Chapter 6.3, Problem 29PPS

To determine

The distance $\left(d\right)$ that the parachutist travels during the time $\left(t\right)$ equal to 11 seconds if the relation between the time $\left(t\right)$ and distance $\left(d\right)$ is given as $t=\sqrt{\frac{d}{16}}$.

Answer to Problem 29PPS

The distance $\left(d\right)$ is equal to 1936 feet.

Explanation of Solution

Given information: The time taken by parachutist is given by the distance-time relation,

  $t=\sqrt{\frac{d}{16}}\mathrm{......}\left(1\right)$

Calculation: Plugging for $\left(t=11\right)$ in (1) and simplify for distance $\left(d\right)$

  $\begin{array}{c}\left(11\right)=\sqrt{\frac{d}{16}}\mathrm{......}\left(\text{For }t=11\right)\\ 121=\frac{d}{16}\mathrm{......}\left(\text{Square both sides}\right)\\ \text{or, }d=1936\text{ feet}\end{array}$