a. Given statements: //declare the variables and assign the values int i = 0; int j = 10; int n = 0; //check "i" is less than "j" while(i < j) { //increment the value i++; //decrement the value j--; //increment the value n++; } Trace table for the above loops: i j n 0 10 0 1 9 1 2 8 2 3 7 3 4 6 4 5 5 5 Explanation: Here, the “i” value is “0”, “j” value is “10” and “n” value is “0”. In first iteration of “while” loop checks “i < j” which means “0 < 10”. The condition becomes true, so it increment the “i” value, i = 1, decrement the “j” value, j = 9 and also increment the “n”, n = 1...

Question

Want to see the full answer?

Answer 1

Expert Solution & Answer

Chapter 6, Problem 6RE

Explanation of Solution

a.

Given statements:

//declare the variables and assign the values

int i = 0;

int j = 10;

int n = 0;

//check "i" is less than "j"

while(i < j)

{

    //increment the value

    i++;

    //decrement the value

    j--;

    //increment the value

    n++;

}

Trace table for the above loops:

i j n
0 10 0
1 9 1
2 8 2
3 7 3
4 6 4
5 5 5

Explanation:

Here, the “i” value is “0”, “j” value is “10” and “n” value is “0”.

In first iteration of “while” loop checks “i < j” which means “0 < 10”. The condition becomes true, so it increment the “i” value, i = 1, decrement the “j” value, j = 9 and also increment the “n”, n = 1...

Explanation of Solution

b.

Given statements:

//declare the variables and assign the values

int i = 0;

int j = 0;

int n = 0;

//check "i" is less than "10"

while(i < 10)

{

    //increment the value

    i++;

    //calculate the "n" value

    n = n + i + j;

    //increment the value

    j++;

}

Trace table for the above loops:

i j n
0 0 1
1 1 4
2 2 9
3 3 16
4 4 25
5 5 36
6 6 49
7 7 64
8 8 81
9 9 100

Explanation:

Here, the “i” value is 0, “j” value is 0 and “n” value is 0.

In first iteration of “while” loop checks “i < 10” which means “0 < 10”. The condition becomes true, so it increment the “i” value, i = 1, calculate “n” value which means (0 + 1 + 0 = 1) and also increment the “j”, j = 1.

In second iteration of “while” loop checks “i < 10” which means “1 < 10”. The condition becomes true, so it increment the “i” value, i = 2, calculate “n” value which means (1+ 2 + 1 = 4) and also increment the “j”, j = 2.

In third iteration of “while” loop checks “i < 10” which means “2 < 10”. The condition becomes true, so it increment the “i” value, i = 3, calculate “n” value which means (4+ 3 + 2 = 9) and also increment the “j”, j = 3.

In fourth iteration of “while” loop checks “i < 10” which means “3 < 10”...

Explanation of Solution

c.

Given statements:

//declare the variables and assign the values

int i = 10;

int j = 0;

int n = 0;

//check "i" is greater than "0"

while(i > 0)

{

    //decrement the value

    i--;

//increment the value

    j++;

    //calculate the "n" value

    n = n + i - j;

}

Trace table for the above loops:

i j n
10 0 8
9 1 14
8 2 18
7 3 20
6 4 20
5 5 18
4 6 14
3 7 8
2 8 0
1 9 -10

Explanation:

Here, the “i” value is 10, “j” value is 0 and “n” value is 0.

In first iteration of “while” loop checks “i > 0” which means “10 > 0”. The condition becomes true, so it decrement the “i” value, i = 9, increment the “j”, j = 1 and calculate “n” value which means (0 + 9 - 1 = 8).

In second iteration of “while” loop checks “i > 0” which means “9 > 0”. The condition becomes true, so it decrement the “i” value, i = 8, increment the “j”, j = 2 and calculate “n” value which means (8 + 8 - 2 = 14).

In third iteration of “while” loop checks “i > 0” which means “8 > 0”. The condition becomes true, so it decrement the “i” value, i = 7, increment the “j”, j = 3 and calculate “n” value which means (14 + 7 - 3 = 18).

In fourth iteration of “while” loop checks “i > 0” which means “7 > 0”...

Explanation of Solution

d.

