Introduction to the Practice of Statistics
9th Edition
ISBN: 9781319055967
Author: Moore
Publisher: MAC HIGHER
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Chapter 7, Problem 119E
Section 1:
To determine
To find: The
Section 1:
Expert Solution
Answer to Problem 119E
Solution: The required mean of the data is 153.50.
Explanation of Solution
Calculation: To obtain the mean, follow the steps below in Minitab software.
Step 1: Enter the data in the Minitab worksheet.
Step 2: Go to Stat and select the basic statistics, and then click on display the
Step 3: Enter the variable in the variables column.
Step 4: Choose the options as mean.
Step 5: Click on OK two times.
The mean is obtained as 153.50.
Section 2:
To determine
To find: The standard deviation of scores of four roommates.
Section 2:
Expert Solution
Answer to Problem 119E
Solution: The standard deviation of the data is 14.71.
Explanation of Solution
Calculation: To obtain the standard deviation, follow the steps below in Minitab software.
Step 1: Enter the data in the Minitab worksheet.
Step 2: Go to Stat and select the basic statistics, and then click on display the descriptive statistics.
Step 3: Enter the variable in the variables column.
Step 4: Choose the options as mean.
Step 5: Click OK twice.
The standard deviation is obtained as 14.71.
Section 3:
To determine
To find: The standard error of the mean.
Section 3:
Expert Solution
Answer to Problem 119E
Solution: The standard error is 7.35.
Explanation of Solution
Calculation: To obtain the standard error, follow the steps below in Minitab software.
Step 1: Enter the data in the Minitab worksheet.
Step 2: Go to Stat and select the basic statistics, and then click on display the descriptive statistics.
Step 3: Enter the variable in the variables column.
Step 4: Choose the options as mean.
Step 5: Click OK twice.
The standard error is obtained as 7.35.
To determine
Whether it is correct to calculate the confidence interval for the data or not.
Expert Solution
Answer to Problem 119E
Solution: As the data cannot be considered as simple random sampling, the confidence interval should not be calculated for this data.
Explanation of Solution
To compute the confidence interval for any dataset, the data should belong to simple random sampling. In the provided case, the data cannot be considered as simple random sampling because of the small sample size . Therefore, it is not appropriate if the confidence interval is calculated on the basis of the provided data.
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Microsoft Excel snapshot for random sampling: Also note the formula used for the last
column
02
x✓ fx =INDEX(5852:58551, RANK(C2, $C$2:$C$51))
A
B
1
No.
States
2
1
ALABAMA
Rand No.
0.925957526
3
2
ALASKA
0.372999976
4
3
ARIZONA
0.941323044
5
4 ARKANSAS
0.071266381
Random Sample
CALIFORNIA
NORTH CAROLINA
ARKANSAS
WASHINGTON
G7
Microsoft Excel snapshot for systematic sampling:
xfx INDEX(SD52:50551, F7)
A
B
E
F
G
1
No.
States
Rand No. Random Sample
population
50
2
1 ALABAMA
0.5296685 NEW HAMPSHIRE
sample
10
3
2 ALASKA
0.4493186 OKLAHOMA
k
5
4
3 ARIZONA
0.707914 KANSAS
5
4 ARKANSAS 0.4831379 NORTH DAKOTA
6
5 CALIFORNIA 0.7277162 INDIANA
Random Sample
Sample Name
7
6 COLORADO 0.5865002 MISSISSIPPI
8
7:ONNECTICU 0.7640596 ILLINOIS
9
8 DELAWARE 0.5783029 MISSOURI
525
10
15
INDIANA
MARYLAND
COLORADO
Suppose the Internal Revenue Service reported that the mean tax refund for the year 2022 was $3401. Assume the standard deviation is $82.5 and that the amounts refunded follow a normal probability distribution. Solve the following three parts? (For the answer to question 14, 15, and 16, start with making a bell curve. Identify on the bell curve where is mean, X, and area(s) to be determined.
1.What percent of the refunds are more than $3,500?
2. What percent of the refunds are more than $3500 but less than $3579?
3. What percent of the refunds are more than $3325 but less than $3579?
A normal distribution has a mean of 50 and a standard deviation of 4. Solve the following three parts?
1. Compute the probability of a value between 44.0 and 55.0.
(The question requires finding probability value between 44 and 55. Solve it in 3 steps.
In the first step, use the above formula and x = 44, calculate probability value.
In the second step repeat the first step with the only difference that x=55.
In the third step, subtract the answer of the first part from the answer of the second part.)
2. Compute the probability of a value greater than 55.0.
Use the same formula, x=55 and subtract the answer from 1.
3. Compute the probability of a value between 52.0 and 55.0.
(The question requires finding probability value between 52 and 55. Solve it in 3 steps.
In the first step, use the above formula and x = 52, calculate probability value.
In the second step repeat the first step with the only difference that x=55.
