Chapter 6.6, Problem 17PPS

(a)

To determine

To Find: The scale of drawing.

Answer to Problem 17PPS

Explanation of Solution

Given:The 8 planet’s distance from the Sun as shown in table.

  $\begin{array}{cc}\text{Planet}& \text{Distance from the Sun}\left(\text{mi}\right)\\ \text{Mercury}& 3.6\times {10}^7\\ \text{Venus}& 6.7\times {10}^7\\ \text{Earth}& 9.3\times {10}^7\\ \text{Mars}& 1.42\times {10}^8\\ \text{Jupiter}& 4.84\times {10}^8\\ \text{Saturn}& 8.87\times {10}^8\\ \text{Uranus}& 1.8\times {10}^9\\ \text{Neptune}& 2.8\times {10}^9\end{array}$

In the given table the exponent of 10 is 7 to 9.

Let’s take scale of ${10}^8\text{ mi}=1\text{ in}$

Now change each distance according to scale.

  $\begin{array}{ccc}\text{Planet}& \text{Distance from the Sum}\left(\text{mi}\right)& \text{Scale }\left(\text{in}\right)\\ \text{Mercury}& 3.6\times {10}^7& 0.36\\ \text{Venus}& 6.7\times {10}^7& 0.67\\ \text{Earth}& 9.3\times {10}^7& 0.93\\ \text{Mars}& 1.42\times {10}^8& 1.42\\ \text{Jupiter}& 4.84\times {10}^8& 4.48\\ \text{Saturn}& 8.87\times {10}^8& 8.87\\ \text{Uranus}& 1.8\times {10}^9& 18\\ \text{Neptune}& 2.8\times {10}^9& 28\end{array}$

(b)

To determine

To make:A map of first six closest planet to sun.

Answer to Problem 17PPS

  

Explanation of Solution

Given:The scale value of each planet as shown below.

  $\begin{array}{ccc}\text{Planet}& \text{Distance from the Sum}\left(\text{mi}\right)& \text{Scale }\left(\text{in}\right)\\ \text{Mercury}& 3.6\times {10}^7& 0.36\\ \text{Venus}& 6.7\times {10}^7& 0.67\\ \text{Earth}& 9.3\times {10}^7& 0.93\\ \text{Mars}& 1.42\times {10}^8& 1.42\\ \text{Jupiter}& 4.84\times {10}^8& 4.48\\ \text{Saturn}& 8.87\times {10}^8& 8.87\\ \text{Uranus}& 1.8\times {10}^9& 18\\ \text{Neptune}& 2.8\times {10}^9& 28\end{array}$

Using table to draw map of grip 0.25 in