Express the following values using scientific notation, engineering notation, and using an appropriate SI prefix such that there are only one, two, or three digits shown to the left of the decimal Standard Scientific Engineering With Prefix (a) 389,589,000 joules [J] (b) 0.0000000008 pascals [Pa]

Question

Want to see more full solutions like this?

Answer 1

Textbook Question

Chapter 7, Problem 1ICA

Express the following values using scientific notation, engineering notation, and using an appropriate SI prefix such that there are only one, two, or three digits shown to the left of the decimal

Standard	Scientific	Engineering	With Prefix
(a) 389,589,000 joules [J]
(b) 0.0000000008 pascals [Pa]

(a)

Expert Solution

To determine

Express the given standard value 389,589,000 J using an appropriate scientific notation, engineering notation and SI prefix.

Answer to Problem 1ICA

The given standard value 389,589,000 J is expressed in appropriate scientific notation, engineering notation and with SI prefix as follows.

Standard	Scientific	Engineering	With Prefix
389,589,000 joules [J]	3⋅89589×108 J	389.589×106 J	389.589 MJ

Explanation of Solution

Given data:

The standard value is 389,589,000 J.

Formula used:

Consider the general Scientific notation as,

#.###×10N (1)

Here,

# is single digit to the left of the decimal point which is the most significant nonzero digit,

N is an integer, and

10N is provide to locate the true position of the decimal point.

Consider the general Engineering notation as,

###.###×10M (2)

Here,

M is an integer multiple of 3, and

# is the number of digits to the left of the decimal point which is one, two, or three as required to yield a power of 10 that is indeed a multiple of 3.

Calculation:

The given standard value in Joules is,

Standard value=389,589,000 J

Convert the value into scientific notation using the expression in equation (1) as follows,

389,589,000 J=3.89589000×108 J=3.89589×108 J

Convert the value into engineering notation using expression equation (2) as follows,

389,589,000 J=389.589000×106 J=389.589×106 J (3)

Consider the SI prefixes.

1 Mega=1 M=106

Convert the standard value into SI prefixes using the equation (3).

389,589,000 J=389.589×(1 M) J {∵1 Mega=1 M=106}=389.589 MJ

Conclusion:

Hence, the given standard value 389,589,000 J is expressed in the appropriate scientific notation, engineering notation and with SI prefixes as follows.

Standard	Scientific	Engineering	With Prefix
389,589,000 joules [J]	3⋅89589×108 J	389.589×106 J	389.589 MJ

(b)

Expert Solution

To determine

Express the given standard value 0.0000000008 Pa using an appropriate scientific notation, engineering notation and SI prefix.

Answer to Problem 1ICA

The given standard value 0.0000000008 Pa is expressed in appropriate scientific notation, engineering notation and with SI prefix as follows.

Standard	Scientific	Engineering	With Prefix
0.0000000008 pascals [Pa]	8.0×10−10 Pa	800.0×10−12 Pa	800.0 pPa

Explanation of Solution

Given data:

The standard value is 0.0000000008 Pa.

Calculation:

The given standard value in Pascal is,

Standard value=0.0000000008 Pa

Convert the value into scientific notation using the expression in equation (1) as follows,

0.0000000008 Pa=8.0×10−10 Pa

Convert the value into engineering notation using expression in equation (2) as follows,

0.0000000008 Pa=800.0×10−12 Pa (4)

Consider the SI prefixes.

1 pico=1 p=10−12

Convert the standard value into SI prefixes using equation (4).

0.0000000008 Pa=800.0×10−12 Pa=800.0 (1 p)Pa {∵1 pico=1 p=10−12}=800.0 pPa

Conclusion:

Hence, the given standard value 0.0000000008 Pa is expressed in the appropriate scientific notation, engineering notation and with SI prefix as follows.