In the third step, subtract the answer of the first part from the…
Chapter 7 Solutions
Introduction to the Practice of Statistics
Ch. 7.1 - Prob. 1UYKCh. 7.1 - Prob. 2UYKCh. 7.1 - Prob. 3UYKCh. 7.1 - Prob. 4UYKCh. 7.1 - Prob. 5UYKCh. 7.1 - Prob. 6UYKCh. 7.1 - Prob. 7UYKCh. 7.1 - Prob. 8UYKCh. 7.1 - Prob. 9UYKCh. 7.1 - Prob. 10UYK
Ch. 7.1 - Prob. 11UYKCh. 7.1 - Prob. 12UYKCh. 7.1 - Prob. 13UYKCh. 7.1 - Prob. 14ECh. 7.1 - Prob. 15ECh. 7.1 - Prob. 16ECh. 7.1 - Prob. 17ECh. 7.1 - Prob. 18ECh. 7.1 - Prob. 19ECh. 7.1 - Prob. 20ECh. 7.1 - Prob. 21ECh. 7.1 - Prob. 22ECh. 7.1 - Prob. 23ECh. 7.1 - Prob. 24ECh. 7.1 - Prob. 25ECh. 7.1 - Prob. 26ECh. 7.1 - Prob. 27ECh. 7.1 - Prob. 28ECh. 7.1 - Prob. 29ECh. 7.1 - Prob. 30ECh. 7.1 - Prob. 31ECh. 7.1 - Prob. 32ECh. 7.1 - Prob. 33ECh. 7.1 - Prob. 34ECh. 7.1 - Prob. 35ECh. 7.1 - Prob. 36ECh. 7.1 - Prob. 37ECh. 7.1 - Prob. 38ECh. 7.1 - Prob. 39ECh. 7.1 - Prob. 40ECh. 7.1 - Prob. 41ECh. 7.1 - Prob. 42ECh. 7.1 - Prob. 43ECh. 7.1 - Prob. 44ECh. 7.1 - Prob. 45ECh. 7.1 - Prob. 46ECh. 7.1 - Prob. 47ECh. 7.2 - Prob. 48UYKCh. 7.2 - Prob. 49UYKCh. 7.2 - Prob. 50UYKCh. 7.2 - Prob. 51UYKCh. 7.2 - Prob. 52UYKCh. 7.2 - Prob. 53UYKCh. 7.2 - Prob. 54UYKCh. 7.2 - Prob. 55ECh. 7.2 - Prob. 56ECh. 7.2 - Prob. 57ECh. 7.2 - Prob. 58ECh. 7.2 - Prob. 59ECh. 7.2 - Prob. 61ECh. 7.2 - Prob. 62ECh. 7.2 - Prob. 63ECh. 7.2 - Prob. 64ECh. 7.2 - Prob. 65ECh. 7.2 - Prob. 66ECh. 7.2 - Prob. 67ECh. 7.2 - Prob. 68ECh. 7.2 - Prob. 69ECh. 7.2 - Prob. 70ECh. 7.2 - Prob. 71ECh. 7.2 - Prob. 72ECh. 7.2 - Prob. 73ECh. 7.2 - Prob. 74ECh. 7.2 - Prob. 75ECh. 7.2 - Prob. 76ECh. 7.2 - Prob. 77ECh. 7.2 - Prob. 78ECh. 7.2 - Prob. 79ECh. 7.2 - Prob. 80ECh. 7.2 - Prob. 81ECh. 7.2 - Prob. 82ECh. 7.2 - Prob. 83ECh. 7.2 - Prob. 84ECh. 7.2 - Prob. 85ECh. 7.2 - Prob. 86ECh. 7.2 - Prob. 87ECh. 7.2 - Prob. 88ECh. 7.2 - Prob. 89ECh. 7.2 - Prob. 90ECh. 7.2 - Prob. 91ECh. 7.2 - Prob. 92ECh. 7.3 - Prob. 93UYKCh. 7.3 - Prob. 94UYKCh. 7.3 - Prob. 95UYKCh. 7.3 - Prob. 96UYKCh. 7.3 - Prob. 97UYKCh. 7.3 - Prob. 98UYKCh. 7.3 - Prob. 99UYKCh. 7.3 - Prob. 100UYKCh. 7.3 - Prob. 101ECh. 7.3 - Prob. 102ECh. 7.3 - Prob. 103ECh. 7.3 - Prob. 104ECh. 7.3 - Prob. 105ECh. 7.3 - Prob. 106ECh. 7.3 - Prob. 107ECh. 7.3 - Prob. 108ECh. 7.3 - Prob. 109ECh. 7.3 - Prob. 110ECh. 7.3 - Prob. 111ECh. 7.3 - Prob. 112ECh. 7.3 - Prob. 113ECh. 7.3 - Prob. 114ECh. 7.3 - Prob. 115ECh. 7.3 - Prob. 116ECh. 7.3 - Prob. 117ECh. 7.3 - Prob. 118ECh. 7 - Prob. 119ECh. 7 - Prob. 120ECh. 7 - Prob. 121ECh. 7 - Prob. 122ECh. 7 - Prob. 123ECh. 7 - Prob. 124ECh. 7 - Prob. 125ECh. 7 - Prob. 126ECh. 7 - Prob. 127ECh. 7 - Prob. 128ECh. 7 - Prob. 129ECh. 7 - Prob. 130ECh. 7 - Prob. 131ECh. 7 - Prob. 132ECh. 7 - Prob. 133ECh. 7 - Prob. 134ECh. 7 - Prob. 135ECh. 7 - Prob. 136ECh. 7 - Prob. 137ECh. 7 - Prob. 138ECh. 7 - Prob. 139ECh. 7 - Prob. 140ECh. 7 - Prob. 141ECh. 7 - Prob. 142ECh. 7 - Prob. 143ECh. 7 - Prob. 144ECh. 7 - Prob. 145ECh. 7 - Prob. 146ECh. 7 - Prob. 147ECh. 7 - Prob. 148ECh. 7 - Prob. 149E
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