Chapter 6.6, Problem 86SR

To determine

The value of $\left(x\right)$ for the expression $x^2+6x-16=0$ by factorization.

Answer to Problem 86SR

The value of $\left(x\right)$ is either $-8\text{or }2$ .

Explanation of Solution

Given information: The given equation is,

  $x^2+6x-16=\mathrm{0......}\left(1\right)$

Calculation: The value of $\left(x\right)$ can be evaluated using (1) as,

  $\begin{array}{c}{x}^2+8x-2x-16=\mathrm{0....}\left(\text{Factorized}\right)\\ x\left(x+8\right)-2\left(x+8\right)=0\\ \left(x+8\right)\left(x-2\right)=0\\ x+8=0\text{or}x-2=0\\ x=-8\text{ or}x=2\end{array}$