Chapter 7, Problem 43A

To determine

The gravitation force between two balls.

Answer to Problem 43A

  $8.00\times {10}^{-10}\text{N}$

Explanation of Solution

Given:

The mass of the balls are $8\text{kg and 6}.0\text{kg}$ , respectively.

Distance between balls is 2.0 m.

Formula used:

Gravitational force:

  $F=\frac{G{m}_1{m}_2}{r^2}$

Where, $G$ is the gravitational constant, $m_1$ and $m_2$ are the masses, and $r$ is the distance between the masses.

Calculation:

The value of gravitational constant is:

  $G=6.67\times {10}^{-11}\text{N}{\text{.m}}^{\text{2}}{\text{/kg}}^{\text{2}}$

Then using the given values of mass of the balls and the distance between them, the gravitational force between the balls will be,

  $\begin{array}{c}F=\frac{Gmm}{r^2}\\ =\frac{6.67\times {10}^{-11}\times 8\times 6}{{\left(2\right)}^2}\\ =8.00\times {10}^{-10}\text{N}\end{array}$

Conclusion:

Thus, the gravitational force between the balls is $8.00\times {10}^{-10}\text{N}$ .