Standard	Scientific	Engineering	With Prefix
0.0000000008 pascals [Pa]	8.0×10−10 Pa	800.0×10−12 Pa	800.0 pPa

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

03:55

Students have asked these similar questions

Which of the following sequences converge and which diverge? 20) an = 21) a = n! 106 1/(Inn) 3n+1 " 22) a = 3n-1 1/n x" 23) a = , x>0 2n+1 3" x 6" 24) an 25) a, = tanh(n) = 2" xn! n² 1 26) a = sin 2n-1 n 27) a = tan(n) 1 28) a = 1 3 ++ (Inn) 200 2" 29) an n 30) =n-√√n²-n 1"1 31) a == dx nix

Which of the following sequences converge and which diverge? n+1 6) a = 1- 2n (-1)+1 7) a = 2n-1 2n 8) an = n+1 1 9) a = sin + 2 n sin n 10) a = n 11) an = 12) a = 13) an 14) an 15) an 16) an n 2" In(n+1) = 81/n n n =(1+7)" = = 10n 3 n 1/n 17) an = In n 1/n n' 18) a =√4"n

Qu 3 Nickel (Ni) single crystal turbine blades burn less fuel at higher temperatures because blades are grown on [110] closed packed direction. Nickel (Ni) at 20°C is FCC, and has an atomic radius, R, of 0.125 nm. Draw a reduced-sphere unit cell for this crystal and draw and label the vector [I 10], starting from the origin (0, 0, 0). a) Calculate the length of the vector [| 10] in nanometers. Express your answer in nanometers to one significant figure. b) Calculate the linear density of Nickel in the [| 1 0] direction in [atom/nm]. Express your answer in atoms/nm to one significant figure. show all work problems

Answer 2

Textbook Question

Chapter 7, Problem 1ICA

Express the following values using scientific notation, engineering notation, and using an appropriate SI prefix such that there are only one, two, or three digits shown to the left of the decimal

Standard	Scientific	Engineering	With Prefix
(a) 389,589,000 joules [J]
(b) 0.0000000008 pascals [Pa]

(a)

Expert Solution

To determine

Express the given standard value 389,589,000 J using an appropriate scientific notation, engineering notation and SI prefix.

Answer to Problem 1ICA

The given standard value 389,589,000 J is expressed in appropriate scientific notation, engineering notation and with SI prefix as follows.

Standard	Scientific	Engineering	With Prefix
389,589,000 joules [J]	3⋅89589×108 J	389.589×106 J	389.589 MJ

Explanation of Solution

Given data:

The standard value is 389,589,000 J.

Formula used:

Consider the general Scientific notation as,

#.###×10N (1)

Here,

# is single digit to the left of the decimal point which is the most significant nonzero digit,

N is an integer, and

10N is provide to locate the true position of the decimal point.

Consider the general Engineering notation as,

###.###×10M (2)

Here,

M is an integer multiple of 3, and

# is the number of digits to the left of the decimal point which is one, two, or three as required to yield a power of 10 that is indeed a multiple of 3.

Calculation:

The given standard value in Joules is,

Standard value=389,589,000 J

Convert the value into scientific notation using the expression in equation (1) as follows,

389,589,000 J=3.89589000×108 J=3.89589×108 J

Convert the value into engineering notation using expression equation (2) as follows,

389,589,000 J=389.589000×106 J=389.589×106 J (3)

Consider the SI prefixes.

1 Mega=1 M=106

Convert the standard value into SI prefixes using the equation (3).

389,589,000 J=389.589×(1 M) J {∵1 Mega=1 M=106}=389.589 MJ

Conclusion:

Hence, the given standard value 389,589,000 J is expressed in the appropriate scientific notation, engineering notation and with SI prefixes as follows.

Standard	Scientific	Engineering	With Prefix
389,589,000 joules [J]	3⋅89589×108 J	389.589×106 J	389.589 MJ

(b)

Expert Solution

To determine

Express the given standard value 0.0000000008 Pa using an appropriate scientific notation, engineering notation and SI prefix.

Answer to Problem 1ICA

The given standard value 0.0000000008 Pa is expressed in appropriate scientific notation, engineering notation and with SI prefix as follows.

Standard	Scientific	Engineering	With Prefix
0.0000000008 pascals [Pa]	8.0×10−10 Pa	800.0×10−12 Pa	800.0 pPa

Explanation of Solution

Given data:

The standard value is 0.0000000008 Pa.

Calculation:

The given standard value in Pascal is,

Standard value=0.0000000008 Pa

Convert the value into scientific notation using the expression in equation (1) as follows,

0.0000000008 Pa=8.0×10−10 Pa

Convert the value into engineering notation using expression in equation (2) as follows,

0.0000000008 Pa=800.0×10−12 Pa (4)

Consider the SI prefixes.

1 pico=1 p=10−12

Convert the standard value into SI prefixes using equation (4).

0.0000000008 Pa=800.0×10−12 Pa=800.0 (1 p)Pa {∵1 pico=1 p=10−12}=800.0 pPa

Conclusion:

Hence, the given standard value 0.0000000008 Pa is expressed in the appropriate scientific notation, engineering notation and with SI prefix as follows.

