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(a)
Interpretation:
The terminal velocity of the urea pellets for the free settling is to be calculated.
Concept Introduction:
The terminal velocity is the constant velocity which a particle attains when moving in a fluid at the zero acceleration.
The settling regime criteria determine the type of flow and the range in which the particle lies. The equation for the same is,
The notations used are,
K = Settling criteria constant
Dp = Diameter of the particle
g = Acceleration due to gravity
For Stokes’ law regime, K < 2.6
For very small Reynolds number, Stokes law is applied to calculate the terminal velocity and equation for the same is given as,
For Newton’s law regime, 68.9 < K < 2360
For large Reynolds number, Newton’s law is applied to calculate the terminal velocity and equation for the same is given as,
(b)
Interpretation:
Velocity of the pellets at the bottom of the tower is to be determined and compare it with the terminal velocity calculated in previous part.
Concept Introduction:
There are 3 forces which act on a particle when it is present in the fluid. These forces are, upward buoyant force, drag force and gravity force. The equation which is obtained on combining the 3 forces are,
The notations used are,
m = Mass of the particle
g = Acceleration due to gravity
CD = Drag coefficient
u = Velocity of particle relative to fluid
Ap = Projected area of particle
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Chapter 7 Solutions
Unit Operations Of Chemical Engineering
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- oh 30 20 D и D P 60 60 80arrow_forward⑤ b Δε m ab C 40arrow_forwardProblem 10.16 An isosceles triangle of base 40 mm and altitude 54 mm has its base in the V.P. The surface of the plane is inclined at 50° to the V.P. and perpendicular to the H.P. Draw its projections. Construction Refer to Fig. 10.17. An isosceles triangle has its base in the V.P., so con- sider that initially the triangle ABC is placed in the V.P. with base AB perpendicular to the H.P. 1. First stage Draw a triangle a'b'c' keeping a'b' perpendicular to xy to represent the front view. Project the corners to xy and obtain ac as the top view. 2. Second stage Reproduce the top view of first stage keeping ab on xy and ac inclined at 50° to xy. Obtain new points a', b' and c' in the front view by joining the points of intersection of the vertical projectors from a, b and c of the second stage with the corresponding horizontal locus lines from a', b' and c' of the first stage. Join a'b'c' to represent the final front view. Here, the front view is an equilateral triangle of side 40 mm. X 54…arrow_forward
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