Chapter 7, Problem 67APP

(a)

Interpretation Introduction

Interpretation : The mass in grams for the oxygen atom of the given molecule should be calculated.

Concept Introduction : The equality and conversion factor can be used to convert moles to grams and grams to moles. We can use the molar mass to convert grams to moles of it.

The mathematical expression is as follows:

  $n=\frac{m}{M}$

Here, n is number of moles, m is mass and M is molar mass.

(b)

Interpretation Introduction

Interpretation : The mass in grams for the oxygen atom of the given molecule should be calculated.

Concept Introduction : The equality and conversion factor can be used to convert moles to grams and grams to moles. We can use the molar mass to convert grams to moles of it.

The mathematical expression is as follows:

  $n=\frac{m}{M}$

Here, n is number of moles, m is mass and M is molar mass.

(c)

Interpretation Introduction

Interpretation : The mass in grams for the oxygen atom of the given molecule should be calculated.

Concept Introduction : The equality and conversion factor can be used to convert moles to grams and grams to moles. We can use the molar mass to convert grams to moles of it.

The mathematical expression is as follows:

  $n=\frac{m}{M}$

Here, n is number of moles, m is mass and M is molar mass.