Given statements:

//declare the variables and assign the values

int i = 0;

int j = 10;

int n = 0;

//check "i" is greater than "0"

while(i != j)

{

    //increment the "i" by 2

    i = i + 2;

//decrement the "j" by 2

    j = j – 2;

    //increment the value

    n++;

}

Trace table for the above loops:

i j n
0 10 0
2 8 1
4 6 2
6 4 3
8 2 4

...

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

Please assist me by writing out the code with its output (in python) using the information provided in the 2 images below.for the IP Address, it has been changed to: 172.21.5.204the serve code has not been open yet though but the ouput must be something along these lines(using command prompt):c:\Users\japha\Desktop>python "Sbongakonke.py"Enter the server IP address (127.0.0.1 or 172.21.5.199): 172.21.5.204Enter your student number: 4125035Connected to server!It's your turn to pour! Enter the amount to your pour (in mL):Please work it out until it gets the correct outputsNB: THIS QUESTION IS NOT A GRADED QUESTION

need help with a html code and css code that will match this image.

need help with a html code and css code that will match this image. Part B - A Navigation Part B is the navigation component of a page. Information you need includes: Color Codes: Visiting links: #ff6666 Unvisited links: #ccff66 Hovered links: white Search box: #2ec4b6 rebeccapurple white Font: Google Font (Roboto) Icons: Font Awesome (fa-quidditch, fa-search) This is a flexbox based navigation menu. Other then padding, all spacing/positioning should be controlled using flex properties. The home link in the nav should point to your assignment file (to triggers visited styling). In the "state" screenshot below, Home is visited, Services is hovered (the mouse doesn't show up in the screenshot) and Products is unvisited.

Answer 2

Expert Solution & Answer

Chapter 6, Problem 6RE

Explanation of Solution

a.

Given statements:

//declare the variables and assign the values

int i = 0;

int j = 10;

int n = 0;

//check "i" is less than "j"

while(i < j)

{

    //increment the value

    i++;

    //decrement the value

    j--;

    //increment the value

    n++;

}

Trace table for the above loops:

i j n
0 10 0
1 9 1
2 8 2
3 7 3
4 6 4
5 5 5

Explanation:

Here, the “i” value is “0”, “j” value is “10” and “n” value is “0”.

In first iteration of “while” loop checks “i < j” which means “0 < 10”. The condition becomes true, so it increment the “i” value, i = 1, decrement the “j” value, j = 9 and also increment the “n”, n = 1...

Explanation of Solution

b.

Given statements:

//declare the variables and assign the values

int i = 0;

int j = 0;

int n = 0;

//check "i" is less than "10"

while(i < 10)

{

    //increment the value

    i++;

    //calculate the "n" value

    n = n + i + j;

    //increment the value

    j++;

}

Trace table for the above loops:

i j n
0 0 1
1 1 4
2 2 9
3 3 16
4 4 25
5 5 36
6 6 49
7 7 64
8 8 81
9 9 100

Explanation:

Here, the “i” value is 0, “j” value is 0 and “n” value is 0.

In first iteration of “while” loop checks “i < 10” which means “0 < 10”. The condition becomes true, so it increment the “i” value, i = 1, calculate “n” value which means (0 + 1 + 0 = 1) and also increment the “j”, j = 1.

In second iteration of “while” loop checks “i < 10” which means “1 < 10”. The condition becomes true, so it increment the “i” value, i = 2, calculate “n” value which means (1+ 2 + 1 = 4) and also increment the “j”, j = 2.

In third iteration of “while” loop checks “i < 10” which means “2 < 10”. The condition becomes true, so it increment the “i” value, i = 3, calculate “n” value which means (4+ 3 + 2 = 9) and also increment the “j”, j = 3.

In fourth iteration of “while” loop checks “i < 10” which means “3 < 10”...

Explanation of Solution

c.

Given statements:

//declare the variables and assign the values

int i = 10;

int j = 0;

int n = 0;

//check "i" is greater than "0"

while(i > 0)

{

    //decrement the value

    i--;

//increment the value

    j++;

    //calculate the "n" value

    n = n + i - j;

}

Trace table for the above loops:

i j n
10 0 8
9 1 14
8 2 18
7 3 20
6 4 20
5 5 18
4 6 14
3 7 8
2 8 0
1 9 -10

Explanation:

Here, the “i” value is 10, “j” value is 0 and “n” value is 0.

