Chapter 7, Problem 28A

Interpretation Introduction

Interpretation:

The unbalanced chemical equation corresponding to the reaction between lead sulphide with oxygen needs to be presented.

Concept Introduction:

• A chemical reaction is expressed as a chemical equation having reactants and products on left and right side of the reaction arrow respectively.

  $\text{Reactants }\to \text{ Products}$

• It also gives the physical state (solid (s), liquid (l), gas (g) and the amount of reactants and products involved in the reaction.

Answer to Problem 28A

  ${\text{PbS (s) + O}}_2\text{(g) }\stackrel{\text{heat}}{\to }{\text{ PbO(s) + SO}}_2\text{(g)}$

Explanation of Solution

The given process involves the reaction between lead sulphide solid and oxygen gas to produce lead oxide and sulfur dioxide gas. The reactants and products are:

Reactants:

  $\begin{array}{l}\text{Lead sulfide, solid - PbS }(\text{s})\\ {\text{Oxygen, gas - O}}_2\text{ (g)}\end{array}$

Products:

  $\begin{array}{l}\text{Lead oxide, solid - PbO (s)}\\ {\text{Sulfur dioxide, gas - SO}}_{\text{2}}\text{ (g)}\end{array}$

Unbalanced equation:

  ${\text{PbS (s) + O}}_2\text{(g) }\stackrel{\text{heat}}{\to }{\text{ PbO(s) + SO}}_2\text{(g)}$

Conclusion

Therefore, the unbalanced reaction will have lead sulphide solid and oxygen gas as the reactants with lead oxide and sulfur dioxide gas as products.