Practical Management Science, Loose-leaf Version
5th Edition
ISBN: 9781305631540
Author: WINSTON, Wayne L.; Albright, S. Christian
Publisher: Cengage Learning
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Chapter 6.5, Problem 30P
Summary Introduction
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Introduction: The variation between the present value of the
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A retailer has 7 stores in different cities in northern Ontario. The weekly demand for each store follows the normal distribution with a mean value of 60 and a standard deviation of 10. The retailer is planning to use a single centralized store in northern Ontario and they think the demand in the single store will be equal to the sum of the demand in all 7 cities. It takes 3 weeks for the supplier to send the products to the retailer. Calculate the safety stock for the centralized and decentralized cases if the correlation of demands between different cities is 0.3. Assume the planned customer service level is 98%.
Please post answer in excel showing formula and answer
99. A plastics manufacturer has 1,200 boxes of transparent wrap in stock at one factory
and another 1,000 boxes at its second factory. The manufacturer has orders for this
product from three different retailers, in quantities of 1,000, 700, and 500 boxes,
respectively. The unit shipping costs (in cents per box) from the factories to the retailers
are as indicated in the table below. Apply the Vogel's Approximation Method to
determine the initial starting solution.
Retailer 1
Retailer 3
Factory 1
Factory 2
Retailer 2
13
13
14
11
13
12
A. Z = $276
B. Z = $267
C. Z = $627
D. Z = $ 762
Chapter 6 Solutions
Practical Management Science, Loose-leaf Version
Ch. 6.3 - Prob. 1PCh. 6.3 - Prob. 2PCh. 6.3 - Solve Problem 1 with the extra assumption that the...Ch. 6.3 - Prob. 4PCh. 6.3 - Prob. 5PCh. 6.3 - Prob. 6PCh. 6.3 - Prob. 7PCh. 6.3 - Prob. 8PCh. 6.3 - Prob. 9PCh. 6.3 - Prob. 10P
Ch. 6.4 - Prob. 11PCh. 6.4 - Prob. 12PCh. 6.4 - Prob. 13PCh. 6.4 - Prob. 14PCh. 6.4 - Prob. 15PCh. 6.4 - Prob. 16PCh. 6.4 - Prob. 17PCh. 6.4 - Prob. 18PCh. 6.4 - Prob. 19PCh. 6.4 - Prob. 20PCh. 6.4 - Prob. 21PCh. 6.4 - Prob. 22PCh. 6.4 - Prob. 23PCh. 6.5 - Prob. 24PCh. 6.5 - Prob. 25PCh. 6.5 - Prob. 26PCh. 6.5 - Prob. 28PCh. 6.5 - Prob. 29PCh. 6.5 - Prob. 30PCh. 6.5 - In the optimal solution to the Green Grass...Ch. 6.5 - Prob. 32PCh. 6.5 - Prob. 33PCh. 6.5 - Prob. 34PCh. 6.5 - Prob. 35PCh. 6.6 - Prob. 36PCh. 6.6 - Prob. 37PCh. 6.6 - Prob. 38PCh. 6 - Prob. 39PCh. 6 - Prob. 40PCh. 6 - Prob. 41PCh. 6 - Prob. 42PCh. 6 - Prob. 43PCh. 6 - Prob. 44PCh. 6 - Prob. 45PCh. 6 - Prob. 46PCh. 6 - Prob. 47PCh. 6 - Prob. 48PCh. 6 - Prob. 49PCh. 6 - Prob. 50PCh. 6 - Prob. 51PCh. 6 - Prob. 52PCh. 6 - Prob. 53PCh. 6 - Prob. 54PCh. 6 - Prob. 55PCh. 6 - Prob. 56PCh. 6 - Prob. 57PCh. 6 - Prob. 58PCh. 6 - Prob. 59PCh. 6 - Prob. 60PCh. 6 - Prob. 61PCh. 6 - Prob. 62PCh. 6 - Prob. 63PCh. 6 - Prob. 64PCh. 6 - Prob. 65PCh. 6 - Prob. 66PCh. 6 - Prob. 67PCh. 6 - Prob. 68PCh. 6 - Prob. 69PCh. 6 - Prob. 70PCh. 6 - Prob. 71PCh. 6 - Prob. 72PCh. 6 - Prob. 73PCh. 6 - Prob. 74PCh. 6 - Prob. 75PCh. 6 - Prob. 76PCh. 6 - Prob. 77PCh. 6 - Prob. 78PCh. 6 - Prob. 79PCh. 6 - Prob. 80PCh. 6 - Prob. 81PCh. 6 - Prob. 82PCh. 6 - Prob. 83PCh. 6 - Prob. 84PCh. 6 - Prob. 85PCh. 6 - Prob. 86PCh. 6 - Prob. 87PCh. 6 - Prob. 88PCh. 6 - Prob. 89PCh. 6 - Prob. 90PCh. 6 - Prob. 91PCh. 6 - Prob. 92PCh. 6 - This problem is based on Motorolas online method...Ch. 6 - Prob. 94PCh. 6 - Prob. 95PCh. 6 - Prob. 96PCh. 6 - Prob. 97PCh. 6 - Prob. 98PCh. 6 - Prob. 99PCh. 6 - Prob. 100PCh. 6 - Prob. 1CCh. 6 - Prob. 2CCh. 6 - Prob. 3.1CCh. 6 - Prob. 3.2CCh. 6 - Prob. 3.3CCh. 6 - Prob. 3.4CCh. 6 - Prob. 3.5CCh. 6 - Prob. 3.6C
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