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Concept explainers
(a)
Interpretation:
The name of the following molecule should be determined.
Concept Introduction:
Compounds consist of carbon and hydrogen is known as hydrocarbons.
Rules of naming
- First choose the longest continuous chain of carbon atoms having double bond known as parent chain.
- The numbering of parent chain should be done in a way that the double bond and substituents get the lowest number.
- The root name of the carbon chain is same as in case of
alkanes , but “−ane” ending is replaced by “−ene” - The appropriate name should be given to every alkyl group and denote its position on the parent chain with the number.
- The alkyl groups are written in alphabetical order.
(b)
Interpretation:
The name of the following molecule should be determined.
Concept Introduction:
Compounds consist of carbon and hydrogen is known as hydrocarbons. Unsaturated hydrocarbon having double bond is known as alkene having general molecular formula
Rules of naming alkenes are:
- First choose the longest continuous chain of carbon atoms having double bond known as parent chain.
- The numbering of parent chain should be done in a way that the double bond and substituents get the lowest number.
- The root name of the carbon chain is same as in case of alkanes, but “−ane” ending is replaced by “−ene”
- The appropriate name should be given to every alkyl group and denote its position on the parent chain with the number.
- The alkyl groups are written in alphabetical order.
(c)
Interpretation:
The name of the following molecule should be determined.
Concept Introduction:
Compounds consist of carbon and hydrogen is known as hydrocarbons. Saturated hydrocarbon is known as alkane having general molecular formula
Rules of naming alkanes are:
- First choose the longest continuous chain of carbon atoms known as parent chain and determines the base name of alkane.
- The numbering of parent chain should be done in a way that the substituents get the lowest number.
- The appropriate name should be given to every alkyl group and denote its position on the parent chain with the number.
- The alkyl groups are written in alphabetical order.
(d)
Interpretation:
The name of the following molecule should be determined.
Concept Introduction:
Compounds consist of carbon and hydrogen is known as hydrocarbons. Unsaturated hydrocarbon having double bond is known as alkene having general molecular formula
Rules of naming alkenes are:
- First choose the longest continuous chain of carbon atoms having double bond known as parent chain.
- The numbering of parent chain should be done in a way that the double bond and substituents get the lowest number.
- The root name of the carbon chain is same as in case of alkanes, but “−ane” ending is replaced by “−ene”
- The appropriate name should be given to every alkyl group and denote its position on the parent chain with the number.
- The alkyl groups are written in alphabetical order.
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Chapter 7 Solutions
Bundle: Principles of Modern Chemistry, Loose-leaf Version, 8th + LMS Integrated for OWLv2 with MindTap Reader, 4 terms (24 months) Printed Access Card
- Curved arrows are used to illustrate the flow of electrons. Using the provided starting and product structures, draw the curved electron-pushing arrows for the following reaction or mechanistic step(s). Be sure to account for all bond-breaking and bond-making steps. Prob 10: Select to Add Arrows THEarrow_forwardCurved arrows are used to illustrate the flow of electrons using the provided starting and product structures draw the curved electron pushing arrows for the following reaction or mechanistic steps Ether(solvent)arrow_forwardThis deals with synthetic organic chemistry. Please fill in the blanks appropriately.arrow_forward
- Use the References to access important values if needed for this question. What is the IUPAC name of each of the the following? 0 CH3CHCNH₂ CH3 CH3CHCNHCH2CH3 CH3arrow_forwardYou have now performed a liquid-liquid extraction protocol in Experiment 4. In doing so, you manipulated and exploited the acid-base chemistry of one or more of the compounds in your mixture to facilitate their separation into different phases. The key to understanding how liquid- liquid extractions work is by knowing which layer a compound is in, and in what protonation state. The following liquid-liquid extraction is different from the one you performed in Experiment 4, but it uses the same type of logic. Your task is to show how to separate apart Compound A and Compound B. . Complete the following flowchart of a liquid-liquid extraction. Handwritten work is encouraged. • Draw by hand (neatly) only the appropriate organic compound(s) in the boxes. . Specify the reagent(s)/chemicals (name is fine) and concentration as required in Boxes 4 and 5. • Box 7a requires the solvent (name is fine). • Box 7b requires one inorganic compound. • You can neatly complete this assignment by hand and…arrow_forwardb) Elucidate compound D w) mt at 170 nd shows c-1 stretch at 550cm;' The compound has the ff electronic transitions: 0%o* and no a* 1H NMR Spectrum (CDCl3, 400 MHz) 3.5 3.0 2.5 2.0 1.5 1.0 0.5 ppm 13C{H} NMR Spectrum (CDCl3, 100 MHz) Solvent 80 70 60 50 40 30 20 10 0 ppm ppm ¹H-13C me-HSQC Spectrum ppm (CDCl3, 400 MHz) 5 ¹H-¹H COSY Spectrum (CDCl3, 400 MHz) 0.5 10 3.5 3.0 2.5 2.0 1.5 1.0 10 15 20 20 25 30 30 -35 -1.0 1.5 -2.0 -2.5 3.0 -3.5 0.5 ppm 3.5 3.0 2.5 2.0 1.5 1.0 0.5 ppmarrow_forward
- Part I. a) Elucidate the structure of compound A using the following information. • mass spectrum: m+ = 102, m/2=57 312=29 • IR spectrum: 1002.5 % TRANSMITTANCE Ngg 50 40 30 20 90 80 70 60 MICRONS 5 8 9 10 12 13 14 15 16 19 1740 cm M 10 0 4000 3600 3200 2800 2400 2000 1800 1600 13 • CNMR 'H -NMR Peak 8 ppm (H) Integration multiplicity a 1.5 (3H) triplet b 1.3 1.5 (3H) triplet C 2.3 1 (2H) quartet d 4.1 1 (2H) quartet & ppm (c) 10 15 28 60 177 (C=0) b) Elucidate the structure of compound B using the following information 13C/DEPT NMR 150.9 MHz IIL 1400 WAVENUMBERS (CM-1) DEPT-90 DEPT-135 85 80 75 70 65 60 55 50 45 40 35 30 25 20 ppm 1200 1000 800 600 400arrow_forward• Part II. a) Elucidate The structure of compound c w/ molecular formula C10 11202 and the following data below: • IR spectra % TRANSMITTANCE 1002.5 90 80 70 60 50 40 30 20 10 0 4000 3600 3200 2800 2400 2000 1800 1600 • Information from 'HAMR MICRONS 8 9 10 11 14 15 16 19 25 1400 WAVENUMBERS (CM-1) 1200 1000 800 600 400 peak 8 ppm Integration multiplicity a 2.1 1.5 (3H) Singlet b 3.6 1 (2H) singlet с 3.8 1.5 (3H) Singlet d 6.8 1(2H) doublet 7.1 1(2H) doublet Information from 13C-nmR Normal carbon 29ppm Dept 135 Dept -90 + NO peak NO peak 50 ppm 55 ppm + NO peak 114 ppm t 126 ppm No peak NO peak 130 ppm t + 159 ppm No peak NO peak 207 ppm по реак NO peakarrow_forwardCould you redraw these and also explain how to solve them for me pleasarrow_forward
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