Horizons: Exploring the Universe (MindTap Course List)
14th Edition
ISBN: 9781305960961
Author: Michael A. Seeds, Dana Backman
Publisher: Cengage Learning
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Chapter 7, Problem 1LTL
To determine
Why the shape and extent of the glowing gases is observed to be different for each eclipse?
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Part 3
1. The diameter of the Sun is 1,391,400 km. The diameter of the Moon is 3,474.8 km. Find
the ratio, r= Dsa/Dsvan between the sizes.
2. From the point of view of an obs erver on Eanth (consider the Earth as a point-like object),
during the eclipse, the Moon covers the Sun exactly. Sketch a picture to illustrate this
fact. Use a nuler to get a straight line. Your drawing does not need to be in scale.
3. The Sun is 1 Astronomical Unit (AU) away from the Earth. Find the distance between the
Earth and the Moon in AU's using the ratio of similar triangles. Show your work.
DEM=
AU.
Convert this to kilometers. Use 1 AU = 149,600,000 km.
DEM =
km.
A distant galaxy has an apparent magnitude of 13 and is 5,000 kpc away. What is its absolute magnitude? (Round your answer to at least one decimal place.)
The difference in absolute magnitude between two objects viewed from the same distance is related to their fluxes by the flux-magnitude relation.
FA
= 2.51(MB - MA)
FB
How does the absolute magnitude of this galaxy compare to the Milky Way (M = -21)?
F,
distant galaxy
FMilky Way
Chapter 7 Solutions
Horizons: Exploring the Universe (MindTap Course List)
Ch. 7 - Prob. 1RQCh. 7 - What evidence can you give that granulation is...Ch. 7 - Prob. 3RQCh. 7 - Prob. 4RQCh. 7 - Prob. 5RQCh. 7 - Prob. 6RQCh. 7 - Prob. 7RQCh. 7 - Prob. 8RQCh. 7 - Prob. 9RQCh. 7 - Prob. 10RQ
Ch. 7 - Prob. 11RQCh. 7 - How can solar flares affect Earth?Ch. 7 - Prob. 13RQCh. 7 - Prob. 14RQCh. 7 - Prob. 15RQCh. 7 - Prob. 16RQCh. 7 - Prob. 17RQCh. 7 - Prob. 18RQCh. 7 - Explain why the presence of spectral lines of a...Ch. 7 - What energy sources on Earth cannot be thought of...Ch. 7 - What would the spectrum of an auroral display look...Ch. 7 - Prob. 4DQCh. 7 - The radius of the Sun is 0.7 million km. Examine...Ch. 7 - Prob. 2PCh. 7 - Prob. 3PCh. 7 - If a sunspot has a temperature of 4200 K and the...Ch. 7 - How much energy is produced when the Sun converts...Ch. 7 - Prob. 6PCh. 7 - Prob. 7PCh. 7 - Prob. 8PCh. 7 - The United States consumes about 2.51019 J of...Ch. 7 - Prob. 10PCh. 7 - Prob. 1LTLCh. 7 - Prob. 2LTLCh. 7 - Prob. 3LTL
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- This photo shows the annular eclipse of May 30, 1984. How is it different from the annular eclipse shown in Figure 3-10c? Figure 310 (a) Because the angular diameter of the Moon and the Sun vary slightly, the disk of the Moon is sometimes too small to cover the disk of the Sun. (b) That means the umbra of the Moon does not reach Earth, and the eclipse is annular, meaning a ring ("annulus") of the Sun's disk can be seen around the Moon. (c) In this photograph of an annular eclipse in 1994, the dark disk of the Moon is almost exactly centered on the bright disk of the Sun.arrow_forwardConfirm that the angular diameter of the Sun of 1/2° corresponds to a linear diameter of 1.39 million km. Use the average distance of the Sun and Earth to derive the answer. (Hint: This can be solved using a trigonometric function.)arrow_forwardCalculate by how many times Betelgeuse is brighter than the Sun, if its parallax is 0.006 arcsec, and its apparent magnitude is m = +.5. Can you first use the parallax to calculate the distance and then use the magnitude-distance formula to find the absolute magnitude of Betelgeuse and finally, compare it to the absolute magnitude of the Sun which is -26,74 because other experts used other methods and the answer was not correct.arrow_forward
- -appendix C: radius of sun is 7 x 10^8 m -please solve this on a sheet of paper so it will be easier to understand.arrow_forwardIf you observed the Solar System from the nearest star (distance = 1.3 parsecs), what would the maximum angular separation be between Earth and the Sun? (Note: 1 pc is 2.1105 AU.) (Hint: Use the small-angle formula in Reasoning with Numbers 3-1.)arrow_forwardWhenever there is a total solar eclipse, you can see something like the image shown here. Explain why the shape and extent of the glowing gases are observed to be different for each eclipse.arrow_forward
- As observed from Earth, the Sun has an angular size of about 0.53o. From the observation, estimate the diameter of the Sun. How large in volume is the Sun when compared to Earth?arrow_forwardCalculate the total amount of radiative energy per second intercepted by Mars from the Sun using the flux of radiation from the Sun at Mars' orbital radius. Flux of radiation from the Sun at Mars' orbital radius is 597 W m-2. The luminosity of the Sun Ls = 3.8×1026 W. Mars orbits at a distance of 2.25×1011 m (1.5 AU) from the Sun. Note: Consider carefully the cross-sectional area Mars presents to the outwards flow of radiative energy when answering this question.arrow_forwardThe telescope and CCD camera described in question 2 are scheduled to observe the star cluster M67 at 22:00 GMT on 02/03/2022. Using Stellarium, determine whether or not this is a good time to observe the cluster. Choose the answer below that best matches your conclusions. a. No - the cluster is not visible from London at this date and time. b. The cluster is visible but the full Moon is close by and so will interfere with the observations. c. The cluster is visible but is very close to the horizon and so will be difficult to observe. d. The cluster M67 is never visible in the sky from London so we should abandon any plans to observe it. e. Yes this is a good time to observe the cluster as it is well placed in the sky for viewing and the moon is not visible.arrow_forward
- A solar eclipse is only visible over a narrow strip on the Earth's surface. This is most closely associated with: Select one alternative: The ways in which our view of the sky depends on latitude. The combination of the Earth's rotation on its axis and its movement around the sun. The elliptical nature of the moon's orbit. The perspective dependence associated with parallax. Solar eclipses are actually visible to everyone on the daylight side of the earth.arrow_forwardI need urgent answers on the photo provided here pls. Thank you so much.arrow_forward1 Solar constant, Sun, and the 10 pc distance! The luminosity of Sun is + 4- 1026 W - 4- 1033ergs-1, The Sun is located at a distance of m from the Earth. The Earth receives a radiant flux (above its atmosphere) of F = 1365W m- 2, also known as the solar constant. What would have been the Solar contact if the Sun was at a distance of 10 pc ? 1AU 1 1.5-+ 1011arrow_forward
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