EBK BIOLOGY
5th Edition
ISBN: 8220100667978
Author: Maier
Publisher: PEARSON
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Chapter 7, Problem 3CTS
Summary Introduction
To write:
There should be a reduction in
How the other genetic disorder's treatment is different from this?
Introduction:
The genes are responsible for the different types of characters in humans. Some of the conditions are completely determined by the genes and some of the traits are affected by both genes and the environment.
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YOUR SISTER DIED FROM TAY-SACHS DISEASE, INHERITED AS A RECESSIVE ALLELE (t). you're married and planning to start your family. you're worried about the disease and decide to have genetic testing to see if you or your spouse is a carrier of the tay-sachs allele. the test results show that you're a carrier of the allele, but your spouse isn't. what is the probability that you and your spouse will have a child with tay-sachs disease? show your work.
Phenylketonuria (PKU) is a human hereditary disease resulting from the inability of the body to process the chemical phenylalanine, which is contained in the protein we eat. PKU is manifest in early infancy and, if it remains untreated, generally leads to cognitive impairment. PKU is caused by a recessive allele with simple Mendelian inheritance. A couple intends to have children but consults a genetic counselor because the man has a sister with PKU and the woman has a brother with PKU. There are no other known cases in their families. They ask the genetic counselor to determine the probability that their first child will have PKU. What is this probability?
Huntington's disease is an autosomal dominant disorder caused by a gradual build up of a misfolded protein in the brain. a 45 year old man finds out that he has Huntington's which his father died from but he knows his mother never developed the disease and lived to be 90. He is married with one daughter and his wife doesn't have the disease. What are the chances that his daughter develop Huntington? 25%, 50%, 75%, 100% or cannot tell from the information
Chapter 7 Solutions
EBK BIOLOGY
Ch. 7 - What is the relationship between genotype and...Ch. 7 - Prob. 2LTBCh. 7 - Prob. 3LTBCh. 7 - Prob. 4LTBCh. 7 - Prob. 5LTBCh. 7 - Scientists have recently developed a process by...Ch. 7 - What is the physical basis for the independent...Ch. 7 - Prob. 8LTBCh. 7 - Prob. 9LTBCh. 7 - Prob. 10LTB
Ch. 7 - Prob. 1GPCh. 7 - Prob. 2GPCh. 7 - Prob. 3GPCh. 7 - Prob. 4GPCh. 7 - Pfeiffer syndrome is a dominant genetic disease...Ch. 7 - Prob. 6GPCh. 7 - A cross between a pea plant that produces round...Ch. 7 - Prob. 8GPCh. 7 - The allele BRCA2 was identified in families with...Ch. 7 - Two parents both have brown eyes, but they have...Ch. 7 - Prob. 2AAATBCh. 7 - Prob. 3AAATBCh. 7 - Prob. 1CTSCh. 7 - Prob. 2CTSCh. 7 - Prob. 3CTS
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- Cystic fibrosis is an autosomal disease that mainly affects the white population, and 1 in 20 whites are heterozygotes. Genetic testing can diagnose heterozygotes. Should a genetic screening program for cystic fibrosis be instituted? Should the federal government fund it? Should the program be voluntary or mandatory, and why?arrow_forwardA male dog is a carrier for the autosomal recessive disorders centronuclear myopathy (Y/y) and von Willebrand disease (D/d). The male dog mates with a female dog that is homozygous recessive for both traits (this female dog has both disorders). How many puppies in an 8-puppy litter would you expect to have centronuclear myopathy and NOT have von Willebrand disease? 1 2 3 4arrow_forwardThe gene for red-green colour vision is carried on the X chromosome. If the gene is faulty, colour blindness (XP) will occur in males. Red-green colour blindness occurs in about 8% of males but in less than 1% of females. Parents Non colour blind female Colour blind male A colour blind man has children with a woman who is not colour blind. The couple have four children. Their phenotypes are: 1 non colour blind son, 1 colour blind son, 2 non colour blind daughters. Describe the mother's: (a) Genotype: (b) Phenotype: Gameles Possible (c) Identify the genotype not possessed by any of the children: fertilizations, O 2012-2014 BIOZONE International ISBN: 978-1-927173-93-0 Photocopying Prohibited WEB 93 APP o 耳arrow_forward
