![Glencoe Physics: Principles and Problems, Student Edition](https://www.bartleby.com/isbn_cover_images/9780078807213/9780078807213_largeCoverImage.gif)
Concept explainers
To explain: The reason for acting a force on Moon according to Newton.
![Check Mark](/static/check-mark.png)
Explanation of Solution
Introduction:
Gravitational force:
Every object in the universe having some mass pull other object. The force is called gravitational pull or gravitational force.
The size of pull depends upon the masses of the objects and the distance between them.
The gravitational force is given by,
Where,
According to Newton’s law of gravitation, there must be a gravitational force between the earth and the moon. It means the moon and the earth should have collided or moon should have fall down on earth. But nothing happened.
It means there is some other force which keeps the moon from falling dawn.
Since the moon is revolving and if there is no gravitational force present, the moon can go tangentially in a straight line.
So, the gravitational force holds the moon around earth.
Hence, there are forces acting on the moon.
Chapter 7 Solutions
Glencoe Physics: Principles and Problems, Student Edition
Additional Science Textbook Solutions
Chemistry & Chemical Reactivity
Human Anatomy & Physiology (2nd Edition)
Microbiology: An Introduction
Organic Chemistry (8th Edition)
Cosmic Perspective Fundamentals
College Physics: A Strategic Approach (3rd Edition)
- Please solve and answer this problem correctly please. Thank you!!arrow_forwardPlease solve and answer this problem correctly please. Thank you!!arrow_forwarda) Use the node-voltage method to find v1, v2, and v3 in the circuit in Fig. P4.14. b) How much power does the 40 V voltage source deliver to the circuit? Figure P4.14 302 202 w w + + + 40 V V1 80 Ω 02 ΣΑΩ 28 A V3 + w w 102 202arrow_forward
- Please solve and answer this problem correctly please. Thank you!!arrow_forwardYou're on an interplanetary mission, in an orbit around the Sun. Suppose you make a maneuver that brings your perihelion in closer to the Sun but leaves your aphelion unchanged. Then you must have Question 2 options: sped up at perihelion sped up at aphelion slowed down at perihelion slowed down at aphelionarrow_forwardThe force of the quadriceps (Fq) and force of the patellar tendon (Fp) is identical (i.e., 1000 N each). In the figure below angle in blue is Θ and the in green is half Θ (i.e., Θ/2). A) Calculate the patellar reaction force (i.e., R resultant vector is the sum of the horizontal component of the quadriceps and patellar tendon force) at the following joint angles: you need to provide a diagram showing the vector and its components for each part. a1) Θ = 160 degrees, a2) Θ = 90 degrees. NOTE: USE ONLY TRIGNOMETRIC FUNCTIONS (SIN/TAN/COS, NO LAW OF COSINES, NO COMPLICATED ALGEBRAIC EQUATIONS OR ANYTHING ELSE, ETC. Question A has 2 parts!arrow_forward
- The force of the quadriceps (Fq) and force of the patellar tendon (Fp) is identical (i.e., 1000 N each). In the figure below angle in blue is Θ and the in green is half Θ (i.e., Θ/2). A) Calculate the patellar reaction force (i.e., R resultant vector is the sum of the horizontal component of the quadriceps and patellar tendon force) at the following joint angles: you need to provide a diagram showing the vector and its components for each part. a1) Θ = 160 degrees, a2) Θ = 90 degrees. NOTE: USE DO NOT USE LAW OF COSINES, NO COMPLICATED ALGEBRAIC EQUATIONS OR ANYTHING ELSE, ETC. Question A has 2 parts!arrow_forwardNo chatgpt pls will upvotearrow_forwardThe force of the quadriceps (Fq) and force of the patellar tendon (Fp) is identical (i.e., 1000 N each). In the figure below angle in blue is Θ and the in green is half Θ (i.e., Θ/2). A) Calculate the patellar reaction force (i.e., R resultant vector is the sum of the horizontal component of the quadriceps and patellar tendon force) at the following joint angles: you need to provide a diagram showing the vector and its components for each part. a1) Θ = 160 degrees, a2) Θ = 90 degrees. NOTE: USE ONLY TRIGNOMETRIC FUNCTIONS (SIN/TAN/COS, NO LAW OF COSINES, NO COMPLICATED ALGEBRAIC EQUATIONS OR ANYTHING ELSE, ETC. Question A has 2 parts!arrow_forward
- College PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage LearningUniversity Physics (14th Edition)PhysicsISBN:9780133969290Author:Hugh D. Young, Roger A. FreedmanPublisher:PEARSONIntroduction To Quantum MechanicsPhysicsISBN:9781107189638Author:Griffiths, David J., Schroeter, Darrell F.Publisher:Cambridge University Press
- Physics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningLecture- Tutorials for Introductory AstronomyPhysicsISBN:9780321820464Author:Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina BrissendenPublisher:Addison-WesleyCollege Physics: A Strategic Approach (4th Editio...PhysicsISBN:9780134609034Author:Randall D. Knight (Professor Emeritus), Brian Jones, Stuart FieldPublisher:PEARSON
![Text book image](https://www.bartleby.com/isbn_cover_images/9781305952300/9781305952300_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9780133969290/9780133969290_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781107189638/9781107189638_smallCoverImage.jpg)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781337553278/9781337553278_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9780321820464/9780321820464_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9780134609034/9780134609034_smallCoverImage.gif)