Standard	Scientific	Engineering	With Prefix
0.0000000008 pascals [Pa]	8.0×10−10 Pa	800.0×10−12 Pa	800.0 pPa

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

03:55

Answer 3

Textbook Question

Chapter 7, Problem 1ICA

Express the following values using scientific notation, engineering notation, and using an appropriate SI prefix such that there are only one, two, or three digits shown to the left of the decimal

Standard	Scientific	Engineering	With Prefix
(a) 389,589,000 joules [J]
(b) 0.0000000008 pascals [Pa]

(a)

Expert Solution

To determine

Express the given standard value 389,589,000 J using an appropriate scientific notation, engineering notation and SI prefix.

Answer to Problem 1ICA

The given standard value 389,589,000 J is expressed in appropriate scientific notation, engineering notation and with SI prefix as follows.

Standard	Scientific	Engineering	With Prefix
389,589,000 joules [J]	3⋅89589×108 J	389.589×106 J	389.589 MJ

Explanation of Solution

Given data:

The standard value is 389,589,000 J.

Formula used:

Consider the general Scientific notation as,

#.###×10N (1)

Here,

# is single digit to the left of the decimal point which is the most significant nonzero digit,

N is an integer, and

10N is provide to locate the true position of the decimal point.

Consider the general Engineering notation as,

###.###×10M (2)

Here,

M is an integer multiple of 3, and

# is the number of digits to the left of the decimal point which is one, two, or three as required to yield a power of 10 that is indeed a multiple of 3.

Calculation:

The given standard value in Joules is,

Standard value=389,589,000 J

Convert the value into scientific notation using the expression in equation (1) as follows,

389,589,000 J=3.89589000×108 J=3.89589×108 J

Convert the value into engineering notation using expression equation (2) as follows,

389,589,000 J=389.589000×106 J=389.589×106 J (3)

Consider the SI prefixes.

1 Mega=1 M=106

Convert the standard value into SI prefixes using the equation (3).

389,589,000 J=389.589×(1 M) J {∵1 Mega=1 M=106}=389.589 MJ

Conclusion:

Hence, the given standard value 389,589,000 J is expressed in the appropriate scientific notation, engineering notation and with SI prefixes as follows.

Standard	Scientific	Engineering	With Prefix
389,589,000 joules [J]	3⋅89589×108 J	389.589×106 J	389.589 MJ

(b)

Expert Solution

To determine

Express the given standard value 0.0000000008 Pa using an appropriate scientific notation, engineering notation and SI prefix.

Answer to Problem 1ICA

The given standard value 0.0000000008 Pa is expressed in appropriate scientific notation, engineering notation and with SI prefix as follows.

Standard	Scientific	Engineering	With Prefix
0.0000000008 pascals [Pa]	8.0×10−10 Pa	800.0×10−12 Pa	800.0 pPa

Explanation of Solution

Given data:

The standard value is 0.0000000008 Pa.

Calculation:

The given standard value in Pascal is,

Standard value=0.0000000008 Pa

Convert the value into scientific notation using the expression in equation (1) as follows,

0.0000000008 Pa=8.0×10−10 Pa

Convert the value into engineering notation using expression in equation (2) as follows,

0.0000000008 Pa=800.0×10−12 Pa (4)

Consider the SI prefixes.

1 pico=1 p=10−12

Convert the standard value into SI prefixes using equation (4).

0.0000000008 Pa=800.0×10−12 Pa=800.0 (1 p)Pa {∵1 pico=1 p=10−12}=800.0 pPa

Conclusion:

Hence, the given standard value 0.0000000008 Pa is expressed in the appropriate scientific notation, engineering notation and with SI prefix as follows.

Standard	Scientific	Engineering	With Prefix
0.0000000008 pascals [Pa]	8.0×10−10 Pa	800.0×10−12 Pa	800.0 pPa

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

03:55

Answer 4

Textbook Question

Chapter 7, Problem 1ICA

Express the following values using scientific notation, engineering notation, and using an appropriate SI prefix such that there are only one, two, or three digits shown to the left of the decimal

Standard	Scientific	Engineering	With Prefix
(a) 389,589,000 joules [J]
(b) 0.0000000008 pascals [Pa]

(a)

Expert Solution

To determine

Express the given standard value 389,589,000 J using an appropriate scientific notation, engineering notation and SI prefix.