In first iteration of “while” loop checks “i > 0” which means “10 > 0”. The condition becomes true, so it decrement the “i” value, i = 9, increment the “j”, j = 1 and calculate “n” value which means (0 + 9 - 1 = 8).

In second iteration of “while” loop checks “i > 0” which means “9 > 0”. The condition becomes true, so it decrement the “i” value, i = 8, increment the “j”, j = 2 and calculate “n” value which means (8 + 8 - 2 = 14).

In third iteration of “while” loop checks “i > 0” which means “8 > 0”. The condition becomes true, so it decrement the “i” value, i = 7, increment the “j”, j = 3 and calculate “n” value which means (14 + 7 - 3 = 18).

In fourth iteration of “while” loop checks “i > 0” which means “7 > 0”...

Explanation of Solution

d.

Given statements:

//declare the variables and assign the values

int i = 0;

int j = 10;

int n = 0;

//check "i" is greater than "0"

while(i != j)

{

    //increment the "i" by 2

    i = i + 2;

//decrement the "j" by 2

    j = j – 2;

    //increment the value

    n++;

}

Trace table for the above loops:

i j n
0 10 0
2 8 1
4 6 2
6 4 3
8 2 4

...

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 3

Expert Solution & Answer

Chapter 6, Problem 6RE

Explanation of Solution

a.

Given statements:

//declare the variables and assign the values

int i = 0;

int j = 10;

int n = 0;

//check "i" is less than "j"

while(i < j)

{

    //increment the value

    i++;

    //decrement the value

    j--;

    //increment the value

    n++;

}

Trace table for the above loops:

i j n
0 10 0
1 9 1
2 8 2
3 7 3
4 6 4
5 5 5

Explanation:

Here, the “i” value is “0”, “j” value is “10” and “n” value is “0”.

In first iteration of “while” loop checks “i < j” which means “0 < 10”. The condition becomes true, so it increment the “i” value, i = 1, decrement the “j” value, j = 9 and also increment the “n”, n = 1...

Explanation of Solution

b.

Given statements:

//declare the variables and assign the values

int i = 0;

int j = 0;

int n = 0;

//check "i" is less than "10"

while(i < 10)

{

    //increment the value

    i++;

    //calculate the "n" value

    n = n + i + j;

    //increment the value

    j++;

}

Trace table for the above loops:

i j n
0 0 1
1 1 4
2 2 9
3 3 16
4 4 25
5 5 36
6 6 49
7 7 64
8 8 81
9 9 100

Explanation:

Here, the “i” value is 0, “j” value is 0 and “n” value is 0.

In first iteration of “while” loop checks “i < 10” which means “0 < 10”. The condition becomes true, so it increment the “i” value, i = 1, calculate “n” value which means (0 + 1 + 0 = 1) and also increment the “j”, j = 1.

In second iteration of “while” loop checks “i < 10” which means “1 < 10”. The condition becomes true, so it increment the “i” value, i = 2, calculate “n” value which means (1+ 2 + 1 = 4) and also increment the “j”, j = 2.

In third iteration of “while” loop checks “i < 10” which means “2 < 10”. The condition becomes true, so it increment the “i” value, i = 3, calculate “n” value which means (4+ 3 + 2 = 9) and also increment the “j”, j = 3.

In fourth iteration of “while” loop checks “i < 10” which means “3 < 10”...

Explanation of Solution

c.

Given statements:

//declare the variables and assign the values

int i = 10;

int j = 0;

int n = 0;

//check "i" is greater than "0"

while(i > 0)

{

    //decrement the value

    i--;

//increment the value

    j++;

    //calculate the "n" value

    n = n + i - j;

}

Trace table for the above loops:

i j n
10 0 8
9 1 14
8 2 18
7 3 20
6 4 20
5 5 18
4 6 14
3 7 8
2 8 0
1 9 -10

Explanation:

Here, the “i” value is 10, “j” value is 0 and “n” value is 0.

In first iteration of “while” loop checks “i > 0” which means “10 > 0”. The condition becomes true, so it decrement the “i” value, i = 9, increment the “j”, j = 1 and calculate “n” value which means (0 + 9 - 1 = 8).

In second iteration of “while” loop checks “i > 0” which means “9 > 0”. The condition becomes true, so it decrement the “i” value, i = 8, increment the “j”, j = 2 and calculate “n” value which means (8 + 8 - 2 = 14).

