(a)
Interpretation:
The amount of energy dissipated as heat by the friction of the breaking process is to be calculated.
Concept introduction:
A braking process is a type of process in which kinetic energy is generated by an automobile. The released kinetic energy gets converted into heat energy.
(b)
Interpretation:
The average rate at which energy dissipates in the given situation by the resulting friction situation is to be calculated.
Concept introduction:
A braking process is a type of process in which kinetic energy is generated by an automobile. The released kinetic energy gets converted into heat energy.
(c)
Interpretation:
The information on the average per-capita consumption of electricity in the United States, France and India is to be determined. The number of people in each country would have met their electricity needs in the given situation is to be calculated.
Concept introduction:
A braking process is a type of process in which kinetic energy is generated by an automobile. The released kinetic energy gets converted into heat energy.
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Chapter 7 Solutions
Elementary Principles of Chemical Processes, Binder Ready Version
- A flash drum at 1.0 atm is separating a feed consisting of methanol and water. If the feed rate is 2000 kg/h and the feed is 45 wt % methanol, what are the values of L (kg/h), V (kg/h), yM, xM (weight fractions), and Tdrum if 35% by weight of the feed is vaporized? VLE data are in Table 2-8.arrow_forwardQ1.B. Make a comparison between current control PWM rectifier in the abc reference frame and dq reference frame.arrow_forwardstep by steparrow_forward
- The power out of an adiabatic steam turbine is 5 MW and the steam enters turbine at 2 MPa and velocity of 50 m/s, specific enthalpy (h) of 3248 kJ/kg. The elevation of the inlet is 10 m higher than at the datum. The vapor mixture exits at 15 kPa and a velocity of 180 m/s, specific enthalpy (h) of 2361.01 kJ/kg. The elevation of the exit is 6 m higher than at the datum. Let g = 9.81 m/s². Assuming the ideal gas model and R = 0.462 KJ/(kg.K). The steam specific heat ratio is 1.283. Calculate:arrow_forwardstep by step pleasearrow_forwardstep by step pleasearrow_forward
- step by steparrow_forwardThe power out of an adiabatic steam turbine is 5 MW and the steam enters turbine at 2 MPa and velocity of 50 m/s, specific enthalpy (h) of 3248 kJ/kg. The elevation of the inlet is 10 m higher than at the datum. The vapor mixture exits at 15 kPa and a velocity of 180 m/s, specific enthalpy (h) of 2361.01 kJ/kg. The elevation of the exit is 6 m higher than at the datum. Let g = 9.81 m/s². Assuming the ideal gas model and R = 0.462 KJ/(kg.K). The steam specific heat ratio is 1.283. Calculate:arrow_forwardThe power out of an adiabatic steam turbine is 5 MW and the steam enters turbine at 2 MPa and velocity of 50 m/s, specific enthalpy (h) of 3248 kJ/kg. The elevation of the inlet is 10 m higher than at the datum. The vapor mixture exits at 15 kPa and a velocity of 180 m/s, specific enthalpy (h) of 2361.01 kJ/kg. The elevation of the exit is 6 m higher than at the datum. Let g = 9.81 m/s². Assuming the ideal gas model and R = 0.462 KJ/(kg.K). The steam specific heat ratio is 1.283. Calculate:arrow_forward
- O Consider a 0.8 m high and 0.5 m wide window with thickness of 8 mm and thermal conductivity of k = 0.78 W/m °C. For dry day, the temperature of outdoor is -10 °C and the inner room temperature is 20°C. Take the heat transfer coefficient on the inner and outer surface of the window to be h₁ = 10 W/m² °C and h₂ = 40 W/m² °C which includes the effects of insulation. Determine:arrow_forwardCalculate the mass flow rate of the steam. Determine Cp and C₁ of steam.arrow_forwardstep by step pleasearrow_forward
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