Chapter 6, Problem 29SGR

To determine

To calculate:To write an equation relating the cost to the number of rings andfind how much customer would pay for $11$ rings and for $20$ rings

Answer to Problem 29SGR

The equation relating the cost to the number of rings is $Cost=\frac{x}{4}$

Cost of $11$ rings is $\$2.75$

Cost of $20$ rings is $\$5$

Explanation of Solution

Given information:A customer at the ring toss booth gets $8$ rings for $\$2$

Calculation:

Let number of rings be $x$

Given that acustomer at the ring toss booth gets $8$ rings for $\$2$

Thus,

Cost of $8$ rings $=\$2$

Cost of $1$ ring $=\frac{2}{8}$

Now, cost of $x$ rings $=\frac{2}{8}\times x$

On solving the above,

Cost $=\frac{x}{4}$

Now, cost of $11$ rings is calculated as follows:

  $\begin{array}{l}Cost=\frac{11}{4}\\ Cost=\$2.75\end{array}$

Also, cost of $20$ rings ins calculated as follows:

  $\begin{array}{l}Cost=\frac{20}{4}\\ Cost=\$5\end{array}$

Hence, equation relating the cost to the number of rings is $Cost=\frac{x}{4}$

Cost of $11$ rings is $\$2.75$

Cost of $20$ rings is $\$5$