In third iteration of “while” loop checks “i > 0” which means “8 > 0”. The condition becomes true, so it decrement the “i” value, i = 7, increment the “j”, j = 3 and calculate “n” value which means (14 + 7 - 3 = 18).

In fourth iteration of “while” loop checks “i > 0” which means “7 > 0”...

Explanation of Solution

d.

Given statements:

//declare the variables and assign the values

int i = 0;

int j = 10;

int n = 0;

//check "i" is greater than "0"

while(i != j)

{

    //increment the "i" by 2

    i = i + 2;

//decrement the "j" by 2

    j = j – 2;

    //increment the value

    n++;

}

Trace table for the above loops:

i j n
0 10 0
2 8 1
4 6 2
6 4 3
8 2 4

...

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 4

Expert Solution & Answer

Chapter 6, Problem 6RE

Explanation of Solution

a.

Given statements:

//declare the variables and assign the values

int i = 0;

int j = 10;

int n = 0;

//check "i" is less than "j"

while(i < j)

{

    //increment the value

    i++;

    //decrement the value

    j--;

    //increment the value

    n++;

}

Trace table for the above loops:

i j n
0 10 0
1 9 1
2 8 2
3 7 3
4 6 4
5 5 5

Explanation:

Here, the “i” value is “0”, “j” value is “10” and “n” value is “0”.

In first iteration of “while” loop checks “i < j” which means “0 < 10”. The condition becomes true, so it increment the “i” value, i = 1, decrement the “j” value, j = 9 and also increment the “n”, n = 1...

Explanation of Solution

b.

Given statements:

//declare the variables and assign the values

int i = 0;

int j = 0;

int n = 0;

//check "i" is less than "10"

while(i < 10)

{

    //increment the value

    i++;

    //calculate the "n" value

    n = n + i + j;

    //increment the value

    j++;

}

Trace table for the above loops:

i j n
0 0 1
1 1 4
2 2 9
3 3 16
4 4 25
5 5 36
6 6 49
7 7 64
8 8 81
9 9 100

Explanation:

Here, the “i” value is 0, “j” value is 0 and “n” value is 0.

In first iteration of “while” loop checks “i < 10” which means “0 < 10”. The condition becomes true, so it increment the “i” value, i = 1, calculate “n” value which means (0 + 1 + 0 = 1) and also increment the “j”, j = 1.

In second iteration of “while” loop checks “i < 10” which means “1 < 10”. The condition becomes true, so it increment the “i” value, i = 2, calculate “n” value which means (1+ 2 + 1 = 4) and also increment the “j”, j = 2.

In third iteration of “while” loop checks “i < 10” which means “2 < 10”. The condition becomes true, so it increment the “i” value, i = 3, calculate “n” value which means (4+ 3 + 2 = 9) and also increment the “j”, j = 3.

In fourth iteration of “while” loop checks “i < 10” which means “3 < 10”...

Explanation of Solution

c.

Given statements:

//declare the variables and assign the values

int i = 10;

int j = 0;

int n = 0;

//check "i" is greater than "0"

while(i > 0)

{

    //decrement the value

    i--;

//increment the value

    j++;

    //calculate the "n" value

    n = n + i - j;

}

Trace table for the above loops:

i j n
10 0 8
9 1 14
8 2 18
7 3 20
6 4 20
5 5 18
4 6 14
3 7 8
2 8 0
1 9 -10

Explanation:

Here, the “i” value is 10, “j” value is 0 and “n” value is 0.

In first iteration of “while” loop checks “i > 0” which means “10 > 0”. The condition becomes true, so it decrement the “i” value, i = 9, increment the “j”, j = 1 and calculate “n” value which means (0 + 9 - 1 = 8).

In second iteration of “while” loop checks “i > 0” which means “9 > 0”. The condition becomes true, so it decrement the “i” value, i = 8, increment the “j”, j = 2 and calculate “n” value which means (8 + 8 - 2 = 14).

In third iteration of “while” loop checks “i > 0” which means “8 > 0”. The condition becomes true, so it decrement the “i” value, i = 7, increment the “j”, j = 3 and calculate “n” value which means (14 + 7 - 3 = 18).

In fourth iteration of “while” loop checks “i > 0” which means “7 > 0”...

Explanation of Solution

d.