Answer to Problem 1ICA

The given standard value 389,589,000 J is expressed in appropriate scientific notation, engineering notation and with SI prefix as follows.

Standard	Scientific	Engineering	With Prefix
389,589,000 joules [J]	3⋅89589×108 J	389.589×106 J	389.589 MJ

Explanation of Solution

Given data:

The standard value is 389,589,000 J.

Formula used:

Consider the general Scientific notation as,

#.###×10N (1)

Here,

# is single digit to the left of the decimal point which is the most significant nonzero digit,

N is an integer, and

10N is provide to locate the true position of the decimal point.

Consider the general Engineering notation as,

###.###×10M (2)

Here,

M is an integer multiple of 3, and

# is the number of digits to the left of the decimal point which is one, two, or three as required to yield a power of 10 that is indeed a multiple of 3.

Calculation:

The given standard value in Joules is,

Standard value=389,589,000 J

Convert the value into scientific notation using the expression in equation (1) as follows,

389,589,000 J=3.89589000×108 J=3.89589×108 J

Convert the value into engineering notation using expression equation (2) as follows,

389,589,000 J=389.589000×106 J=389.589×106 J (3)

Consider the SI prefixes.

1 Mega=1 M=106

Convert the standard value into SI prefixes using the equation (3).

389,589,000 J=389.589×(1 M) J {∵1 Mega=1 M=106}=389.589 MJ

Conclusion:

Hence, the given standard value 389,589,000 J is expressed in the appropriate scientific notation, engineering notation and with SI prefixes as follows.

Standard	Scientific	Engineering	With Prefix
389,589,000 joules [J]	3⋅89589×108 J	389.589×106 J	389.589 MJ

(b)

Expert Solution

To determine

Express the given standard value 0.0000000008 Pa using an appropriate scientific notation, engineering notation and SI prefix.

Answer to Problem 1ICA

The given standard value 0.0000000008 Pa is expressed in appropriate scientific notation, engineering notation and with SI prefix as follows.

Standard	Scientific	Engineering	With Prefix
0.0000000008 pascals [Pa]	8.0×10−10 Pa	800.0×10−12 Pa	800.0 pPa

Explanation of Solution

Given data:

The standard value is 0.0000000008 Pa.

Calculation:

The given standard value in Pascal is,

Standard value=0.0000000008 Pa

Convert the value into scientific notation using the expression in equation (1) as follows,

0.0000000008 Pa=8.0×10−10 Pa

Convert the value into engineering notation using expression in equation (2) as follows,

0.0000000008 Pa=800.0×10−12 Pa (4)

Consider the SI prefixes.

1 pico=1 p=10−12

Convert the standard value into SI prefixes using equation (4).

0.0000000008 Pa=800.0×10−12 Pa=800.0 (1 p)Pa {∵1 pico=1 p=10−12}=800.0 pPa

Conclusion:

Hence, the given standard value 0.0000000008 Pa is expressed in the appropriate scientific notation, engineering notation and with SI prefix as follows.

Standard	Scientific	Engineering	With Prefix
0.0000000008 pascals [Pa]	8.0×10−10 Pa	800.0×10−12 Pa	800.0 pPa

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

03:55

Answer 5

Textbook Question

Answer 6

Textbook Question

Answer 7

(a)

Expert Solution

To determine

Express the given standard value 389,589,000 J using an appropriate scientific notation, engineering notation and SI prefix.

Answer to Problem 1ICA

The given standard value 389,589,000 J is expressed in appropriate scientific notation, engineering notation and with SI prefix as follows.

Standard	Scientific	Engineering	With Prefix
389,589,000 joules [J]	3⋅89589×108 J	389.589×106 J	389.589 MJ

Explanation of Solution

Given data:

The standard value is 389,589,000 J.

Formula used:

Consider the general Scientific notation as,

#.###×10N (1)

Here,

# is single digit to the left of the decimal point which is the most significant nonzero digit,

N is an integer, and

10N is provide to locate the true position of the decimal point.

Consider the general Engineering notation as,

###.###×10M (2)

Here,

M is an integer multiple of 3, and

# is the number of digits to the left of the decimal point which is one, two, or three as required to yield a power of 10 that is indeed a multiple of 3.

Calculation:

The given standard value in Joules is,

Standard value=389,589,000 J

Convert the value into scientific notation using the expression in equation (1) as follows,

389,589,000 J=3.89589000×108 J=3.89589×108 J

Convert the value into engineering notation using expression equation (2) as follows,

389,589,000 J=389.589000×106 J=389.589×106 J (3)

Consider the SI prefixes.

