Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN: 9780133594140
Author: James Kurose, Keith Ross
Publisher: PEARSON
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Chapter 7, Problem R17RQ

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Difference between 3G and 4G cellular architecture:

3G cellular architecture4G cellular architecture
The 3rd generation of wireless mobile telecommunication is simply called as 3G network which gives faster internet speed when compare to 2G and 2.5G GPRS network.The 4th generation of wireless mobile telecommunication is simply called as 4G network; It gives capabilities defined by ITU in IMT advanced...

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Problem 3: Consider the two-link planar elbow manipulator shown below with link information: a₁ = 3, a₂ = 3. a2 S 3/0 Link | a | ai | di ai | di | 0i | มา 02 21 02. 12 01 0 0 01 02 0 0 02 01 To (a) Find the location of the end-effector P° if the joint angles are: 0₁ = 140°, 0₂ = 30° (b) Find the values of joint variables 01, 02 if the robotic manipulator is commanded to reach the desired location of Pº = [4.5, 3,0]. Notice there are possibly two sets of solutions. (c) Also sketch the two poses of the robot for the computed joint variables. Page 5 of 7
Problem 5: The following shows the schematic of a SCARA robot and its DH parameters. Complete the following questions based on this information. 20 01 21 02. 22 done by ai α; di Ꮎ ; 21 d3 1 a1 0 0 0₁** 2 a2 180° 0 0% 3 0 0 d3 0 The Jacobian matrix of this robot is given below: -a1S1a2S12 -a2S12 J(q) = a1c1 + a2c12 0 a2C12 0 10° (a) For a₁ = 1, a2 = 2, is q = 180° a singularity configuration of this robot? a1 3 [10°1 (b) For a₁ = 1, a2 = 2, is q = | 0° a singularity configuration of this robot? 3
(c) Consider the following sequence of rotations: 1) Rotate by 130° about the world z-axis 2) Rotate by 45° about the current x-axis 3) Rotate by -30° about the world/fixed y-axis Compute the resulting overall rotation matrix R. Notice that you need to provide the numerical solution to the matrix R. (d) Find R giving the following rotation matrices. 1 0 0 1 √√3 го о 0 0 R₁₁ = 2 R₁ = 0 1 0 1 0 0 0 2 2
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