Given statements:

//declare the variables and assign the values

int i = 0;

int j = 10;

int n = 0;

//check "i" is greater than "0"

while(i != j)

{

    //increment the "i" by 2

    i = i + 2;

//decrement the "j" by 2

    j = j – 2;

    //increment the value

    n++;

}

Trace table for the above loops:

i j n
0 10 0
2 8 1
4 6 2
6 4 3
8 2 4

...

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 5

Expert Solution & Answer

Answer 6

Expert Solution & Answer

Answer 7

Chapter 6, Problem 6RE

Explanation of Solution

a.

Given statements:

//declare the variables and assign the values

int i = 0;

int j = 10;

int n = 0;

//check "i" is less than "j"

while(i < j)

{

    //increment the value

    i++;

    //decrement the value

    j--;

    //increment the value

    n++;

}

Trace table for the above loops:

i j n
0 10 0
1 9 1
2 8 2
3 7 3
4 6 4
5 5 5

Explanation:

Here, the “i” value is “0”, “j” value is “10” and “n” value is “0”.

In first iteration of “while” loop checks “i < j” which means “0 < 10”. The condition becomes true, so it increment the “i” value, i = 1, decrement the “j” value, j = 9 and also increment the “n”, n = 1...

Explanation of Solution

b.

Given statements:

//declare the variables and assign the values

int i = 0;

int j = 0;

int n = 0;

//check "i" is less than "10"

while(i < 10)

{

    //increment the value

    i++;

    //calculate the "n" value

    n = n + i + j;

    //increment the value

    j++;

}

Trace table for the above loops:

i j n
0 0 1
1 1 4
2 2 9
3 3 16
4 4 25
5 5 36
6 6 49
7 7 64
8 8 81
9 9 100

Explanation:

Here, the “i” value is 0, “j” value is 0 and “n” value is 0.

In first iteration of “while” loop checks “i < 10” which means “0 < 10”. The condition becomes true, so it increment the “i” value, i = 1, calculate “n” value which means (0 + 1 + 0 = 1) and also increment the “j”, j = 1.

In second iteration of “while” loop checks “i < 10” which means “1 < 10”. The condition becomes true, so it increment the “i” value, i = 2, calculate “n” value which means (1+ 2 + 1 = 4) and also increment the “j”, j = 2.

In third iteration of “while” loop checks “i < 10” which means “2 < 10”. The condition becomes true, so it increment the “i” value, i = 3, calculate “n” value which means (4+ 3 + 2 = 9) and also increment the “j”, j = 3.

In fourth iteration of “while” loop checks “i < 10” which means “3 < 10”...

Explanation of Solution

c.

Given statements:

//declare the variables and assign the values

int i = 10;

int j = 0;

int n = 0;

//check "i" is greater than "0"

while(i > 0)

{

    //decrement the value

    i--;

//increment the value

    j++;

    //calculate the "n" value

    n = n + i - j;

}

Trace table for the above loops:

i j n
10 0 8
9 1 14
8 2 18
7 3 20
6 4 20
5 5 18
4 6 14
3 7 8
2 8 0
1 9 -10

Explanation:

Here, the “i” value is 10, “j” value is 0 and “n” value is 0.

In first iteration of “while” loop checks “i > 0” which means “10 > 0”. The condition becomes true, so it decrement the “i” value, i = 9, increment the “j”, j = 1 and calculate “n” value which means (0 + 9 - 1 = 8).

In second iteration of “while” loop checks “i > 0” which means “9 > 0”. The condition becomes true, so it decrement the “i” value, i = 8, increment the “j”, j = 2 and calculate “n” value which means (8 + 8 - 2 = 14).

In third iteration of “while” loop checks “i > 0” which means “8 > 0”. The condition becomes true, so it decrement the “i” value, i = 7, increment the “j”, j = 3 and calculate “n” value which means (14 + 7 - 3 = 18).

In fourth iteration of “while” loop checks “i > 0” which means “7 > 0”...

Explanation of Solution

d.

Given statements:

//declare the variables and assign the values

int i = 0;

int j = 10;

int n = 0;

//check "i" is greater than "0"

while(i != j)

{

    //increment the "i" by 2

    i = i + 2;

//decrement the "j" by 2

    j = j – 2;

    //increment the value

    n++;

}

Trace table for the above loops:

i j n
0 10 0
2 8 1
4 6 2
6 4 3
8 2 4

...

