In many engineering uses, the value of "g," the acceleration due to gravity, is taken as a constant. However, g is actually dependent upon the distance from the center of the Earth. A more accurate expression for g is: g = g 0 ( R e R e + A ) 2 Here, g 0 is the acceleration of gravity at the surface of the Earth, A is the altitude above the Earth's surface, and R, is the radius of the Earth, approximately 6,380 kilometers [km]. Assume g 0 = 9.8 meters per second squared [m/s 2 ]. If the value of g is 9 meters per second squared [m/s 2 ], what is the altitude in units of miles [mi]?
In many engineering uses, the value of "g," the acceleration due to gravity, is taken as a constant. However, g is actually dependent upon the distance from the center of the Earth. A more accurate expression for g is: g = g 0 ( R e R e + A ) 2 Here, g 0 is the acceleration of gravity at the surface of the Earth, A is the altitude above the Earth's surface, and R, is the radius of the Earth, approximately 6,380 kilometers [km]. Assume g 0 = 9.8 meters per second squared [m/s 2 ]. If the value of g is 9 meters per second squared [m/s 2 ], what is the altitude in units of miles [mi]?
Solution Summary: The author calculates the altitude (A) above the earth's surface in units of miles, 173.699. The acceleration due to gravity is 9 meters per second squared.
In many engineering uses, the value of "g," the acceleration due to gravity, is taken as a constant. However, g is actually dependent upon the distance from the center of the Earth. A more accurate expression for g is:
g
=
g
0
(
R
e
R
e
+
A
)
2
Here, g0 is the acceleration of gravity at the surface of the Earth, A is the altitude above the Earth's surface, and R, is the radius of the Earth, approximately 6,380 kilometers [km]. Assume g0 = 9.8 meters per second squared [m/s2]. If the value of g is 9 meters per second squared [m/s2], what is the altitude in units of miles [mi]?
A wheel of diameter 150.0 mm and width 37.00 mm carrying a load 2.200 kN rolls on a
flat rail. Take the wheel material as steel and the rail material as cast iron. Assume the
figure given, which is based on a Poisson's ratio of 0.3, is applicable to estimate
the depth at which the maximum shear stress occurs for these materials. At this critical
depth, calculate the Hertzian stresses σr, σy, σz, and Tmax for the wheel.
1.0
0.8
0, т
Ratio of stress to Pmax
0.4
0.6
90
69
0.2
0.5b
b
1.5b
Tmax
2b
Distance from contact surface
The Hertizian stresses are as follows:
02 = or = -23.8 psi for the wheel =|
necessary.)
σy for the wheel =|
MPa
σz for the wheel =
MPa
V4 for the wheel = |
MPa
2.5b
ཡི
3b
MPa (Include a minus sign if
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