Using MIS (10th Edition)
10th Edition
ISBN: 9780134606996
Author: David M. Kroenke, Randall J. Boyle
Publisher: PEARSON
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Chapter 6.7, Problem 1QLQ
Explanation of Solution
Learning new information:
Different people can come with different examples of article that they have newly learned.
- I have recently learned a
programming language called “JAVA”.- JAVA is an object oriented programming language similar as C++, designed to implement applications.
Time taken to complete the above language:
In order to learn and mastering in JAVA needs 6 months to complete it. This time taken will suits a people who knows basic programming languages like C++, Pascal, scripting languages and so on.
Types learning
The following mechanisms required to learn JAVA:
- JAVA online tutorials.
- Reference books.
- JAVA IDE software’s like Eclipse, NetBeans and so on.
Types of approaches needed to learn the above language:
The following approaches required to learn JAVA:
- Get ideas from experts like professors...
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Check out a sample textbook solution
Students have asked these similar questions
I would like to get help to resolve the following case
Last Chance Securities
The IT director opened the department staff meeting today by saying, "I've got some good news and
some bad news. The good news is that management approved the payroll system project this morning.
The new system will reduce clerical time and errors, improve morale in the payroll department, and avoid
possible fines and penalties for noncompliance. The bad news is that the system must be installed by
January 1st in order to meet new federal reporting rules, all expenses from now on must be approved in
advance, the system should have a modular design if possible, and the vice president of finance would
like to announce the new system in a year-end report if it is ready by mid-December."
Tasks
1. Why is it important to define the project scope? How would you define the scope of the payroll
project in this case?
2. Review each constraint and identify its characteristics: present versus future, internal versus exter-
nal, and mandatory versus desirable.
3. What…
2. Signed Integers
Unsigned binary numbers work for natural numbers, but many calculations use negative
numbers as well. To deal with this, a number of different methods have been used to represent
signed numbers, but we will focus on two's complement, as it is the standard solution for
representing signed integers.
2.1 Two's complement
• Most significant bit has a negative value, all others are positive. So, the value of an n-digit
-2
two's complement number can be written as: Σ2 2¹ di 2n-1 dn
• Otherwise exactly the same as unsigned integers.
i=0
-
• A neat trick for flipping the sign of a two's complement number: flip all the bits (0 becomes 1,
or 1 becomes 0) and then add 1 to the least significant bit.
• Addition is exactly the same as with an unsigned number.
2.2 Exercises
For questions 1-3, answer each one for the case of a two's complement number and an
unsigned number, indicating if it cannot be answered with a specific representation.
1. (15 pts) What is the largest integer…
Chapter 6 Solutions
Using MIS (10th Edition)
Ch. 6.3 - Prob. 1EGDQCh. 6.3 - Prob. 2EGDQCh. 6.3 - Prob. 3EGDQCh. 6.3 - Prob. 4EGDQCh. 6.3 - Prob. 5EGDQCh. 6.3 - Prob. 6EGDQCh. 6.3 - Prob. 7EGDQCh. 6.3 - Prob. 8EGDQCh. 6.3 - Prob. 9EGDQCh. 6.7 - Prob. 1QLQ
Ch. 6.7 - Prob. 2QLQCh. 6.7 - Prob. 3QLQCh. 6.7 - The article mentions that quantum computers will...Ch. 6.8 - Prob. 1SGDQCh. 6.8 - Prob. 2SGDQCh. 6.8 - Prob. 3SGDQCh. 6.8 - Prob. 4SGDQCh. 6.8 - Prob. 5SGDQCh. 6.8 - Prob. 6.1ARQCh. 6.8 - Prob. 6.2ARQCh. 6.8 - Prob. 6.3ARQCh. 6.8 - Prob. 6.4ARQCh. 6.8 - Prob. 6.5ARQCh. 6.8 - Prob. 6.6ARQCh. 6.8 - Prob. 6.7ARQCh. 6.8 - Prob. 6.8ARQCh. 6 - Prob. 6.1UYKCh. 6 - Prob. 6.2UYKCh. 6 - Prob. 6.3UYKCh. 6 - Prob. 6.4UYKCh. 6 - Prob. 6.5UYKCh. 6 - Prob. 6.6UYKCh. 6 - Prob. 6.7CE6Ch. 6 - Prob. 6.8CE6Ch. 6 - Prob. 6.9CE6Ch. 6 - Prob. 6.1CE6Ch. 6 - Prob. 6.11CE6Ch. 6 - Prob. 6.12CE6Ch. 6 - Prob. 6.14CS6Ch. 6 - Prob. 6.15CS6Ch. 6 - Prob. 6.16CS6Ch. 6 - Prob. 6.17CS6Ch. 6 - Prob. 6.18CS6Ch. 6 - Prob. 6.19CS6Ch. 6 - Prob. 6.2CS6Ch. 6 - Prob. 6.21MMLCh. 6 - Prob. 6.22MML
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- can u solve this questionarrow_forward1. Unsigned Integers If we have an n-digit unsigned numeral dn-1d n-2...do in radix (or base) r, then the value of that numeral is n−1 r² di Σi=0 which is basically saying that instead of a 10's or 100's place we have an r's or r²'s place. For binary, decimal, and hex r equals 2, 10, and 16, respectively. Just a reminder that in order to write down a large number, we typically use the IEC or SI prefixing system: IEC: Ki = 210, Mi = 220, Gi = 230, Ti = 240, Pi = 250, Ei = 260, Zi = 270, Yi = 280; SI: K=103, M = 106, G = 109, T = 10¹², P = 1015, E = 10¹8, Z = 1021, Y = 1024. 1.1 Conversions a. (15 pts) Write the following using IEC prefixes: 213, 223, 251, 272, 226, 244 21323 Ki8 Ki 223 23 Mi 8 Mi b. (15 pts) Write the following using SI prefixes: 107, 10¹7, 10¹¹, 1022, 1026, 1015 107 10¹ M = 10 M = 1017102 P = 100 P c. (10 pts) Write the following with powers of 10: 7 K, 100 E, 21 G 7 K = 7*10³arrow_forwardanswer shoul avoid using AI and should be basic and please explainarrow_forward
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- answer should avoid using AI (such as ChatGPT), do not any answer directly copied from AI would and explain codearrow_forwardWrite a c++ program that will count from 1 to 10 by 1. The default output should be: 1, 2, 3, 4, 5, 6 , 7, 8, 9, 10 There should be only a newline after the last number. Each number except the last should be followed by a comma and a space. To make your program more functional, you should parse command line arguments and change behavior based on their values. Argument Parameter Action -f, --first yes, an integer Change place you start counting -l, --last yes, an integer Change place you end counting -s, --skip optional, an integer, 1 if not specified Change the amount you add to the counter each iteration -h, —help none Print a help message including these instructions. -j, --joke none Tell a number based joke. So, if your program is called counter, counter -f 10 --last 4 --skip 2 should produce 10, 8, 6, 4 Please use the last supplied argument. If your code is called counter, counter -f 4 -f 5 -f 6 should count from 6. You should…arrow_forwardshow workarrow_forward
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