1 Mega=1 M=106

Convert the standard value into SI prefixes using the equation (3).

389,589,000 J=389.589×(1 M) J {∵1 Mega=1 M=106}=389.589 MJ

Conclusion:

Hence, the given standard value 389,589,000 J is expressed in the appropriate scientific notation, engineering notation and with SI prefixes as follows.

Standard	Scientific	Engineering	With Prefix
389,589,000 joules [J]	3⋅89589×108 J	389.589×106 J	389.589 MJ

(b)

Expert Solution

To determine

Express the given standard value 0.0000000008 Pa using an appropriate scientific notation, engineering notation and SI prefix.

Answer to Problem 1ICA

The given standard value 0.0000000008 Pa is expressed in appropriate scientific notation, engineering notation and with SI prefix as follows.

Standard	Scientific	Engineering	With Prefix
0.0000000008 pascals [Pa]	8.0×10−10 Pa	800.0×10−12 Pa	800.0 pPa

Explanation of Solution

Given data:

The standard value is 0.0000000008 Pa.

Calculation:

The given standard value in Pascal is,

Standard value=0.0000000008 Pa

Convert the value into scientific notation using the expression in equation (1) as follows,

0.0000000008 Pa=8.0×10−10 Pa

Convert the value into engineering notation using expression in equation (2) as follows,

0.0000000008 Pa=800.0×10−12 Pa (4)

Consider the SI prefixes.

1 pico=1 p=10−12

Convert the standard value into SI prefixes using equation (4).

0.0000000008 Pa=800.0×10−12 Pa=800.0 (1 p)Pa {∵1 pico=1 p=10−12}=800.0 pPa

Conclusion:

Hence, the given standard value 0.0000000008 Pa is expressed in the appropriate scientific notation, engineering notation and with SI prefix as follows.

Standard	Scientific	Engineering	With Prefix
0.0000000008 pascals [Pa]	8.0×10−10 Pa	800.0×10−12 Pa	800.0 pPa

Answer 8

(a)

Expert Solution

To determine

Express the given standard value 389,589,000 J using an appropriate scientific notation, engineering notation and SI prefix.

Answer to Problem 1ICA

The given standard value 389,589,000 J is expressed in appropriate scientific notation, engineering notation and with SI prefix as follows.

Standard	Scientific	Engineering	With Prefix
389,589,000 joules [J]	3⋅89589×108 J	389.589×106 J	389.589 MJ

Explanation of Solution

Given data:

The standard value is 389,589,000 J.

Formula used:

Consider the general Scientific notation as,

#.###×10N (1)

Here,

# is single digit to the left of the decimal point which is the most significant nonzero digit,

N is an integer, and

10N is provide to locate the true position of the decimal point.

Consider the general Engineering notation as,

###.###×10M (2)

Here,

M is an integer multiple of 3, and

# is the number of digits to the left of the decimal point which is one, two, or three as required to yield a power of 10 that is indeed a multiple of 3.

Calculation:

The given standard value in Joules is,

Standard value=389,589,000 J

Convert the value into scientific notation using the expression in equation (1) as follows,

389,589,000 J=3.89589000×108 J=3.89589×108 J

Convert the value into engineering notation using expression equation (2) as follows,

389,589,000 J=389.589000×106 J=389.589×106 J (3)

Consider the SI prefixes.

1 Mega=1 M=106

Convert the standard value into SI prefixes using the equation (3).

389,589,000 J=389.589×(1 M) J {∵1 Mega=1 M=106}=389.589 MJ

Conclusion:

Hence, the given standard value 389,589,000 J is expressed in the appropriate scientific notation, engineering notation and with SI prefixes as follows.

Standard	Scientific	Engineering	With Prefix
389,589,000 joules [J]	3⋅89589×108 J	389.589×106 J	389.589 MJ

Answer 9

(a)

Expert Solution

Answer 10

(a)

Expert Solution

Answer 11

Expert Solution

Answer 12

To determine

Express the given standard value 389,589,000 J using an appropriate scientific notation, engineering notation and SI prefix.

Answer 13

Answer to Problem 1ICA

The given standard value 389,589,000 J is expressed in appropriate scientific notation, engineering notation and with SI prefix as follows.

