Chapter 7, Problem 22A

Interpretation Introduction

Interpretation:

The unbalanced chemical equation corresponding to the combustion of acetylene gas needs to be presented

Concept Introduction:

• A chemical reaction is expressed as a chemical equation having reactants and products on left and right side of the reaction arrow respectively.

  $\text{Reactants }\to \text{ Products}$

• It also gives the physical state (solid (s), liquid (l), gas (g)) and the amount of reactants and products involved in the reaction.

Answer to Problem 22A

  ${\text{C}}_{\text{2}}{\text{H}}_{\text{2}}{\text{(g) + O}}_{\text{2}}\text{(g) }\to {\text{ CO}}_2{\text{ (g) + H}}_{\text{2}}\text{O(g)}$

Explanation of Solution

The given process involves the reaction between acetylene gas and oxygen gas to produce carbon dioxide gas and water vapor. The reactants and products are:

Reactants:

  $\begin{array}{l}{\text{Acetylene, gas - C}}_{\text{2}}{\text{H}}_{\text{2}}(\text{g})\\ {\text{Oxygen, gas - O}}_{\text{2}}\text{ (g)}\end{array}$

Products:

  $\begin{array}{l}{\text{Carbon dioxide, gas - CO}}_2\text{(g)}\\ {\text{Water vapor - H}}_{\text{2}}\text{O (g)}\end{array}$

Unbalanced equation:

  ${\text{C}}_{\text{2}}{\text{H}}_{\text{2}}{\text{(g) + O}}_{\text{2}}\text{(g) }\to {\text{ CO}}_2{\text{ (g) + H}}_{\text{2}}\text{O(g)}$

Conclusion

Therefore the unbalanced reaction will have acetylene and oxygen gas as the reactants with carbon dioxide gas and water vapor as the products.