EP BASIC CHEMISTRY-STANDALONE ACCESS
6th Edition
ISBN: 9780134999890
Author: Timberlake
Publisher: PEARSON CO
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Question
Chapter 7, Problem 83APP
Interpretation Introduction
Interpretation : The empirical and molecular formula of the compound should be calculated.
Concept Introduction : Any compound can easily represent with the help of molecular formula. Another type of formula is empirical formula which represents the lowest whole number ratio of atoms in a compound. It does not represent the actual number of atoms in the molecule. The relation between molecular formula and empirical formula can be written as;
Molecular formula = small integer x empirical formula
The following steps should be followed to get the molecular formula:
1. Calculate the number of moles for each element.
2. Divide by smallest number of moles.
3. Write the empirical formula with the help of whole number of step-2.
4. Calculate the mass of empirical formula with the help of
5. Calculate the integer value and find the molecular formula.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
None
24. Calculate the mass percent of K in K2CrO4. (3.5)
(5.8)Which of the following reactions will form a gaseous product?
O H₂CO3(aq) + Pb(NO3)2(aq)
O NaOH(aq) + HNO3(aq)
O None of these
O Na₂SO3(aq) + H₂SO4(aq)
◄ Previous
Chapter 7 Solutions
EP BASIC CHEMISTRY-STANDALONE ACCESS
Ch. 7.1 - What is a mole?Ch. 7.1 - What is Avogadro’s number?Ch. 7.1 - Calculate each of the following: a. number of C...Ch. 7.1 - Calculate each of the following: a. number of Li...Ch. 7.1 - Calculate each of the following quantities in 2.00...Ch. 7.1 - Calculate each of the following quantities in...Ch. 7.1 - Quinine, C20H24N2O2 , is a component of tonic...Ch. 7.1 - Aluminum sulfate, Al2(SO4)3 , is used in some...Ch. 7.1 - Naproxen is used to treat pain and inflammation...Ch. 7.1 - Benadryl is an over-the-counter drug used to treat...
Ch. 7.2 - Calculate the molar mass for each of the...Ch. 7.2 - Calculate the molar mass for each of the...Ch. 7.2 - Calculate the molar mass for each of the...Ch. 7.2 - Calculate the molar mass for each of the...Ch. 7.2 - Calculate the molar mass for each of the...Ch. 7.2 - Calculate the molar mass for each of the...Ch. 7.2 - Calculate the molar mass for each of the...Ch. 7.2 - Calculate the molar mass for each of the...Ch. 7.2 - Calculate the molar mass for each of the...Ch. 7.2 - Calculate the molar mass for each of the...Ch. 7.3 - Calculate the mass, in grams, for each of the...Ch. 7.3 - Calculate the mass, in grams, for each of the...Ch. 7.3 - Calculate the mass, in grams, in 0.150 mol of each...Ch. 7.3 - Calculate the mass, in grams, in 2.28 mol of each...Ch. 7.3 - Calculate the number of moles in each of the...Ch. 7.3 - Calculate the number of moles in each of the...Ch. 7.3 - Calculate the number of moles in 25.0 g of each of...Ch. 7.3 - Calculate the number of moles in 4.00 g of each of...Ch. 7.3 - Calculate the mass, in grams, of C in each of the...Ch. 7.3 - Calculate the mass, in grams, of N in each of the...Ch. 7.3 - Propane gas, C3H8 , is used as a fuel for many...Ch. 7.3 - Allyl sulfide, (C3H5)2S , gives garlic, onions,...Ch. 7.3 - a. The compound MgSO4 , Epsom salts, is used to...Ch. 7.3 - Prob. 34PPCh. 7.3 - Prob. 35PPCh. 7.3 - Prob. 36PPCh. 7.4 - Calculate the mass percent composition of each of...Ch. 7.4 - Calculate the mass percent composition of each of...Ch. 7.4 - Prob. 39PPCh. 7.4 - Prob. 40PPCh. 7.4 - Prob. 41PPCh. 7.4 - Calculate the mass percent of S in each of the...Ch. 7.5 - Calculate the empirical formula for each of the...Ch. 7.5 - Calculate the empirical formula for each of the...Ch. 7.5 - Calculate the empirical formula for each of the...Ch. 7.5 - Calculate the empirical formula for each of the...Ch. 7.6 - Write the empirical formula for each of the...Ch. 7.6 - Prob. 48PPCh. 7.6 - The carbohydrate fructose found in honey and...Ch. 7.6 - Caffeine has an empirical formula of C4H5N2O . If...Ch. 7.6 - Prob. 51PPCh. 7.6 - Glyoxal, used in textiles; maleic acid, used to...Ch. 7.6 - Prob. 53PPCh. 7.6 - Prob. 54PPCh. 7.6 - Vanillic acid contains 57.14% C, 4.80% H, and...Ch. 7.6 - Lactic acid, the substance that builds up in...Ch. 7.6 - A sample of nicotine, a poisonous compound found...Ch. 7.6 - Adenine, a nitrogen-containing compound found in...Ch. 7.6 - Clavulanic acid has a molecular formula of C8H9NO5...Ch. 7.6 - Phenylpropanolamine (PPA) is used to treat urinary...Ch. 7 - The chapter sections to review are shown in...Ch. 7 - The chapter sections to review are shown in...Ch. 7 - The chapter sections to review are shown in...Ch. 7 - Prob. 64UTCCh. 7 - Prob. 65APPCh. 7 - Calculate the mass, in grams, of Cu in each of the...Ch. 7 - Prob. 67APPCh. 