Chapter 6.3, Problem 6.8P

Interpretation Introduction

Interpretation:

The temperature that is needed to change the volume to $\text{12}\text{.0L}$ have to be given.

Concept Introduction:

Charles Law:

At constant pressure, the temperature and the volume of the gas are proportionally related.

  $\frac{\text{V}}{\text{T}}\text{=K}$

Where V is the volume of the gas

T is the temperature of the gas in Kelvin

K is the constant

The temperature or the volume of the gas can be calculated using the relation,

  $\frac{{\text{V}}_{\text{1}}}{{\text{T}}_{\text{1}}}\text{=}\frac{{\text{V}}_{\text{2}}}{{\text{T}}_{\text{2}}}$

Where ${\text{V}}_{\text{1}}\text{\&}{\text{T}}_{\text{1}}$ are the volume and temperature of the gas at initial state

${\text{V}}_{\text{2}}\text{\&}{\text{T}}_{\text{2}}$ are the volume and temperature of the gas at final state