Chapter 6, Problem 6.56AP

Interpretation Introduction

Interpretation:

The pressure inside the container has to be given.

Concept Introduction:

Gay Lussac’s Law:

At constant volume, the temperature and the pressure of the gas are proportionally related.

  $\frac{\text{P}}{\text{T}}\text{=K}$

Where P is the pressure of the gas.

T is the temperature of the gas in Kelvin.

K is the constant.

The temperature or the pressure of the gas can be calculated using the relation,

  $\frac{{\text{P}}_{\text{1}}}{{\text{T}}_{\text{1}}}\text{=}\frac{{\text{P}}_{\text{2}}}{{\text{T}}_{\text{2}}}$

Where ${\text{P}}_{\text{1}}\text{\&}{\text{T}}_{\text{1}}$ are the pressure and temperature of the gas at initial state.

${\text{P}}_{\text{2}}\text{\&}{\text{T}}_{\text{2}}$ are the volume and temperature of the gas at final state.