7 - Calculate the mass percent composition for each of...Ch. 7 - Prob. 69APPCh. 7 - Prob. 70APPCh. 7 - A mixture contains 0.250 mol of Mn2O3 and 20.0 g...Ch. 7 - A mixture contains 4.001023 molecules of PCl3 and...Ch. 7 - Prob. 73APPCh. 7 - Prob. 74APPCh. 7 - Prob. 75APPCh. 7 - Prob. 76APPCh. 7 - Prob. 77APPCh. 7 - Prob. 78APPCh. 7 - Calculate the molar mass for each of the...Ch. 7 - Calculate the molar mass for each of the...Ch. 7 - Aspirin, C9H8O4 , is used to reduce inflammation...Ch. 7 - Ammonium sulfate, (NH4)2SO4 , is used in...Ch. 7 - Prob. 83APPCh. 7 - Prob. 84APPCh. 7 - Oleic acid, a component of olive oil, is 76.54% C,...Ch. 7 - Prob. 86APPCh. 7 - Prob. 87CPCh. 7 - Prob. 88CPCh. 7 - Prob. 89CPCh. 7 - The following problems are related to the topics...Ch. 7 - For parts a to f, consider the loss of electrons...Ch. 7 - A sterling silver bracelet, which is 92.5% silver...Ch. 7 - Prob. 9CICh. 7 - The active ingredient in an antacid tablet is...Ch. 7 - Oseltamivir, C16H28N2O4 , is a drug that is used...Ch. 7 - Prob. 12CI
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Similar questions
- (3.9) How many grams of hydrogen are present in 255 mL of propane at room temperature? The density of propane is 0.493 g/mL at room temperature. O 45.6 g O 11.4 g O 22.8 g O 5.70 garrow_forwardNeed typed solutionarrow_forward(3.9)Calculate the percent composition of sulfur in aluminum sulfate, Al2(SO4)3. 28.1% 17.7% 71.9% 33.6% ◄ Previousarrow_forward
- hemistry-4th Hour - Dr. Paul / Gases/Lesson 148 Honor 22. According to Charles' law, what kind of relationship does temperature and volume have? O direct relationship O no relationship O indirect relationship chemical relationship GET IT ablo! (3.0.227)arrow_forward9.1 Calculate the total mass of the reactants and the products for each of the following equations: a. 2SO₂(g) + O₂(g)2SO3(g) b. 4P(s) + 50₂(g) 2P₂O5(s) nogearrow_forwardP. How many moles of oxygen are needed to produce water when 4 x 10 molecules of hydrogen are used? (0.3). -> H,O H2 + O2arrow_forward
- 7.16 Calculate the molar mass for each of the following: a. FeSO4, iron supplement b. Al2O3, absorbent and abrasive c. C7H5NO3S, saccharin, artificial sweetenerarrow_forwardA student sets up and solves the following equation to solve a problem in solution stoichiometry. Fill in the missing part of the student's equation. (47.6) 65.08 mol 1 mL -3 10 L mol (3²) 3.2 L = 2.3 x 10 mL x10 ロ・ロ X μarrow_forward, (What is the weight needed to prepare (2 litters) of (0.1)N of calcium carbonate (CaC03 Awt. Ca = 40, C= 12, 0 =16 .A g/mol 12.5 .B g/mol 25 .c g/mol 50 .D g/mol 100arrow_forward
- 8. 9. 10. 4 Fe + 3 0₂ → 2 Fe₂O3 If you have 43 grams of oxygen, how many mols of iron(III) oxide will be formed? If you have 7.5 mol of iron, how many mols of oxygen would be required? If you have 125 g of iron, how many grams of iron(III) oxide will be formed? was per the an de and the red nox 91arrow_forward(4.3: Similar to Conceptual Connection) How many moles of O₂(g) are required to react with 5.38 moles of C4H10(g) according to the following reaction? 2C4010(g) + 1302(g) --> 8CO2(g) + 10H₂O(g) O 16.1 mol O 29.6 mol O 69.9 mol 35.0 molarrow_forward9. Which element is oxidized in the following reaction: 2FECI2 + Cl2 → 2FECI3 if Fe goes from +2 to +3 and CI goes from 0 to –2? Fe Neither element CI Cl and Fe GET IT NOW New version available! (3.0.220) PREVIOUSarrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage Learning
ChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill Education
Principles of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill Education
Chemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage Learning
Elementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY
Chemistry
Chemistry
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Cengage Learning
Chemistry
Chemistry
ISBN:9781259911156
Author:Raymond Chang Dr., Jason Overby Professor
Publisher:McGraw-Hill Education
Principles of Instrumental Analysis
Chemistry
ISBN:9781305577213
Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:Cengage Learning
Organic Chemistry
Chemistry
ISBN:9780078021558
Author:Janice Gorzynski Smith Dr.
Publisher:McGraw-Hill Education
Chemistry: Principles and Reactions
Chemistry
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:Cengage Learning
Elementary Principles of Chemical Processes, Bind...
Chemistry
ISBN:9781118431221
Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:WILEY
Bonding (Ionic, Covalent & Metallic) - GCSE Chemistry; Author: Science Shorts;https://www.youtube.com/watch?v=p9MA6Od-zBA;License: Standard YouTube License, CC-BY
Stoichiometry - Chemistry for Massive Creatures: Crash Course Chemistry #6; Author: Crash Course;https://www.youtube.com/watch?v=UL1jmJaUkaQ;License: Standard YouTube License, CC-BY