Answer 8

Chapter 6, Problem 6RE

Explanation of Solution

a.

Given statements:

//declare the variables and assign the values

int i = 0;

int j = 10;

int n = 0;

//check "i" is less than "j"

while(i < j)

{

    //increment the value

    i++;

    //decrement the value

    j--;

    //increment the value

    n++;

}

Trace table for the above loops:

i j n
0 10 0
1 9 1
2 8 2
3 7 3
4 6 4
5 5 5

Explanation:

Here, the “i” value is “0”, “j” value is “10” and “n” value is “0”.

In first iteration of “while” loop checks “i < j” which means “0 < 10”. The condition becomes true, so it increment the “i” value, i = 1, decrement the “j” value, j = 9 and also increment the “n”, n = 1...

Answer 9

Chapter 6, Problem 6RE

Explanation of Solution

a.

Given statements:

//declare the variables and assign the values

int i = 0;

int j = 10;

int n = 0;

//check "i" is less than "j"

while(i < j)

{

    //increment the value

    i++;

    //decrement the value

    j--;

    //increment the value

    n++;

}

Trace table for the above loops:

i j n
0 10 0
1 9 1
2 8 2
3 7 3
4 6 4
5 5 5

Explanation:

Here, the “i” value is “0”, “j” value is “10” and “n” value is “0”.

In first iteration of “while” loop checks “i < j” which means “0 < 10”. The condition becomes true, so it increment the “i” value, i = 1, decrement the “j” value, j = 9 and also increment the “n”, n = 1...

Answer 10

Explanation of Solution

b.

Given statements:

//declare the variables and assign the values

int i = 0;

int j = 0;

int n = 0;

//check "i" is less than "10"

while(i < 10)

{

    //increment the value

    i++;

    //calculate the "n" value

    n = n + i + j;

    //increment the value

    j++;

}

Trace table for the above loops:

i j n
0 0 1
1 1 4
2 2 9
3 3 16
4 4 25
5 5 36
6 6 49
7 7 64
8 8 81
9 9 100

Explanation:

Here, the “i” value is 0, “j” value is 0 and “n” value is 0.

In first iteration of “while” loop checks “i < 10” which means “0 < 10”. The condition becomes true, so it increment the “i” value, i = 1, calculate “n” value which means (0 + 1 + 0 = 1) and also increment the “j”, j = 1.

In second iteration of “while” loop checks “i < 10” which means “1 < 10”. The condition becomes true, so it increment the “i” value, i = 2, calculate “n” value which means (1+ 2 + 1 = 4) and also increment the “j”, j = 2.

In third iteration of “while” loop checks “i < 10” which means “2 < 10”. The condition becomes true, so it increment the “i” value, i = 3, calculate “n” value which means (4+ 3 + 2 = 9) and also increment the “j”, j = 3.

In fourth iteration of “while” loop checks “i < 10” which means “3 < 10”...

Answer 11

Explanation of Solution

b.

Given statements:

//declare the variables and assign the values

int i = 0;

int j = 0;

int n = 0;

//check "i" is less than "10"

while(i < 10)

{

    //increment the value

    i++;

    //calculate the "n" value

    n = n + i + j;

    //increment the value

    j++;

}

Trace table for the above loops:

i j n
0 0 1
1 1 4
2 2 9
3 3 16
4 4 25
5 5 36
6 6 49
7 7 64
8 8 81
9 9 100

Explanation:

Here, the “i” value is 0, “j” value is 0 and “n” value is 0.

In first iteration of “while” loop checks “i < 10” which means “0 < 10”. The condition becomes true, so it increment the “i” value, i = 1, calculate “n” value which means (0 + 1 + 0 = 1) and also increment the “j”, j = 1.

In second iteration of “while” loop checks “i < 10” which means “1 < 10”. The condition becomes true, so it increment the “i” value, i = 2, calculate “n” value which means (1+ 2 + 1 = 4) and also increment the “j”, j = 2.

In third iteration of “while” loop checks “i < 10” which means “2 < 10”. The condition becomes true, so it increment the “i” value, i = 3, calculate “n” value which means (4+ 3 + 2 = 9) and also increment the “j”, j = 3.

In fourth iteration of “while” loop checks “i < 10” which means “3 < 10”...

Answer 12

Explanation of Solution

c.

