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(a)
Interpretation:
The amount of heat released when 0.255 mol of aluminum has reacted in kJ is to be determined.
Concept Introduction:
Enthalpy H: it is the total amount of heat in a particular system.
The value of heat formed in a reaction ΔH is calculated by the formula,
ΔH=∑(Bond Dissociation Energy)(reactants) −∑(Bond Dissociation Energy)(products)
If the value obtained for ΔH in a reaction is positive then it is an endothermic reaction whereas the value obtained for ΔH is negative it is an exothermic reaction.
Conversion of kcal to joules is 1 kcal = 4184 J
(b)
Interpretation:
The amount of heat released when 5 g of aluminum has reacted in kcal is to be determined.
Concept Introduction:
Enthalpy H: it is the total amount of heat in a particular system.
The value of heat formed in a reaction ΔH is calculated by the formula,
ΔH=∑(Bond Dissociation Energy)(reactants) −∑(Bond Dissociation Energy)(products)
If the value obtained for ΔH in a reaction is positive then it is an endothermic reaction whereas the value obtained for ΔH is negative it is an exothermic reaction.
Conversion of kcal to joules is 1 kcal = 4184 J
From its given mass is,
Number of moles = Given massMolecular mass
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Chapter 7 Solutions
Fundamentals of General, Organic, and Biological Chemistry (8th Edition)
- What is the primary sequence of this undecapeptide? Also, if x-ray crystallography shows a highly stable hairpin turn within the polypeptide, what about the primary sequence explains this structural feature?arrow_forwardDraw the product of this reaction. Ignore inorganic byproducts. H H ⚫OH HO- -H H- -OH H- -OH CH2OH Ag*, NH4OH, H2O Draw Fischer Projectionarrow_forwardDraw the product of this reaction. Ignore inorganic byproducts. H₂O -OH H ⚫OH HO H HO- CH2OH Cu2+ Draw Fischer Projectionarrow_forward
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- Draw the product of this reaction. Ignore inorganic byproducts. HO HO- HO H HO ∙H HO CH2OH NaBH4, CH3OH Draw Fischer Projectionarrow_forwardDraw the product of this reaction. Ignore inorganic byproducts. Но сво HO H HO H H OH H -OH CH2OH H2 Pd Draw Fischer Projectionarrow_forwardDraw the Haworth projection for Gulose-ẞ-1,6-sorbose and answer the following questions. (Gulose will be in the pyranose form and Sorbose will be in the furanose form) a. Label the reducing and nonreducing ends of the disaccharide b. Label the glycosidic bond c. Circle the anomeric carbons and label them as hemiacetals or acetals. d. Can this disaccharide undergo mutarotation?arrow_forward
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