Standard	Scientific	Engineering	With Prefix
389,589,000 joules [J]	3⋅89589×108 J	389.589×106 J	389.589 MJ

Answer 14

Explanation of Solution

Given data:

The standard value is 389,589,000 J.

Formula used:

Consider the general Scientific notation as,

#.###×10N (1)

Here,

# is single digit to the left of the decimal point which is the most significant nonzero digit,

N is an integer, and

10N is provide to locate the true position of the decimal point.

Consider the general Engineering notation as,

###.###×10M (2)

Here,

M is an integer multiple of 3, and

# is the number of digits to the left of the decimal point which is one, two, or three as required to yield a power of 10 that is indeed a multiple of 3.

Calculation:

The given standard value in Joules is,

Standard value=389,589,000 J

Convert the value into scientific notation using the expression in equation (1) as follows,

389,589,000 J=3.89589000×108 J=3.89589×108 J

Convert the value into engineering notation using expression equation (2) as follows,

389,589,000 J=389.589000×106 J=389.589×106 J (3)

Consider the SI prefixes.

1 Mega=1 M=106

Convert the standard value into SI prefixes using the equation (3).

389,589,000 J=389.589×(1 M) J {∵1 Mega=1 M=106}=389.589 MJ

Conclusion:

Hence, the given standard value 389,589,000 J is expressed in the appropriate scientific notation, engineering notation and with SI prefixes as follows.

Standard	Scientific	Engineering	With Prefix
389,589,000 joules [J]	3⋅89589×108 J	389.589×106 J	389.589 MJ

Answer 15

(b)

Expert Solution

To determine

Express the given standard value 0.0000000008 Pa using an appropriate scientific notation, engineering notation and SI prefix.

Answer to Problem 1ICA

The given standard value 0.0000000008 Pa is expressed in appropriate scientific notation, engineering notation and with SI prefix as follows.

Standard	Scientific	Engineering	With Prefix
0.0000000008 pascals [Pa]	8.0×10−10 Pa	800.0×10−12 Pa	800.0 pPa

Explanation of Solution

Given data:

The standard value is 0.0000000008 Pa.

Calculation:

The given standard value in Pascal is,

Standard value=0.0000000008 Pa

Convert the value into scientific notation using the expression in equation (1) as follows,

0.0000000008 Pa=8.0×10−10 Pa

Convert the value into engineering notation using expression in equation (2) as follows,

0.0000000008 Pa=800.0×10−12 Pa (4)

Consider the SI prefixes.

1 pico=1 p=10−12

Convert the standard value into SI prefixes using equation (4).

0.0000000008 Pa=800.0×10−12 Pa=800.0 (1 p)Pa {∵1 pico=1 p=10−12}=800.0 pPa

Conclusion:

Hence, the given standard value 0.0000000008 Pa is expressed in the appropriate scientific notation, engineering notation and with SI prefix as follows.

Standard	Scientific	Engineering	With Prefix
0.0000000008 pascals [Pa]	8.0×10−10 Pa	800.0×10−12 Pa	800.0 pPa

Answer 16

(b)

Expert Solution

Answer 17

(b)

Expert Solution

Answer 18

Expert Solution

Answer 19

To determine

Express the given standard value 0.0000000008 Pa using an appropriate scientific notation, engineering notation and SI prefix.

Answer 20

Answer to Problem 1ICA

The given standard value 0.0000000008 Pa is expressed in appropriate scientific notation, engineering notation and with SI prefix as follows.

Standard	Scientific	Engineering	With Prefix
0.0000000008 pascals [Pa]	8.0×10−10 Pa	800.0×10−12 Pa	800.0 pPa

Answer 21

Explanation of Solution

Given data:

The standard value is 0.0000000008 Pa.

Calculation:

The given standard value in Pascal is,

Standard value=0.0000000008 Pa

Convert the value into scientific notation using the expression in equation (1) as follows,

0.0000000008 Pa=8.0×10−10 Pa

Convert the value into engineering notation using expression in equation (2) as follows,

0.0000000008 Pa=800.0×10−12 Pa (4)

Consider the SI prefixes.

1 pico=1 p=10−12

Convert the standard value into SI prefixes using equation (4).

0.0000000008 Pa=800.0×10−12 Pa=800.0 (1 p)Pa {∵1 pico=1 p=10−12}=800.0 pPa

Conclusion:

Hence, the given standard value 0.0000000008 Pa is expressed in the appropriate scientific notation, engineering notation and with SI prefix as follows.