Universe
Universe
11th Edition
ISBN: 9781319039448
Author: Robert Geller, Roger Freedman, William J. Kaufmann
Publisher: W. H. Freeman
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Chapter 6, Problem 9Q
To determine

The reason behind an upside down image being formed by a simple refracting telescope, with the help of a diagram.

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The rigid bar ABC is supported by two links, AD and BE, of uniform 37.5 × 6-mm rectangular cross section and made of a mild steel that is assumed to be elastoplastic with E = 200 GPa and σy= 250 MPa. The magnitude of the force Q applied at B is gradually increased from zero to 265 kN and a = 0.640 m. 1.7 m 1 m D A B 2.64 m E Determine the value of the normal stress in each link. The value of the normal stress in link AD is The value of the normal stress in link BE is 250 MPa. MPa.
Two tempered-steel bars, each 16 in. thick, are bonded to a ½ -in. mild-steel bar. This composite bar is subjected as shown to a centric axial load of magnitude P. Both steels are elastoplastic with E= 29 × 106 psi and with yield strengths equal to 100 ksi and 50 ksi, respectively, for the tempered and mild steel. The load P is gradually increased from zero until the deformation of the bar reaches a maximum value dm = 0.04 in. and then decreased back to zero. Take L = 15 in. NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. 2.0 in. in. 3 in. 3 16 in. Determine the maximum stress in the tempered-steel bars. The maximum stress in the tempered-steel bars is ksi.
Ammonia enters the compressor of an industrial refrigeration plant at 2 bar, -10°C with a mass flow rate of 15 kg/min and is compressed to 12 bar, 140°C. Heat transfer from the compressor to its surroundings occurs at a rate of 6 kW. For steady-state operation, calculate,   (a) the power input to the compressor, in kW, Answer   (b) the entropy production rate, in kW/K, for a control volume encompassing the compressor and its immediate surroundings such that heat transfer occurs at 300 K.
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