Chapter 7, Problem 83P

Interpretation Introduction

Interpretation:

The sample from sample a with 100.0 g of water at 16 °C absorbing 200 cal of heat or sample b with 50g of water at 16 °C absorbing 350cal of heat having higher temperature needs to be determined.

Concept introduction:

The heat needed to raise the temperature of a unit mass of a substance by a unit degree is termed as specific heat. It is denoted by the equation.

  $\text{Specific heat= }\frac{\text{Heat}}{\text{Mass x ΔT}}$

Here, heat is measured in 'calories' or 'Joules', Mass is measured in 'g' and temperature in '(C'.

Therefore, the equation is also represented as follows:

  $C=\frac{Q}{m\text{ x ΔT }}$