Chapter 7, Problem 21A

Interpretation Introduction

Interpretation:

The unbalanced chemical equation corresponding to the combustion of hydrogen sulphide gas needs to be presented.

Concept Introduction:

• A chemical reaction is expressed as a chemical equation having reactants and products on left and right side of the reaction arrow respectively.

  $\text{Reactants }\to \text{ Products}$

• It also gives the physical state (solid (s), liquid (l), gas (g)) and the amount of reactants and products involved in the reaction.

Answer to Problem 21A

  ${\text{H}}_{\text{2}}{\text{S (g) + O}}_{\text{2}}\text{(g) }\stackrel{\text{heat}}{\to }{\text{ SO}}_2{\text{ (g) + H}}_{\text{2}}\text{O(g)}$

Explanation of Solution

The given process involves the reaction between hydrogen sulphide gas and oxygen gas in the presence of heat to produce sulfur dioxide gas and water vapor. The reactants and products are:

Reactants:

  $\begin{array}{l}{\text{Hydrogen sulfide, gas - H}}_{\text{2}}\text{S }(\text{g})\\ {\text{Oxygen, gas - O}}_{\text{2}}\text{ (g)}\end{array}$

Products:

  $\begin{array}{l}{\text{Sulfur dioxide, gas - SO}}_2\text{(g)}\\ {\text{Water vapor - H}}_{\text{2}}\text{O (g)}\end{array}$

Unbalanced equation:

  ${\text{H}}_{\text{2}}{\text{S (g) + O}}_{\text{2}}\text{(g) }\stackrel{\text{heat}}{\to }{\text{ SO}}_2{\text{ (g) + H}}_{\text{2}}\text{O(g)}$

Conclusion

Therefore, the unbalanced reaction will have hydrogen sulphide and oxygen gas as the reactants with sulfur dioxide gas and water vapor as the products.