloride has to be stated.
Concept Introduction:
The Friedel-Crafts alkylation reaction is an example of electrophilic
In Friedel-Crafts alkylation, the major product is determined by stabilization of an electrophile (a carbocation). A tertiary carbocation is more stable as compare to the secondary and primary carbocation and thereby tertiary carbocation gives major product.
(b)
Interpretation:
The major product of a Fridel-Crafts alkylation with the given alkyl chloride has to be stated.
Concept Introduction:
The Friedel-Crafts alkylation reaction is an example of electrophilic aromatic substitution reaction. This reaction takes place between benzene (mostly) and an alkyl halide in the presence of Lewis acid catalyst. The mechanism of the reaction comprises three steps. The first step is generation of an electrophile (a carbocation). The second step is addition of electrophile on the benzene ring. The third step is deprotonation to yield an alkylated product.
(c)
Interpretation:
The major product of a Fridel-Crafts alkylation with the given alkyl chloride has to be stated.
Concept Introduction:
The Friedel-Crafts alkylation reaction is an example of electrophilic aromatic substitution reaction. This reaction takes place between benzene (mostly) and an alkyl halide in the presence of Lewis acid catalyst. The mechanism of the reaction comprises three steps. The first step is generation of an electrophile (a carbocation). The second step is addition of electrophile on the benzene ring. The third step is deprotonation to yield an alkylated product.
(d)
Interpretation:
The major product of a Fridel-Crafts alkylation with the given alkyl chloride has to be stated.
Concept Introduction:
The Friedel-Crafts alkylation reaction is an example of electrophilic aromatic substitution reaction. This reaction takes place between benzene (mostly) and an alkyl halide in the presence of Lewis acid catalyst. The mechanism of the reaction comprises three steps. The first step is generation of an electrophile (a carbocation). The second step is addition of electrophile on the benzene ring. The third step is deprotonation to yield an alkylated product.
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Chapter 7 Solutions
EBK ESSENTIAL ORGANIC CHEMISTRY
- I don't understand what to put for final step. Does that just mean termination? And would a radical form when I add bromine to ch2 between the rings?arrow_forwardNonearrow_forward11 1 Which one of the following compounds would show a proton NMR signal at the highest chemical shift? (7pts) cl @amitabh CI CI d) Cl CICIarrow_forward
- Nonearrow_forwardH2SO4 (cat.), H₂O 100 °C NH₂arrow_forwardX Draw the major products of the elimination reaction below. If elimination would not occur at a significant rate, check the box under the drawing area instead. ది www. Cl + OH Elimination will not occur at a significant rate. Click and drag to start drawing a structure.arrow_forward
- Nonearrow_forward1A H 2A Li Be Use the References to access important values if needed for this question. 8A 3A 4A 5A 6A 7A He B C N O F Ne Na Mg 3B 4B 5B 6B 7B 8B-1B 2B Al Si P 1B 2B Al Si P S Cl Ar K Ca Sc Ti V Cr Mn Fe Co Ni Cu Zn Ga Ge As Se Br Kr Rb Sr Y Zr Nb Mo Tc Ru Rh Pd Ag Cd In Sn Sb Te I Xe * Cs Ba La Hf Ta W Re Os Ir Pt Au Hg Tl Pb Bi Po At Rn Fr Ra Ac Rf Ha ****** Ce Pr Nd Pm Sm Eu Gd Tb Dy Ho Er Tm Yb Lu Th Pa U Np Pu Am Cm Bk Cf Es Fm Md No Lr Analyze the following reaction by looking at the electron configurations given below each box. Put a number and a symbol in each box to show the number and kind of the corresponding atom or ion. Use the smallest integers possible. cation anion + + Shell 1: 2 Shell 2: 8 Shell 3: 1 Shell 1 : 2 Shell 2 : 6 Shell 1 : 2 Shell 2: 8 Shell 1: 2 Shell 2: 8arrow_forwardNonearrow_forward
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