Chapter 6.4, Problem 17SC

Explanation of Solution

Given input check “do-while” loop:

//declaring variable value

int value;

//define "do-while" loop

do

{

    //prompt the range of input

    System.out.print("Enter an integer < 100: ");

    //scan for the input value

    value = in.nextInt();

//"while" condition to stop

} while(value >= 100);

Explanation:

In the above code snippet,

• A variable named “value” is created.
• A “do-while” loop is executed up to the condition “value >= 100”.
  • Prompt the range of the input integers.
  • Scan for the input integers using object “in”.

Program for checking input greater than “0” and less than “100”:

//import required header files

import java.util.Scanner;

//define class "Range"

publicclassRange

{

    //define main method

    publicstaticvoid main(String[] args)

    {

        //declaring variable value

        int value=100;

        //declaring the object of "Scanner" class

        Scanner in=new Scanner(System...

Explanation of Solution

The disadvantage of the solution:

• The “while” loop enters to its body only if the condition is true. But the “do-while” loop enters to the body once before checking the condition.
• In the given code, when the “do-while” loop is changed to “while” loop, there is a need of assigning “100” to the variable “value”.
• Here, the variable “value” had to be initialized with an artificial value to ensure that the loop is entered at least once...