- If one person with the trait of Huntington's disease (H h) has 2 children with a partner who does not have a trait for the disease what is the chance that both children won't have the disease?arrow_forwardA certain type of deafness in humans is inherited as an X-linked recessive trait. A man with this type of deafness married a normal woman, and they are expecting a child. They find out that they are distantly related. Part of the family tree is shown here.How would you advise the parents about the probability of their child being a deaf boy, a deaf girl, a normal boy, or a normal girl? Be sure to state any assumptions that you make.arrow_forwardWhat’s the probability of receiving a particular gene? The Punnett Square is a tool that allows you to see the different gene combinations that are possible when two parents of any species create offspring.arrow_forward
- The father of three sons and two daughters begins to show symptoms of Huntington disease. What is the probability that Sam, the man’s second oldest son (II-2), will suffer from the disease if he lives a normal life span? Sam’s mother and her ancestors do not have the disease. Sam's father was adopted, so we do not know his biological family history for Huntington disease. Explore all possible outcomes for Sam and explain your reasoning. What about the risk to Sam's sisters? Would that be the same or not?arrow_forwardHuntington's disease is an inherited autosomal dominant disorder that can affect both men and women. Imagine a couple has had seven children, and later in life, the husband develops Huntington's disease. He is tested and it is discovered he is heterozygous for the disease allele, Hh. The wife is also genetically tested for the Huntington's disease allele, and her test results show she is unaffected, hh. What is the percent probability that the first child of this couple will have Huntington's disease? probability: % What is the percent probability that two of the seven children will have Huntington's disease? probability: %arrow_forwardA type of red-green colorblindness is inherited recessively on the X chromosome. A woman who is a carrier had children with a male that is not affected by the disease. Show your answers with the use of a Punnett square • What is the probability (% or likelihood) that a child is affected by the disease? • What is the probability (% or likelihood) that a son is a carrier? (Careful!) • Is there a chance that a girl of the couple is affected by the disease?arrow_forward
- Red-green color blindness is inherited as an X-linked recessive (Xc). If a color-blind man marries a woman who is heterozygous for normal vision, what would be the expected phenotypes of their children with reference to this character? In your answer, specify in your phenotype descriptions the gender of the children. (For example, don’t just say 75% of the children would be colorblind – you would instead say 100 % of the daughters would be colorblind and 50% of the sons would be colorblind. Note that this is not a correct answer; it is just to give you an idea of how to explain the correct phenotypes of the cross.)___arrow_forwardage An extra finger in humans is rare but is due to a dominant gene. When one parent is normal and the other parent has an extra finger but is heterozygous for the trait, what is the probability that the first child will have an extra finger? - /mod/quiz/attempt.php?attempt=1173673&cmid=3837312&page=11# Select one: O a. 25% O b. 50% O c. 75% O d. 0% O e. 100% @ 2 W # 3 E с $ 4 R G Search or type URL % 5 T MacBook Pro 6 Y & 7 ☆ U * 8 ( 9 F ) 0 0 Next page P (3) BO 11arrow_forwardWhich of the following genotype(s) must a female child have in order to be color blind? XNXN XNXn XnXn XNY XnY (XN represents the normal color vision allele. Xn represents the color-blindness allele. Y represents the Y chromosome, which does not carry the color-vision gene.) Which of the following genotype(s) must a color-blind male have? Explain your rationale. XNXN XNXn XnXn XNY XnY (XN represents the normal color vision allele. Xn represents the color-blindness allele. Y represents the Y chromosome, which does not carry the color-vision gene.)arrow_forward
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