Universe
11th Edition
ISBN: 9781319039448
Author: Robert Geller, Roger Freedman, William J. Kaufmann
Publisher: W. H. Freeman
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Chapter 6, Problem 35Q
To determine
The necessity of keeping an infrared telescope at a very low temperature.
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If the density and atomic mass of copper are respectively 8.80 x 103 kg/m³ and 63.5 kg/kmol (note that 1 kmol = 1,000 mol), and copper has one free electron per copper atom, determine the following.
(a) the drift speed of the electrons in a 10 gauge copper wire (2.588 mm in diameter) carrying a 13.5 A current
1.988-4
See if you can obtain an expression for the drift speed of electrons in a copper wire in terms of the current in the wire, the diameter of the wire, the molecular weight and mass density of copper, Avogadro's number, and the charge
on an electron. m/s
(b) the Hall voltage if a 2.68 T field is applied perpendicular to the wire
3.34e-6
x
Can you start with basic equations for the electric and magnetic forces acting on the electrons moving through the wire and obtain a relationship between the magnitude of the electric and magnetic field and the drift speed of the
electrons? How is the magnitude of the electric field related to the Hall voltage and the diameter of the wire? V
(a) At what speed (in m/s) will a proton move in a circular path of the same radius as an electron that travels at 7.85 x 100 m/s perpendicular to the Earth's magnetic field at an altitude where the field strength is 1.20 x 10-5 T?
4.27e3
m/s
(b) What would the radius (in m) of the path be if the proton had the same speed as the electron?
0.685
x m
(c) What would the radius (in m) be if the proton had the same kinetic energy as the electron?
0.0084
m
(d) What would the radius (in m) be if the proton had the same momentum as the electron?
0.0303
x m
Two charges are placed on the x axis. One of the charges (91 = +6.63 μC) is at x₁ = +3.00 cm
and the other (92 = -24.2 μC) is at x2 = +9.00 cm. Find the net electric field (magnitude and
direction given as a plus or minus sign) at (a) x = 0 cm and (b) x = +6.00 cm.
Chapter 6 Solutions
Universe
Ch. 6 - Prob. 1CCCh. 6 - Prob. 2CCCh. 6 - Prob. 3CCCh. 6 - Prob. 4CCCh. 6 - Prob. 5CCCh. 6 - Prob. 6CCCh. 6 - Prob. 7CCCh. 6 - Prob. 8CCCh. 6 - Prob. 9CCCh. 6 - Prob. 10CC
Ch. 6 - Prob. 11CCCh. 6 - Prob. 1QCh. 6 - Prob. 2QCh. 6 - Prob. 3QCh. 6 - Prob. 4QCh. 6 - Prob. 5QCh. 6 - Prob. 6QCh. 6 - Prob. 7QCh. 6 - Prob. 8QCh. 6 - Prob. 9QCh. 6 - Prob. 10QCh. 6 - Prob. 11QCh. 6 - Prob. 12QCh. 6 - Prob. 13QCh. 6 - Prob. 14QCh. 6 - Prob. 15QCh. 6 - Prob. 16QCh. 6 - Prob. 17QCh. 6 - Prob. 18QCh. 6 - Prob. 19QCh. 6 - Prob. 20QCh. 6 - Prob. 21QCh. 6 - Prob. 22QCh. 6 - Prob. 23QCh. 6 - Prob. 24QCh. 6 - Prob. 25QCh. 6 - Prob. 26QCh. 6 - Prob. 27QCh. 6 - Prob. 28QCh. 6 - Prob. 29QCh. 6 - Prob. 30QCh. 6 - Prob. 31QCh. 6 - Prob. 32QCh. 6 - Prob. 33QCh. 6 - Prob. 34QCh. 6 - Prob. 35QCh. 6 - Prob. 36QCh. 6 - Prob. 37QCh. 6 - Prob. 38QCh. 6 - Prob. 39QCh. 6 - Prob. 40QCh. 6 - Prob. 41QCh. 6 - Prob. 42QCh. 6 - Prob. 43QCh. 6 - Prob. 44QCh. 6 - Prob. 45Q
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- A cylinder with a piston contains 0.153 mol of nitrogen at a pressure of 1.83×105 Pa and a temperature of 290 K. The nitrogen may be treated as an ideal gas. The gas is first compressed isobarically to half its original volume. It then expands adiabatically back to its original volume, and finally it is heated isochorically to its original pressure. Part A Compute the temperature at the beginning of the adiabatic expansion. Express your answer in kelvins. ΕΠΙ ΑΣΦ T₁ = ? K Submit Request Answer Part B Compute the temperature at the end of the adiabatic expansion. Express your answer in kelvins. Π ΑΣΦ T₂ = Submit Request Answer Part C Compute the minimum pressure. Express your answer in pascals. ΕΠΙ ΑΣΦ P = Submit Request Answer ? ? K Paarrow_forwardLearning Goal: To understand the meaning and the basic applications of pV diagrams for an ideal gas. As you know, the parameters of an ideal gas are described by the equation pV = nRT, where p is the pressure of the gas, V is the volume of the gas, n is the number of moles, R is the universal gas constant, and T is the absolute temperature of the gas. It follows that, for a portion of an ideal gas, pV = constant. Τ One can see that, if the amount of gas remains constant, it is impossible to change just one parameter of the gas: At least one more parameter would also change. For instance, if the pressure of the gas is changed, we can be sure that either the volume or the temperature of the gas (or, maybe, both!) would also change. To explore these changes, it is often convenient to draw a graph showing one parameter as a function of the other. Although there are many choices of axes, the most common one is a plot of pressure as a function of volume: a pV diagram. In this problem, you…arrow_forwardLearning Goal: To understand the meaning and the basic applications of pV diagrams for an ideal gas. As you know, the parameters of an ideal gas are described by the equation pV = nRT, where p is the pressure of the gas, V is the volume of the gas, n is the number of moles, R is the universal gas constant, and T is the absolute temperature of the gas. It follows that, for a portion of an ideal gas, pV = constant. T One can see that, if the amount of gas remains constant, it is impossible to change just one parameter of the gas: At least one more parameter would also change. For instance, if the pressure of the gas is changed, we can be sure that either the volume or the temperature of the gas (or, maybe, both!) would also change. To explore these changes, it is often convenient to draw a graph showing one parameter as a function of the other. Although there are many choices of axes, the most common one is a plot of pressure as a function of volume: a pV diagram. In this problem, you…arrow_forward
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