Given statements:

//declare the variables and assign the values

int i = 10;

int j = 0;

int n = 0;

//check "i" is greater than "0"

while(i > 0)

{

    //decrement the value

    i--;

//increment the value

    j++;

    //calculate the "n" value

    n = n + i - j;

}

Trace table for the above loops:

i j n
10 0 8
9 1 14
8 2 18
7 3 20
6 4 20
5 5 18
4 6 14
3 7 8
2 8 0
1 9 -10

Explanation:

Here, the “i” value is 10, “j” value is 0 and “n” value is 0.

In first iteration of “while” loop checks “i > 0” which means “10 > 0”. The condition becomes true, so it decrement the “i” value, i = 9, increment the “j”, j = 1 and calculate “n” value which means (0 + 9 - 1 = 8).

In second iteration of “while” loop checks “i > 0” which means “9 > 0”. The condition becomes true, so it decrement the “i” value, i = 8, increment the “j”, j = 2 and calculate “n” value which means (8 + 8 - 2 = 14).

In third iteration of “while” loop checks “i > 0” which means “8 > 0”. The condition becomes true, so it decrement the “i” value, i = 7, increment the “j”, j = 3 and calculate “n” value which means (14 + 7 - 3 = 18).

In fourth iteration of “while” loop checks “i > 0” which means “7 > 0”...

Answer 13

Explanation of Solution

c.

Given statements:

//declare the variables and assign the values

int i = 10;

int j = 0;

int n = 0;

//check "i" is greater than "0"

while(i > 0)

{

    //decrement the value

    i--;

//increment the value

    j++;

    //calculate the "n" value

    n = n + i - j;

}

Trace table for the above loops:

i j n
10 0 8
9 1 14
8 2 18
7 3 20
6 4 20
5 5 18
4 6 14
3 7 8
2 8 0
1 9 -10

Explanation:

Here, the “i” value is 10, “j” value is 0 and “n” value is 0.

In first iteration of “while” loop checks “i > 0” which means “10 > 0”. The condition becomes true, so it decrement the “i” value, i = 9, increment the “j”, j = 1 and calculate “n” value which means (0 + 9 - 1 = 8).

In second iteration of “while” loop checks “i > 0” which means “9 > 0”. The condition becomes true, so it decrement the “i” value, i = 8, increment the “j”, j = 2 and calculate “n” value which means (8 + 8 - 2 = 14).

In third iteration of “while” loop checks “i > 0” which means “8 > 0”. The condition becomes true, so it decrement the “i” value, i = 7, increment the “j”, j = 3 and calculate “n” value which means (14 + 7 - 3 = 18).

In fourth iteration of “while” loop checks “i > 0” which means “7 > 0”...

Answer 14

Explanation of Solution

d.

Given statements:

//declare the variables and assign the values

int i = 0;

int j = 10;

int n = 0;

//check "i" is greater than "0"

while(i != j)

{

    //increment the "i" by 2

    i = i + 2;

//decrement the "j" by 2

    j = j – 2;

    //increment the value

    n++;

}

Trace table for the above loops:

i j n
0 10 0
2 8 1
4 6 2
6 4 3
8 2 4

...

Answer 15

Explanation of Solution

d.

Given statements:

//declare the variables and assign the values

int i = 0;

int j = 10;

int n = 0;

//check "i" is greater than "0"

while(i != j)

{

    //increment the "i" by 2

    i = i + 2;

//decrement the "j" by 2

    j = j – 2;

    //increment the value

    n++;

}

Trace table for the above loops:

i j n
0 10 0
2 8 1
4 6 2
6 4 3
8 2 4

...

Answer 16

Expert Solution & Answer

Answer 17

Expert Solution & Answer

Answer 18

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 19

Ch. 6.1 - Prob. 1SC Ch. 6.1 - Prob. 2SC Ch. 6.1 - Prob. 3SC Ch. 6.1 - Prob. 4SC Ch. 6.1 - What does the following loop print? int n =...Ch. 6.2 - Hand-trace the following code, showing the value...Ch. 6.2 - Prob. 7SC Ch. 6.2 - Prob. 8SC Ch. 6.2 - Prob. 9SC Ch. 6.2 - Prob. 10SC

Videos

Explanation of Solution

Explanation of Solution

Explanation of Solution

Explanation of Solution

Want to see the full answer?

Chapter 6 Solutions